A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

The Answer of A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

The Answer of A Titration of 200$\times$ 10 - 5 ,K a2 = 3$\times$ 10 - 9

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A Titration of 200 $\times$ 10^-⁵,K_a2 = 3 $\times$ 10^-⁹

Question 23

Multiple Choice

A titration of 200.0 mL of 1.00 M H₂A was done with 1.38 M NaOH.For the diprotic acid H₂A,K_a1 = 2.5 $\times$ 10^-⁵,K_a2 = 3.1 $\times$ 10^-⁹.Calculate the pH after 100.0 mL of 1.38 M NaOH have been added.

A) 9.05
B) 8.86
C) 5.14
D) 9.90
E) 4.95

A Titration of 200 ×\times× 10-5,Ka2 = 3 ×\times× 10-9

Multiple Choice

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A Titration of 200 $\times$ 10^-⁵,K_a2 = 3 $\times$ 10^-⁹

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