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Approximately How Much Water Should Be Added to 10 ×\times 10-5)?
A)28 ML
B)276 ML
C)3 L
D)28 L
E)276

Question 70

Multiple Choice

Approximately how much water should be added to 10.0 mL of 11.1 M HCl so that it has the same pH as 0.90 M acetic acid (Ka = 1.8 ×\times 10-5) ?


A) 28 mL
B) 276 mL
C) 3 L
D) 28 L
E) 276 L

Correct Answer:

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