The Reaction: 2A + B $\to$ C
Has the Following Proposed Mechanism:
Step 1: a

Multiple Choice

The reaction: 2A + B $\to$ C
Has the following proposed mechanism:
Step 1: A + B D (fast equilibrium)
Step 2: D + B $\to$ E
Step 3: E + A $\to$ C + B
If step 2 is the rate-determining step,then the rate of formation of C should equal:

A) k[A]
B) k[A]²[B]
C) k[A]²[B]²
D) k[A][B]
E) k[A][B]²