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The First Three Derivatives Of f(x)=(x+4)3/2f ( x ) = ( x + 4 ) ^ { 3 / 2 }

Question 167

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The first three derivatives of f(x)=(x+4)3/2f ( x ) = ( x + 4 ) ^ { 3 / 2 } are f(x)=3(x+4)1/22f ^ { \prime } ( x ) = \frac { 3 ( x + 4 ) ^ { 1 / 2 } } { 2 } , f(x)=34(x+4)1/2f ^ { \prime \prime } ( x ) = \frac { 3 } { 4 ( x + 4 ) ^ { 1 / 2 } } and f(x)=38(x+4)3/2f ^ { \prime \prime } ( x ) = \frac { - 3 } { 8 ( x + 4 ) ^ { 3 / 2 } } .(a) Give the first four terms of the Taylor series associated with f at a=3a = - 3 .(b) Give the second-order Taylor polynomial, T2(x)T _ { 2 } ( x ) , associated with f at a=0a = 0 .(c) Suppose that x0x \geq 0 and that T2(x)T _ { 2 } ( x ) from part (b) is used to approximate f(x)f ( x ) . Prove that the error in this approximation does not exceed x3128\frac { x ^ { 3 } } { 128 } .

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