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Find dydx\frac { d y } { d x } (A) y=(x+1x3)4y = \left( \frac { x + 1 } { x - 3 } \right) ^ { 4 }

Question 226

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Find dydx\frac { d y } { d x } .(a) y=(x+1x3)4y = \left( \frac { x + 1 } { x - 3 } \right) ^ { 4 } (b) y=e2x+e99y = e ^ { 2 x } + e ^ { 99 } (c) y=xex2+7y = x e ^ { x ^ { 2 } + 7 } (d) y=tan(sinx2)y = \tan \left( \sin x ^ { 2 } \right)

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