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The Angular Displacement θ\theta Of a Simple Pendulum Is Given By θ=θ0sin(ωt+ϕ)\theta = \theta _ { 0 } \sin ( \omega t + \phi )

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The angular displacement θ\theta of a simple pendulum is given by θ=θ0sin(ωt+ϕ)\theta = \theta _ { 0 } \sin ( \omega t + \phi ) where θ0\theta _ { 0 } is the angular amplitude, ω\omega the angular frequency and θ\theta a phase constant depending on initial conditions. If we are given that ω\omega = 10 and ϕ=π2\phi = \frac { \pi } { 2 }
, find the angular velocity dθdt\frac { d \theta } { d t } when θ=θ02\theta = \frac { \theta _ { 0 } } { 2 } .

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