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Given f(x)=x−4x−1f ( x ) = \frac { x - 4 } { x - 1 }

Question 218

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Given f(x)=x−4x−1f ( x ) = \frac { x - 4 } { x - 1 } , find an equation of the line(s) tangent to the graph of y=f(x)y = f ( x ) and parallel to y−3x+7=0y - 3 x + 7 = 0 .

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