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Show That the Curve with Vector Equation R (T) = cos2t\cos ^ { 2 } t

Question 67

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Show that the curve with vector equation r (t) = 2 cos2t\cos ^ { 2 } t i + sin (2t) j + 2 sin t k is the curve of intersection of the surfaces (x1)2+y2=1( x - 1 ) ^ { 2 } + y ^ { 2 } = 1 and x2+y2+z2=4x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 4 Use this fact to sketch the curve.

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