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Calculate the Equilibrium Concentration of Zn2(aq) in a Solution

Question 120

Multiple Choice

Calculate the equilibrium concentration of Zn2(aq) in a solution that is 0.0125 M Zn(NO3) 2 and 0.600 M NH3.
Given: Zn2(aq) 4NH3(aq) Calculate the equilibrium concentration of Zn<sup>2</sup><font face= symbol ><sup></sup></font>(aq) in a solution that is 0.0125 M Zn(NO<sub>3</sub>) <sub>2</sub> and 0.600 M NH<sub>3</sub>. Given: Zn<sup>2</sup><font face= symbol ><sup></sup></font>(aq) <font face= symbol ></font> 4NH<sub>3</sub>(aq) Zn(NH<sub>3</sub>) <sub>4</sub><sup>2</sup><font face= symbol ><sup></sup></font>(aq) K<sub>f</sub> <font face= symbol ></font> 2.9 <font face= symbol ></font> 10<sup>9</sup>. A) 7.8 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>12</sup> M B) 4.7 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>11 </sup>M C) 1.5 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>8</sup> M D) 2.5 <font face= symbol ></font> 10<font face= symbol ><sup></sup></font><sup>9</sup> M E) 2.9 <font face= symbol ></font> 10<sup>9</sup> M Zn(NH3) 42(aq) Kf 2.9 109.


A) 7.8 1012 M
B) 4.7 1011 M
C) 1.5 108 M
D) 2.5 109 M
E) 2.9 109 M

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