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Treatment of Tert-Butyl Alcohol with Hydrogen Chloride Yields a Mixture

Question 42

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Treatment of tert-butyl alcohol with hydrogen chloride yields a mixture of tert-butyl chloride and 2-methylpropene. (CH3)3COHHCl(CH3)3CCl+(CH3)2C=CH2\left( \mathrm { CH } _ { 3 } \right) _ { 3 } \mathrm { COH } \stackrel { \mathrm { HCl } } { \longrightarrow } \left( \mathrm { CH } _ { 3 } \right) _ { 3 } \mathrm { CCl } + \left( \mathrm { CH } _ { 3 } \right) _ { 2 } \mathrm { C } = \mathrm { CH } _ { 2 } a) After chromatographic separation, how would you use 1H^1H NMR to help you decide which was which?

b) How would the 13C{}^{13}C NMR for the two compounds differ?

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