Dinitrogen Tetroxide (N₂O₄) Decomposes to Nitrogen Dioxide (NO₂) $\Delta$ H° = 5802 KJ/mol And Decomposes

Multiple Choice

Dinitrogen tetroxide (N₂O₄) decomposes to nitrogen dioxide (NO₂) . If $\Delta$ H° = 58.02 kJ/mol and $\Delta$ S° = 176.1 J/mol · K, at what temperature are reactants and products in their standard states at equilibrium?

A) +56.5°C
B) +329.5°C
C) -272.7°C
D) +25.0°C
E) +98.3°C