Multiple Choice
When [Ni(NH3) 4]2+ is treated with concentrated HCl, two compounds having the same formula, Ni(NH3) 4Cl2, designated I and II, are formed. Compound I can be converted to compound II by boiling it in dilute HCl. A solution of I reacts with oxalic acid, H2C2O4, to form Ni(NH3) 4(C2O4) . Compound II does not react with oxalic acid. Compound II is:
A) the cis isomer
B) tetrahedral in shape
C) the trans isomer
D) the same as compound I
E) octahedral in shape
Correct Answer:
Verified
Correct Answer:
Verified
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