Multiple Choice
A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 10-3 M CuNO3. Cu(I) forms complex ions with cyanide as follows: ![A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 <font face= symbol ></font> 10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu(CN) <sub>2</sub><sup>-</sup>] A) 1.0 <font face= symbol ></font> 10<sup>-</sup><sup>3</sup> M B) 4.0 <font face= symbol ></font><font face= symbol ></font>10<sup>-</sup><sup>12</sup> M C) 2.0 <font face= symbol ></font> 10<sup>-</sup><sup>7</sup> M D) 2.0 <font face= symbol ></font> 10<sup>-</sup><sup>3</sup> M E) none of these](https://d2lvgg3v3hfg70.cloudfront.net/TB6420/11eaaf8d_c168_297e_892c_296022b8a32c_TB6420_00_TB6420_00_TB6420_00.jpg)
Calculate the following concentrations at equilibrium:
-[Cu(CN) 2-]
A) 1.0 10-3 M
B) 4.0 10-12 M
C) 2.0 10-7 M
D) 2.0 10-3 M
E) none of these
Correct Answer:
Verified
Correct Answer:
Verified
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