Short Answer
The structure for CaF2 can be described as a face-centered array of Ca2+ ions with F- ions in the tetrahedral holes. The edge length of the unit cell is 5.45 *10-8 cm.
A) What fraction of the tetrahedral holes must be occupied by F- ions?
B) Calculate the density of CaF2.
C) If the ionic radius of F- is 1.36 * 10-8 cm, estimate the ionic radius of Ca2+. Tetrahedral holes are located along the body diagonals of each unit cell so that 1/4 (body diagonal) = rCa2+ + rF-.
Correct Answer:
Verified
Correct Answer:
Verified
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