Essay
A 50.0-mL solution of the acid H3A (Ka1 = 1.0 × 10-6 , Ka2 = 1.0 × 10-9, and Ka3 = 1.0 × 10-12.) is titrated with 0.050 M KOH. The second equivalence point is reached at 25.0 mL of base. Calculate the original concentration of H3A and the volume of 0.050 M KOH needed to reach a pH of 6.70.
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[H3A] = 0.0...View Answer
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