Multiple Choice
The potential energy of a 0.20-kg particle moving along the x axis is given by U(x) =(8.0J/m2) x2 + (2.0J/m4) x4.
When the particle is at x = 1.0 m its magnituede of its acceleration is:
A) 0
B) -8 m/s2
C) 8 m/s2
D) -40 m/s2
E) 40 m/s2
Correct Answer:
Verified
Correct Answer:
Verified
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