Multiple Choice
A certain capacitor has a capacitance of 5.0 F.After it is charged to 5 C and isolated, the plates are brought closer together so its capacitance becomes 10 F.The work done by the agent is about:
A) "0 J"
B) "1.25 * 10-6 J"
C) "-1.25 * 10-6 J"
D) "8.3 * 10-7 J"
E) "-8.3 *10-7 J"
Correct Answer:

Verified
Correct Answer:
Verified
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