Multiple Choice
What is the mass of potassium iodide (166.00 g/mol) that yields 0.500 g of lead(II) iodide (461.0 g/mol) precipitate? __Pb(NO₃) 2(aq) + __KI(s) → __PbI₂(s) + __KNO₃(aq)
A) 0.0900 g
B) 0.180 g
C) 0.360 g
D) 0.694 g
E) 2.78 g
Correct Answer:
Verified
Correct Answer:
Verified
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