Multiple Choice
If 1.020 g of KHC8H₄O₄ (204.23 g/mol) is completely neutralized with 0.200 M KOH,what volume of potassium hydroxide is required? KHC8H₄O₄(aq) + KOH(aq) → k₂C8H₄O₄(aq) + 2 H₂O(l)
A) 12.5 mL
B) 20.0 mL
C) 25.0 mL
D) 40.0 mL
E) 50.0 mL
Correct Answer:

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Correct Answer:
Verified
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