Completely Describe the Sampling Distribution of the Sample Proportion for Samples

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The Answer is Since np = 200 and n(1 - p) = 300 are both greater than 5, the distribution of the sample proportion

Since np = 200 and n(1 - p) = 300 are both greater than 5, the distribution of the sample proportion will be approximately normal with a mean = 0.4 and a standard deviation (or standard error) = 0.0219.

will be approximately normal with a mean Since np = 200 and n(1 - p) = 300 are both greater than 5, the distribution of the sample proportion will be approximately normal with a mean = 0.4 and a standard deviation (or standard error) = 0.0219.

= 0.4 and a standard deviation (or standard error) Since np = 200 and n(1 - p) = 300 are both greater than 5, the distribution of the sample proportion will be approximately normal with a mean = 0.4 and a standard deviation (or standard error) = 0.0219.

= 0.0219.

Completely Describe the Sampling Distribution of the Sample Proportion for Samples

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Completely Describe the Sampling Distribution of the Sample Proportion for Samples

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Correct Answer:VerifiedShow Answer

Correct Answer:
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