Short Answer
Given a DG° of 0.8 kJ/mol at 25°C for the equilibrium shown below, calculate the percentage of the axial conformer at 25°C. [R = 8.314 J/K∙ mol]
Correct Answer:

Verified
Correct Answer:
Verified
Related Questions
Q5: What is meant by the mechanism of
Q19: What is the CCC bond angle in
Q54: Which of the following is a propagation
Q57: When light is shined on a mixture
Q77: Which compound has the smaller bond dissociation
Q83: Given a K of 2.2 at 25°C,
Q84: For the reaction A + B →
Q89: List the following radicals in order of
Q92: Use the Hammond Postulate to explain why
Q115: Energy is _ when bonds are formed