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Which of the Presented Mechanisms Would Be the Most Energetically

Question 117

Multiple Choice

Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)
H2 + Cl2
Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)  H<sub>2 </sub> + Cl<sub>2 </sub> <sub> </sub>   2 HCl A)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl H∙ + Cl∙ → HCl B)  Cl<sub>2 </sub> <sub> </sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl<sub>2 </sub>→ HCl + Cl∙ C)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl Cl∙ + H<sub>2 </sub>→ HCl + H∙ D)  Cl<sub>2</sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl∙ → HCl 2 HCl


A) H2
Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)  H<sub>2 </sub> + Cl<sub>2 </sub> <sub> </sub>   2 HCl A)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl H∙ + Cl∙ → HCl B)  Cl<sub>2 </sub> <sub> </sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl<sub>2 </sub>→ HCl + Cl∙ C)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl Cl∙ + H<sub>2 </sub>→ HCl + H∙ D)  Cl<sub>2</sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl∙ → HCl H∙ + H∙
H∙ + Cl2 → Cl∙ + HCl
H∙ + Cl∙ → HCl
B) Cl2
Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)  H<sub>2 </sub> + Cl<sub>2 </sub> <sub> </sub>   2 HCl A)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl H∙ + Cl∙ → HCl B)  Cl<sub>2 </sub> <sub> </sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl<sub>2 </sub>→ HCl + Cl∙ C)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl Cl∙ + H<sub>2 </sub>→ HCl + H∙ D)  Cl<sub>2</sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl∙ → HCl Cl∙ + Cl∙
Cl∙ + H2 → H∙ + HCl
H∙ + Cl2 → HCl + Cl∙
C) H2
Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)  H<sub>2 </sub> + Cl<sub>2 </sub> <sub> </sub>   2 HCl A)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl H∙ + Cl∙ → HCl B)  Cl<sub>2 </sub> <sub> </sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl<sub>2 </sub>→ HCl + Cl∙ C)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl Cl∙ + H<sub>2 </sub>→ HCl + H∙ D)  Cl<sub>2</sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl∙ → HCl H∙ + H∙
H∙ + Cl2 → Cl∙ + HCl
Cl∙ + H2 → HCl + H∙
D) Cl2 Which of the presented mechanisms would be the most energetically favorable and thus the most likely mechanism to actually occur for the following free radical chain reaction? (bond dissociation energies -- H-H = 104 kcal/mol; Cl-Cl = 58 kcal/mol; H-Cl = 103 kcal/mol)  H<sub>2 </sub> + Cl<sub>2 </sub> <sub> </sub>   2 HCl A)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl H∙ + Cl∙ → HCl B)  Cl<sub>2 </sub> <sub> </sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl<sub>2 </sub>→ HCl + Cl∙ C)  H<sub>2 </sub> <sub> </sub>   H∙ + H∙ H∙ + Cl<sub>2 </sub>→ Cl∙ + HCl Cl∙ + H<sub>2 </sub>→ HCl + H∙ D)  Cl<sub>2</sub>   Cl∙ + Cl∙ Cl∙ + H<sub>2 </sub>→ H∙ + HCl H∙ + Cl∙ → HCl Cl∙ + Cl∙
Cl∙ + H2 → H∙ + HCl
H∙ + Cl∙ → HCl

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