Given the Following Network with Activities and Times Estimated in Days

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\begin{array}{l} ext { a. and } b ext {. }\\begin{array} { l c l } ext { Activity } & ext { Expected Time } & ext { Variance } \\hline ext { A } & 4.67 & 0.44 \ ext { B } & 3.33 & 1.00 \ ext { C } & 7.33 & 0.44 \ ext { D } & 11.17 & 2.25 \ ext { E } & 4.00 & 0.11 \ ext { F } & 9.33 & 0.44 \ ext { G } & 6.00 & 0.44 \ ext { H } & 5.83 & 0.69 \ ext { I } & 7.50 & 1.36 \ ext { J } & 13.00 & 0.11 \ ext { K } & 2.83 & 0.25\end{array}\end{array}

$\begin{array}{l} ext { a. and } b ext {. }\ \begin{array} { l c l } ext { Activity } & ext { Expected Time } & ext { Variance } \ \hline ext { A } & 4.67 & 0.44 \ ext { B } & 3.33 & 1.00 \ ext { C } & 7.33 & 0.44 \ ext { D } & 11.17 & 2.25 \ ext { E } & 4.00 & 0.11 \ ext { F } & 9.33 & 0.44 \ ext { G } & 6.00 & 0.44 \ ext { H } & 5.83 & 0.69 \ ext { I } & 7.50 & 1.36 \ ext { J } & 13.00 & 0.11 \ ext { K } & 2.83 & 0.25 \end{array} \end{array} CRITICAL PATH: C-H-J-K EXPECTED PROJECT COM PLETION TIME = 29 VARIANCE OF PROJECT COMPLETION TIME = 1.5 The probability that the project will take more than 28 days is P ( z > ( 28 - 29 ) / 1.22 ) = P ( z > - .82 ) = .7939$
CRITICAL PATH: C-H-J-K
EXPECTED PROJECT COM PLETION TIME

= 29

VARIANCE OF PROJECT COMPLETION TIME

= 1.5

The probability that the project will take more than 28 days is

P ( z > ( 28 - 29 ) / 1.22 ) = P ( z > - .82 ) = .7939

Given the Following Network with Activities and Times Estimated in Days

Essay

Correct Answer:
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Given the Following Network with Activities and Times Estimated in Days

Essay

Correct Answer:VerifiedShow Answer

Correct Answer:
Verified