Deck 3: Chemical Foundations Ii: Concentration and Kinetics
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Deck 3: Chemical Foundations Ii: Concentration and Kinetics
1
Which of the following is not an assumption when calculating volumes of distribution using the Fick dilution principle?
A) The concentration of the solute is homogeneous am ong all its volume of distribution.
B) The am ou nt o f s olu te is known at the time of sampling of the volume in which it is distributed.
C) The volume in which the solute is distributed is well mixed.
D) The solute's concentration can be determined.
E) The solute is sm all.
A) The concentration of the solute is homogeneous am ong all its volume of distribution.
B) The am ou nt o f s olu te is known at the time of sampling of the volume in which it is distributed.
C) The volume in which the solute is distributed is well mixed.
D) The solute's concentration can be determined.
E) The solute is sm all.
E
2
For the reaction A + B ·
C, the reve rse rate c ons tant h as th e un its
A) s-1
B) M s-1
C) M -1 s-1
D) M s
E) M -1 s
C, the reve rse rate c ons tant h as th e un its
A) s-1
B) M s-1
C) M -1 s-1
D) M s
E) M -1 s
A
3
You have a 0.1 M solution of ATP and take 6.25 mL of it to add to a 25 mL volumetric flask, along with some other solutions, which is then brought up to volume to make a stock solution. You then add 1 mL of that stock solution to a reaction bath that has a total final volume, including the 1 mL of stock solution, of 5 mL. W hat is the ATP concentration in the final reaction bath?
A) 0.025 M
B) 0.05 M
C) 0.02 M
D) 0.005 M
E) Cannot be calculated from the information given.
A) 0.025 M
B) 0.05 M
C) 0.02 M
D) 0.005 M
E) Cannot be calculated from the information given.
D
4
Suppose that the glucose concentration in normal plasma is 5.0 mM. If the gram-m olecular weight is 180 g mol-1 and the normal plasma v olu m e is 4 L , wh at is the m as s o f all o f th e g luc os e th at is contained in all of the plasma?
A) 20 g
B) 20 mol
C) 20 mm ol
D) 3.6 g
E) 0.36 g
A) 20 g
B) 20 mol
C) 20 mm ol
D) 3.6 g
E) 0.36 g
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5
The Michaelis-Menten equation is written as
A) V = Vmax S / (KM S + 1)
B) V = Vmax S / KM
C) V = Vmax S
D) V = Vmax S / (KM + S)
E) None of the above
A) V = Vmax S / (KM S + 1)
B) V = Vmax S / KM
C) V = Vmax S
D) V = Vmax S / (KM + S)
E) None of the above
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6
The glucose concentration in plasma is typically 100 mg% , meaning 100 mg in 100 mL of plasma. The gram m olecular weight of glucose is 180 g mol-1. W hat is the molar concentration of this plasma glucose?
A) 50 mM
B) 56 mM
C) 5.0 mM
D) 5 .6 mM
E) 1.8 mM
A) 50 mM
B) 56 mM
C) 5.0 mM
D) 5 .6 mM
E) 1.8 mM
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7
The gram m olecular weight of urea, CO (NH2 )2 is about
A) 48 g mol-1
B) 48 daltons
C) 48 g
D) 60 g mol-1
E) 180 g mol-1
A) 48 g mol-1
B) 48 daltons
C) 48 g
D) 60 g mol-1
E) 180 g mol-1
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8
For an e xpe rim ent, we weighed out 18 g of NaCl and dissolved it into a final volume of 500 m L with water. The atomic weight of Na is 22.99 and Cl is 35.45. W hat is the molar concentration of NaCl in the final solution?
A) 1.57 M
B) 1.02 M
C) 0.62 M
D) 0.15 M
E) 0.31 M
A) 1.57 M
B) 1.02 M
C) 0.62 M
D) 0.15 M
E) 0.31 M
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9
You took 0.5 m L of c onc entra tion H Cl, at 1 1.5 M, and added it to a 100mL volumetric flask, and then ad de d w ate r to the m ar k. Th e c on ce ntr atio n o f H C l in th e fin al s olu tion is
A) 0.5 M
B) 0.0575 M
C) 0.115 M
D) 1.15 M
E) 0.575 M
A) 0.5 M
B) 0.0575 M
C) 0.115 M
D) 1.15 M
E) 0.575 M
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10
Enzymes catalyze reactions by
A) spe edin g up bindin g of s ubs trate
B) Speeding up dissociation of product
C) Lowering the activation energy
D) Increasing the energy available for the reaction
E) Changing the equilibrium constant for the reaction
A) spe edin g up bindin g of s ubs trate
B) Speeding up dissociation of product
C) Lowering the activation energy
D) Increasing the energy available for the reaction
E) Changing the equilibrium constant for the reaction
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11
If th e d ou ble -re cip ro ca l plo t of an en zym e is line ar , the inte rc ep t on the ab sc iss a (v er tica l ax is) is
A) Vmax
B) KM
C) - 1 / K M
D) 1 / V max
E) KM / Vmax
A) Vmax
B) KM
C) - 1 / K M
D) 1 / V max
E) KM / Vmax
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12
You dissolved 100 g of a material with a molecule weight of 5.5 kDa in 1 L of so lution. Its molar co nc en tra tion is
A) 18 nM
B) 18 µ M
C) 1.8 mM
D) 18 mM
E) 18 M
A) 18 nM
B) 18 µ M
C) 1.8 mM
D) 18 mM
E) 18 M
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