Deck 14: Entropy and Gibbs Energy

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Question
The following substances are ordered with increasing entropy: neon gas < liquid water < a gold bar.
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Question
The entropy change for the following reaction will be negative:
C11H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
Question
The entropy change for the following reaction will be positive:
N2 (g) + 3 H2 (g) → 2 NH3 (g)
Question
Entropy is identified with the amount of ________ in the system.
Question
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of ethanol at its boiling point (T<sub>b</sub> =78.45 °C) vaporizes (in the process the temperature does not change,   for ethanol is + 43.5 kJ mol<sup>-1</sup>).</strong> A) + 124. B) - 124. C) + 554. D) + 0.12. <div style=padding-top: 35px> , J K-1 mol-1) when 1.00 mol of ethanol at its boiling point (Tb =78.45 °C) vaporizes (in the process the temperature does not change, <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of ethanol at its boiling point (T<sub>b</sub> =78.45 °C) vaporizes (in the process the temperature does not change,   for ethanol is + 43.5 kJ mol<sup>-1</sup>).</strong> A) + 124. B) - 124. C) + 554. D) + 0.12. <div style=padding-top: 35px> for ethanol is + 43.5 kJ mol-1).

A) + 124.
B) - 124.
C) + 554.
D) + 0.12.
Question
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of mercury at its boiling point (T<sub>b</sub> = 356.55 °C) vaporizes (in the process the temperature does not change,   for mercury is + 59.3 kJ mol<sup>-1</sup>).</strong> A) - 94. B) + 94. C) + 166. D) + 0.09. <div style=padding-top: 35px> , J K-1 mol-1) when 1.00 mol of mercury at its boiling point (Tb = 356.55 °C) vaporizes (in the process the temperature does not change, <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of mercury at its boiling point (T<sub>b</sub> = 356.55 °C) vaporizes (in the process the temperature does not change,   for mercury is + 59.3 kJ mol<sup>-1</sup>).</strong> A) - 94. B) + 94. C) + 166. D) + 0.09. <div style=padding-top: 35px> for mercury is + 59.3 kJ mol-1).

A) - 94.
B) + 94.
C) + 166.
D) + 0.09.
Question
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of methane at its melting point (T<sub>m</sub> = - 182.05 °C) freezes (in the process the temperature does not change and   for methane is + 0.94 kJ mol<sup>-1</sup>).</strong> A) - 10.3. B) - 0.01. C) + 10.3. D) - 5.2. <div style=padding-top: 35px> , J K-1 mol-1) when 1.00 mol of methane at its melting point (Tm = - 182.05 °C) freezes (in the process the temperature does not change and <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of methane at its melting point (T<sub>m</sub> = - 182.05 °C) freezes (in the process the temperature does not change and   for methane is + 0.94 kJ mol<sup>-1</sup>).</strong> A) - 10.3. B) - 0.01. C) + 10.3. D) - 5.2. <div style=padding-top: 35px> for methane is + 0.94 kJ mol-1).

A) - 10.3.
B) - 0.01.
C) + 10.3.
D) - 5.2.
Question
For water For water   = + 109 J K<sup>-1</sup> mol<sup>-1</sup> whilst   = + 22 J K<sup>-1</sup> mol<sup>-1</sup>. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.<div style=padding-top: 35px> = + 109 J K-1 mol-1 whilst For water   = + 109 J K<sup>-1</sup> mol<sup>-1</sup> whilst   = + 22 J K<sup>-1</sup> mol<sup>-1</sup>. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.<div style=padding-top: 35px> = + 22 J K-1 mol-1. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.
Question
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) > 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
Question
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) < 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
Question
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) = 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
Question
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of methanol is heated at constant pressure from 5 °C to 35 °C, the molar heat capacity, Cp, of methanol is 81.6 J K-1 mol-1, assume that the molar heat capacity, Cp is constant over this temperature range.

A) + 8.36.
B) - 8.36.
C) - 158.79.
D) + 158.79.
Question
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of ethanol is cooled at constant pressure from 25 °C to 10 °C, the molar heat capacity, Cp, of ethanol is 111.5 J K-1 mol-1 and assume that Cp is constant over this temperature range.

A) + 5.8.
B) - 5.8.
C) - 102.2.
D) + 102.2.
Question
When 1 mol of trichloromethane is heated from 5 °C to 20 °C at constant pressure, the change of entropy is + 6.00 J K-1 mol-1. When the solvent is heated further from 20 °C to 35 °C, the change in entropy will also be + 6.00 J K-1 mol-1.
Question
When 1 mol of water is heated from 10 °C to 25 °C at constant pressure, the change in entropy is + 3.89 J K-1 mol-1. When 1 mol of methanol is heated from 10 °C to 25 °C at constant pressure, the change in entropy will be smaller.
Question
At zero kelvin the entropy of a perfect crystal is ____.
Question
Calculate the standard entropy <strong>Calculate the standard entropy   of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, C<sub>p</sub>, of water is 75.3 J K<sup>-1</sup> mol<sup>-1</sup> and   is 69.9 J K<sup>-1</sup> mol<sup>-1</sup>.</strong> A) 69.9. B) - 133.5. C) 68.7. D) 71.1. <div style=padding-top: 35px> of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, Cp, of water is 75.3 J K-1 mol-1 and <strong>Calculate the standard entropy   of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, C<sub>p</sub>, of water is 75.3 J K<sup>-1</sup> mol<sup>-1</sup> and   is 69.9 J K<sup>-1</sup> mol<sup>-1</sup>.</strong> A) 69.9. B) - 133.5. C) 68.7. D) 71.1. <div style=padding-top: 35px> is 69.9 J K-1 mol-1.

A) 69.9.
B) - 133.5.
C) 68.7.
D) 71.1.
Question
The standard entropy The standard entropy   of ethanol, at 1 bar, is 159.9 J K<sup>-1</sup> mol<sup>-1</sup>. At 315 K, its standard entropy will be larger.<div style=padding-top: 35px> of ethanol, at 1 bar, is 159.9 J K-1 mol-1. At 315 K, its standard entropy will be larger.
Question
The standard entropy change for the following reaction will be large and positive. CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g)
Question
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction <strong>Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction   ( in J K<sup>-1</sup> mol<sup>-1</sup>) for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) + 243.0. B) - 243.0. C) - 107.8. D) + 107.8. <div style=padding-top: 35px> ( in J K-1 mol-1) for the following reaction: CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

A) + 243.0.
B) - 243.0.
C) - 107.8.
D) + 107.8.
Question
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction <strong>Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) for the following reaction: NH<sub>3</sub> (g) + HNO<sub>3</sub> (l) → NH<sub>4</sub>NO<sub>3</sub> (s)</strong> A) - 197. B) + 197. C) -151.1. D) +151.1. <div style=padding-top: 35px> (in J K-1 mol-1) for the following reaction:
NH3 (g) + HNO3 (l) → NH4NO3 (s)

A) - 197.
B) + 197.
C) -151.1.
D) +151.1.
Question
The standard entropy change, <strong>The standard entropy change,   for the following reaction is: -198.7 J K<sup>-1</sup> mol<sup>-1</sup>. N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 550 K.</strong> A) - 226. B) - 171. C) + 226. D) + 171. <div style=padding-top: 35px> for the following reaction is: -198.7 J K-1 mol-1.
N2 (g) + 3 H2 (g) → 2 NH3 (g) Calculate the standard entropy change of reaction <strong>The standard entropy change,   for the following reaction is: -198.7 J K<sup>-1</sup> mol<sup>-1</sup>. N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 550 K.</strong> A) - 226. B) - 171. C) + 226. D) + 171. <div style=padding-top: 35px> (in J K-1 mol-1) at 550 K.

A) - 226.
B) - 171.
C) + 226.
D) + 171.
Question
The standard entropy change, <strong>The standard entropy change,   for the following reaction is: + 511.9 J K<sup>-1</sup> mol<sup>-1</sup>. C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 390 116.85 °C.</strong> A) + 511.9. B) + 48.3. C) + 379. D) + 645. <div style=padding-top: 35px> for the following reaction is: + 511.9 J K-1 mol-1.
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) Calculate the standard entropy change of reaction <strong>The standard entropy change,   for the following reaction is: + 511.9 J K<sup>-1</sup> mol<sup>-1</sup>. C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 390 116.85 °C.</strong> A) + 511.9. B) + 48.3. C) + 379. D) + 645. <div style=padding-top: 35px> (in J K-1 mol-1) at 390 116.85 °C.

A) + 511.9.
B) + 48.3.
C) + 379.
D) + 645.
Question
The standard entropy change, The standard entropy change,   is: - 198.7 J K<sup>-1</sup> mol<sup>-1</sup>, for the following reaction: N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) This violates the Second Law of thermodynamics.<div style=padding-top: 35px> is: - 198.7 J K-1 mol-1, for the following reaction: N2 (g) + 3 H2 (g) → 2 NH3 (g) This violates the Second Law of thermodynamics.
Question
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG < 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
Question
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG > 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
Question
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG = 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
Question
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS < 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
Question
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS > 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
Question
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS > 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
Question
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS < 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
Question
An endothermic reaction has <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. <div style=padding-top: 35px> , <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. <div style=padding-top: 35px> and <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. <div style=padding-top: 35px> . Find the temperature, T(K), at which the reaction becomes spontaneous.

A) 298.
B) 783.
C) 0.78.
D) 1.28.
Question
Using <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. <div style=padding-top: 35px> and <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. <div style=padding-top: 35px> data given below:
<strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. <div style=padding-top: 35px>
Calculate the standard Gibbs energy change, <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. <div style=padding-top: 35px> (kJ mol-1), for the following reaction:
2 NH3 (g) → N2 (g) + 3 H2 (g)

A) + 151.
B) - 151.
C) + 33.
D) - 59.
Question
Using <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. <div style=padding-top: 35px> and <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. <div style=padding-top: 35px> data given below:
<strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. <div style=padding-top: 35px> Calculate the standard Gibbs energy change, <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. <div style=padding-top: 35px> (kJ mol-1), for the following reaction:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

A) - 818.
B) + 71.5.
C) + 963.
D) - 963.
Question
Using <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8. <div style=padding-top: 35px> data given below:
<strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8. <div style=padding-top: 35px>
Calculate the standard Gibbs energy change, <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8. <div style=padding-top: 35px> (kJ mol-1), for the following reaction:
CO (g) + 2 H2 (g) → CH3OH (g)

A) - 299.2.
B) + 299.2.
C) + 24.8.
D) - 24.8.
Question
Using <strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. <div style=padding-top: 35px> data given below:
<strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. <div style=padding-top: 35px> calculate the standard Gibbs energy change, <strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. <div style=padding-top: 35px> (kJ mol-1), for the following reaction:
CO2 (g) + CH4 (g) → CH3CO2H (l)

A) - 835.1
B) - 55.3.
C) + 835.1.
D) + 55.3.
Question
Using <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5. <div style=padding-top: 35px> data given below:
<strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5. <div style=padding-top: 35px>
Calculate the standard Gibbs energy change, <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5. <div style=padding-top: 35px> (kJ mol-1), for the following reaction:
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)

A) + 911.5.
B) - 5797.9.
C) + 5797.9.
D) - 911.5.
Question
An endothermic reaction with a positive entropy change will become spontaneous on cooling.
Question
Using the data given below estimate the value of the Gibbs energy change of reaction (kJ mol-1) at 310 K, for the following reaction:
CH3CH2OH (l) + O2 (g) → CH3CO2H (l) + H2O (l)
<strong>Using the data given below estimate the value of the Gibbs energy change of reaction (kJ mol<sup>-1</sup>) at 310 K, for the following reaction: CH<sub>3</sub>CH<sub>2</sub>OH (l) + O<sub>2</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l) + H<sub>2</sub>O (l)  </strong> A) - 450.2 B) - 451.8. C) -41.7. D) -533.8. <div style=padding-top: 35px>

A) - 450.2
B) - 451.8.
C) -41.7.
D) -533.8.
Question
Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction:
N2 (g) + 2 O2 (g) → 2 NO2 (g)
<strong>Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction: N<sub>2</sub> (g) + 2 O<sub>2 </sub>(g) → 2 NO<sub>2</sub> (g)  </strong> A) + 26.1. B) + 105.9. C) + 102.6. D) + 40. <div style=padding-top: 35px>

A) + 26.1.
B) + 105.9.
C) + 102.6.
D) + 40.
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Deck 14: Entropy and Gibbs Energy
1
The following substances are ordered with increasing entropy: neon gas < liquid water < a gold bar.
False
2
The entropy change for the following reaction will be negative:
C11H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)
False
3
The entropy change for the following reaction will be positive:
N2 (g) + 3 H2 (g) → 2 NH3 (g)
False
4
Entropy is identified with the amount of ________ in the system.
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5
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of ethanol at its boiling point (T<sub>b</sub> =78.45 °C) vaporizes (in the process the temperature does not change,   for ethanol is + 43.5 kJ mol<sup>-1</sup>).</strong> A) + 124. B) - 124. C) + 554. D) + 0.12. , J K-1 mol-1) when 1.00 mol of ethanol at its boiling point (Tb =78.45 °C) vaporizes (in the process the temperature does not change, <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of ethanol at its boiling point (T<sub>b</sub> =78.45 °C) vaporizes (in the process the temperature does not change,   for ethanol is + 43.5 kJ mol<sup>-1</sup>).</strong> A) + 124. B) - 124. C) + 554. D) + 0.12. for ethanol is + 43.5 kJ mol-1).

A) + 124.
B) - 124.
C) + 554.
D) + 0.12.
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6
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of mercury at its boiling point (T<sub>b</sub> = 356.55 °C) vaporizes (in the process the temperature does not change,   for mercury is + 59.3 kJ mol<sup>-1</sup>).</strong> A) - 94. B) + 94. C) + 166. D) + 0.09. , J K-1 mol-1) when 1.00 mol of mercury at its boiling point (Tb = 356.55 °C) vaporizes (in the process the temperature does not change, <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of mercury at its boiling point (T<sub>b</sub> = 356.55 °C) vaporizes (in the process the temperature does not change,   for mercury is + 59.3 kJ mol<sup>-1</sup>).</strong> A) - 94. B) + 94. C) + 166. D) + 0.09. for mercury is + 59.3 kJ mol-1).

A) - 94.
B) + 94.
C) + 166.
D) + 0.09.
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7
Calculate the entropy change ( <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of methane at its melting point (T<sub>m</sub> = - 182.05 °C) freezes (in the process the temperature does not change and   for methane is + 0.94 kJ mol<sup>-1</sup>).</strong> A) - 10.3. B) - 0.01. C) + 10.3. D) - 5.2. , J K-1 mol-1) when 1.00 mol of methane at its melting point (Tm = - 182.05 °C) freezes (in the process the temperature does not change and <strong>Calculate the entropy change (   , J K<sup>-1</sup> mol<sup>-1</sup>) when 1.00 mol of methane at its melting point (T<sub>m</sub> = - 182.05 °C) freezes (in the process the temperature does not change and   for methane is + 0.94 kJ mol<sup>-1</sup>).</strong> A) - 10.3. B) - 0.01. C) + 10.3. D) - 5.2. for methane is + 0.94 kJ mol-1).

A) - 10.3.
B) - 0.01.
C) + 10.3.
D) - 5.2.
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8
For water For water   = + 109 J K<sup>-1</sup> mol<sup>-1</sup> whilst   = + 22 J K<sup>-1</sup> mol<sup>-1</sup>. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature. = + 109 J K-1 mol-1 whilst For water   = + 109 J K<sup>-1</sup> mol<sup>-1</sup> whilst   = + 22 J K<sup>-1</sup> mol<sup>-1</sup>. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature. = + 22 J K-1 mol-1. The entropy change for vaporization is larger than the entropy change for fusion because it is measured at a higher temperature.
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9
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) > 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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10
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) < 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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11
Whether the total entropy change (ΔS(total)) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the (ΔS(total)) condition with its description.
-ΔS(total) = 0

A) spontaneous process
B) non-spontaneous process
C) process at equilibrium
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12
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of methanol is heated at constant pressure from 5 °C to 35 °C, the molar heat capacity, Cp, of methanol is 81.6 J K-1 mol-1, assume that the molar heat capacity, Cp is constant over this temperature range.

A) + 8.36.
B) - 8.36.
C) - 158.79.
D) + 158.79.
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13
Calculate the change of entropy (in J K-1 mol-1) when 1 mol of ethanol is cooled at constant pressure from 25 °C to 10 °C, the molar heat capacity, Cp, of ethanol is 111.5 J K-1 mol-1 and assume that Cp is constant over this temperature range.

A) + 5.8.
B) - 5.8.
C) - 102.2.
D) + 102.2.
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14
When 1 mol of trichloromethane is heated from 5 °C to 20 °C at constant pressure, the change of entropy is + 6.00 J K-1 mol-1. When the solvent is heated further from 20 °C to 35 °C, the change in entropy will also be + 6.00 J K-1 mol-1.
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15
When 1 mol of water is heated from 10 °C to 25 °C at constant pressure, the change in entropy is + 3.89 J K-1 mol-1. When 1 mol of methanol is heated from 10 °C to 25 °C at constant pressure, the change in entropy will be smaller.
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16
At zero kelvin the entropy of a perfect crystal is ____.
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17
Calculate the standard entropy <strong>Calculate the standard entropy   of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, C<sub>p</sub>, of water is 75.3 J K<sup>-1</sup> mol<sup>-1</sup> and   is 69.9 J K<sup>-1</sup> mol<sup>-1</sup>.</strong> A) 69.9. B) - 133.5. C) 68.7. D) 71.1. of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, Cp, of water is 75.3 J K-1 mol-1 and <strong>Calculate the standard entropy   of 1 mol of water at 20 °C and 1 bar. The molar heat capacity, C<sub>p</sub>, of water is 75.3 J K<sup>-1</sup> mol<sup>-1</sup> and   is 69.9 J K<sup>-1</sup> mol<sup>-1</sup>.</strong> A) 69.9. B) - 133.5. C) 68.7. D) 71.1. is 69.9 J K-1 mol-1.

A) 69.9.
B) - 133.5.
C) 68.7.
D) 71.1.
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18
The standard entropy The standard entropy   of ethanol, at 1 bar, is 159.9 J K<sup>-1</sup> mol<sup>-1</sup>. At 315 K, its standard entropy will be larger. of ethanol, at 1 bar, is 159.9 J K-1 mol-1. At 315 K, its standard entropy will be larger.
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19
The standard entropy change for the following reaction will be large and positive. CS2 (l) + 3O2 (g) → CO2 (g) + 2SO2 (g)
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20
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction <strong>Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction   ( in J K<sup>-1</sup> mol<sup>-1</sup>) for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) + 243.0. B) - 243.0. C) - 107.8. D) + 107.8. ( in J K-1 mol-1) for the following reaction: CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

A) + 243.0.
B) - 243.0.
C) - 107.8.
D) + 107.8.
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21
Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction <strong>Using data in Appendix 7, (p. 1350), calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) for the following reaction: NH<sub>3</sub> (g) + HNO<sub>3</sub> (l) → NH<sub>4</sub>NO<sub>3</sub> (s)</strong> A) - 197. B) + 197. C) -151.1. D) +151.1. (in J K-1 mol-1) for the following reaction:
NH3 (g) + HNO3 (l) → NH4NO3 (s)

A) - 197.
B) + 197.
C) -151.1.
D) +151.1.
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22
The standard entropy change, <strong>The standard entropy change,   for the following reaction is: -198.7 J K<sup>-1</sup> mol<sup>-1</sup>. N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 550 K.</strong> A) - 226. B) - 171. C) + 226. D) + 171. for the following reaction is: -198.7 J K-1 mol-1.
N2 (g) + 3 H2 (g) → 2 NH3 (g) Calculate the standard entropy change of reaction <strong>The standard entropy change,   for the following reaction is: -198.7 J K<sup>-1</sup> mol<sup>-1</sup>. N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 550 K.</strong> A) - 226. B) - 171. C) + 226. D) + 171. (in J K-1 mol-1) at 550 K.

A) - 226.
B) - 171.
C) + 226.
D) + 171.
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23
The standard entropy change, <strong>The standard entropy change,   for the following reaction is: + 511.9 J K<sup>-1</sup> mol<sup>-1</sup>. C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 390 116.85 °C.</strong> A) + 511.9. B) + 48.3. C) + 379. D) + 645. for the following reaction is: + 511.9 J K-1 mol-1.
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l) Calculate the standard entropy change of reaction <strong>The standard entropy change,   for the following reaction is: + 511.9 J K<sup>-1</sup> mol<sup>-1</sup>. C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l) Calculate the standard entropy change of reaction   (in J K<sup>-1</sup> mol<sup>-1</sup>) at 390 116.85 °C.</strong> A) + 511.9. B) + 48.3. C) + 379. D) + 645. (in J K-1 mol-1) at 390 116.85 °C.

A) + 511.9.
B) + 48.3.
C) + 379.
D) + 645.
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24
The standard entropy change, The standard entropy change,   is: - 198.7 J K<sup>-1</sup> mol<sup>-1</sup>, for the following reaction: N<sub>2</sub> (g) + 3 H<sub>2</sub> (g) → 2 NH<sub>3</sub> (g) This violates the Second Law of thermodynamics. is: - 198.7 J K-1 mol-1, for the following reaction: N2 (g) + 3 H2 (g) → 2 NH3 (g) This violates the Second Law of thermodynamics.
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25
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG < 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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26
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG > 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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27
Whether Gibbs energy change (ΔG) of a process is positive, negative, or equal to zero defines whether the process is spontaneous. Match the situation with its description.
-ΔG = 0

A) the reaction or process is spontaneous
B) the reaction or process is non-spontaneous
C) the reaction or process is at equilibrium
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28
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS < 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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29
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH > 0, ΔS > 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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30
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS > 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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31
Match the reaction description and whether it is spontaneous and under which conditions
-ΔH < 0, ΔS < 0

A) Never spontaneous
B) Spontaneous on heating
C) Always spontaneous
D) Spontaneous on cooling
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32
An endothermic reaction has <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. , <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. and <strong>An endothermic reaction has   ,   and   . Find the temperature, T(K), at which the reaction becomes spontaneous.</strong> A) 298. B) 783. C) 0.78. D) 1.28. . Find the temperature, T(K), at which the reaction becomes spontaneous.

A) 298.
B) 783.
C) 0.78.
D) 1.28.
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33
Using <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. and <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. data given below:
<strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59.
Calculate the standard Gibbs energy change, <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: 2 NH<sub>3</sub> (g) → N<sub>2</sub> (g) + 3 H<sub>2</sub> (g)</strong> A) + 151. B) - 151. C) + 33. D) - 59. (kJ mol-1), for the following reaction:
2 NH3 (g) → N2 (g) + 3 H2 (g)

A) + 151.
B) - 151.
C) + 33.
D) - 59.
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34
Using <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. and <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. data given below:
<strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. Calculate the standard Gibbs energy change, <strong>Using   and   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CH<sub>4</sub> (g) + 2 O<sub>2</sub> (g) → CO<sub>2</sub> (g) + 2 H<sub>2</sub>O (l)</strong> A) - 818. B) + 71.5. C) + 963. D) - 963. (kJ mol-1), for the following reaction:
CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

A) - 818.
B) + 71.5.
C) + 963.
D) - 963.
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35
Using <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8. data given below:
<strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8.
Calculate the standard Gibbs energy change, <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO (g) + 2 H<sub>2</sub> (g) → CH<sub>3</sub>OH (g)</strong> A) - 299.2. B) + 299.2. C) + 24.8. D) - 24.8. (kJ mol-1), for the following reaction:
CO (g) + 2 H2 (g) → CH3OH (g)

A) - 299.2.
B) + 299.2.
C) + 24.8.
D) - 24.8.
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36
Using <strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. data given below:
<strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. calculate the standard Gibbs energy change, <strong>Using   data given below:   calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: CO<sub>2</sub> (g) + CH<sub>4</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l)</strong> A) - 835.1 B) - 55.3. C) + 835.1. D) + 55.3. (kJ mol-1), for the following reaction:
CO2 (g) + CH4 (g) → CH3CO2H (l)

A) - 835.1
B) - 55.3.
C) + 835.1.
D) + 55.3.
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37
Using <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5. data given below:
<strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5.
Calculate the standard Gibbs energy change, <strong>Using   data given below:   Calculate the standard Gibbs energy change,   (kJ mol<sup>-1</sup>), for the following reaction: C<sub>12</sub>H<sub>22</sub>O<sub>11</sub> (s) + 12 O<sub>2</sub> (g) → 12 CO<sub>2</sub> (g) + 11 H<sub>2</sub>O (l)</strong> A) + 911.5. B) - 5797.9. C) + 5797.9. D) - 911.5. (kJ mol-1), for the following reaction:
C12H22O11 (s) + 12 O2 (g) → 12 CO2 (g) + 11 H2O (l)

A) + 911.5.
B) - 5797.9.
C) + 5797.9.
D) - 911.5.
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38
An endothermic reaction with a positive entropy change will become spontaneous on cooling.
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39
Using the data given below estimate the value of the Gibbs energy change of reaction (kJ mol-1) at 310 K, for the following reaction:
CH3CH2OH (l) + O2 (g) → CH3CO2H (l) + H2O (l)
<strong>Using the data given below estimate the value of the Gibbs energy change of reaction (kJ mol<sup>-1</sup>) at 310 K, for the following reaction: CH<sub>3</sub>CH<sub>2</sub>OH (l) + O<sub>2</sub> (g) → CH<sub>3</sub>CO<sub>2</sub>H (l) + H<sub>2</sub>O (l)  </strong> A) - 450.2 B) - 451.8. C) -41.7. D) -533.8.

A) - 450.2
B) - 451.8.
C) -41.7.
D) -533.8.
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40
Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction:
N2 (g) + 2 O2 (g) → 2 NO2 (g)
<strong>Using the data given below estimate the value of the Gibbs energy change of reaction at 325 K, for the following reaction: N<sub>2</sub> (g) + 2 O<sub>2 </sub>(g) → 2 NO<sub>2</sub> (g)  </strong> A) + 26.1. B) + 105.9. C) + 102.6. D) + 40.

A) + 26.1.
B) + 105.9.
C) + 102.6.
D) + 40.
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