Deck 7: Replication, Maintenance, and Rearrangements of Genomic Dna
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Deck 7: Replication, Maintenance, and Rearrangements of Genomic Dna
1
DNA polymerases can synthesize DNA
A) de novo by catalyzing the polymerization of free dNTPs.
B) by adding dNTPs to complementary dNTPs on a single-stranded DNA.
C) by adding dNTPs to a hydroxyl group on the end of a growing polynucleotide chain hydrogen-bonded to a strand of RNA.
D) by adding dNTPs to a hydroxyl group on the end of a growing polynucleotide chain hydrogen-bonded to a strand of DNA.
A) de novo by catalyzing the polymerization of free dNTPs.
B) by adding dNTPs to complementary dNTPs on a single-stranded DNA.
C) by adding dNTPs to a hydroxyl group on the end of a growing polynucleotide chain hydrogen-bonded to a strand of RNA.
D) by adding dNTPs to a hydroxyl group on the end of a growing polynucleotide chain hydrogen-bonded to a strand of DNA.
D
2
In addition to synthesizing DNA, DNA polymerase I has a second catalytic activity: it can
A) synthesize short RNA sequences.
B) synthesize short polypeptide sequences.
C) remove RNA primers.
D) ligate short segments of DNA together.
A) synthesize short RNA sequences.
B) synthesize short polypeptide sequences.
C) remove RNA primers.
D) ligate short segments of DNA together.
C
3
Short segments of newly synthesized DNA on the lagging strand of DNA are called
A) Okazaki fragments.
B) replicons.
C) origins of replication.
D) lagging fragments.
A) Okazaki fragments.
B) replicons.
C) origins of replication.
D) lagging fragments.
A
4
The short fragments of DNA produced during DNA replication are joined together by
A) RNA polymerase.
B) DNA polymerase.
C) DNA helicase.
D) DNA ligase.
A) RNA polymerase.
B) DNA polymerase.
C) DNA helicase.
D) DNA ligase.
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5
Which eukaryotic DNA polymerase replicates the leading strand in the 5'to 3'direction?
A)
B)
C)
D)
A)
B)
C)
D)
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6
Which eukaryotic DNA polymerase replicates the lagging strand in the 3ʹ to 5ʹ direction?
A) α
B) γ
C) δ
D) None of the above; the lagging strand is replicated in the 5ʹ to 3ʹ direction.
A) α
B) γ
C) δ
D) None of the above; the lagging strand is replicated in the 5ʹ to 3ʹ direction.
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7
Primase synthesizes short sequences of _______ complementary to the _______ strand.
A) DNA; leading
B) RNA; lagging
C) DNA; lagging
D) All of the above
A) DNA; leading
B) RNA; lagging
C) DNA; lagging
D) All of the above
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8
In eukaryotic cells, RNA primers are removed by the combined action of 5ʹ to 3ʹ exonucleases and
A) Rnase A.
B) RNase H.
C) DNA polymerase I.
D) DNA polymerase α.
A) Rnase A.
B) RNase H.
C) DNA polymerase I.
D) DNA polymerase α.
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9
Eukaryotic DNA polymerase ε
A) is the polymerase for leading-strand replication.
B) is the polymerase for lagging-strand replication.
C) fills in the gaps between Okazaki fragments.
D) functions primarily in repair of DNA damage.
A) is the polymerase for leading-strand replication.
B) is the polymerase for lagging-strand replication.
C) fills in the gaps between Okazaki fragments.
D) functions primarily in repair of DNA damage.
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10
In E. coli, the major enzyme responsible for DNA replication is DNA polymerase
A)
B)
C)
D)
A)
B)
C)
D)
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11
Proliferating cell nuclear antigen (PCNA) is a(n) _______ in eukaryotes.
A) DNA polymerase
B) sliding-clamp protein
C) single-stranded DNA binding protein
D) origin-of-replication binding protein
A) DNA polymerase
B) sliding-clamp protein
C) single-stranded DNA binding protein
D) origin-of-replication binding protein
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12
Free rotation of one cut DNA strand around one uncut strand is the primary function of
A) topoisomerase I.
B) topoisomerase II.
C) DNA helicase.
D) DNA polymerase.
A) topoisomerase I.
B) topoisomerase II.
C) DNA helicase.
D) DNA polymerase.
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13
The function of topoisomerase II is to
A) resolve DNA tangles.
B) allow DNA to swivel and unwind.
C) allow daughter chromatids to separate in anaphase.
D) All of the above
A) resolve DNA tangles.
B) allow DNA to swivel and unwind.
C) allow daughter chromatids to separate in anaphase.
D) All of the above
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14
During DNA replication, the overall error frequency is 1 in _______ base pairs.
A) 105
B) 106
C) 108
D) 109
A) 105
B) 106
C) 108
D) 109
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15
The proofreading property of DNA polymerase is due to its _______ activity.
A) 3ʹ to 5ʹ exonuclease
B) 5ʹ to 3ʹ exonuclease
C) excision repair
D) endonuclease
A) 3ʹ to 5ʹ exonuclease
B) 5ʹ to 3ʹ exonuclease
C) excision repair
D) endonuclease
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16
Origins of replication are the
A) sites where DNA transcription starts.
B) binding sites for the protein complex that initiates DNA synthesis.
C) loops with two replication forks seen in replicating DNA.
D) forks where DNA replication is occurring.
A) sites where DNA transcription starts.
B) binding sites for the protein complex that initiates DNA synthesis.
C) loops with two replication forks seen in replicating DNA.
D) forks where DNA replication is occurring.
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17
Autonomously replicating sequences are
A) yeast plasmids.
B) yeast telomeres.
C) bacterial plasmids.
D) yeast origins of replication.
A) yeast plasmids.
B) yeast telomeres.
C) bacterial plasmids.
D) yeast origins of replication.
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18
Telomeres are the
A) midpoints of chromosomes.
B) microtubule attachment points on chromosomes.
C) end-sequences of chromosomes.
D) enzyme complexes that complete DNA replication.
A) midpoints of chromosomes.
B) microtubule attachment points on chromosomes.
C) end-sequences of chromosomes.
D) enzyme complexes that complete DNA replication.
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19
Telomerase is
A) a reverse transcriptase.
B) the enzyme that adds a random sequence to the ends of chromosomes.
C) an enzyme first discovered in Thermus aquaticus.
D) An enzyme that breaks down DNA from the ends.
A) a reverse transcriptase.
B) the enzyme that adds a random sequence to the ends of chromosomes.
C) an enzyme first discovered in Thermus aquaticus.
D) An enzyme that breaks down DNA from the ends.
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20
Pyrimidine dimers
A) block DNA replication and transcription.
B) can be repaired by photoreactivation.
C) can be repaired by nucleotide-excision repair.
D) All of the above
A) block DNA replication and transcription.
B) can be repaired by photoreactivation.
C) can be repaired by nucleotide-excision repair.
D) All of the above
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21
The human disease in which affected individuals are extremely sensitive to sunlight and develop multiple skin cancers on exposed areas is called
A) melanoma.
B) zero pigment disease.
C) xeroderma pigmentosum.
D) Cockayne's syndrome.
A) melanoma.
B) zero pigment disease.
C) xeroderma pigmentosum.
D) Cockayne's syndrome.
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22
Cultured cells from xeroderma pigmentosum patients were unable to carry out
A) base-excision repair.
B) nucleotide-excision repair.
C) synthesis of melanin.
D) DNA synthesis.
A) base-excision repair.
B) nucleotide-excision repair.
C) synthesis of melanin.
D) DNA synthesis.
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23
The most common cause of skin cancer is damage to DNA by
A) infrared light.
B) ultraviolet light.
C) γ radiation.
D) β particle radiation.
A) infrared light.
B) ultraviolet light.
C) γ radiation.
D) β particle radiation.
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24
The human genes that convey a susceptibility to hereditary nonpolyposis colorectal cancer are genes coding proteins involved in the DNA repair mechanism called
A) mismatch repair.
B) nucleotide-excision repair.
C) photoreactivation.
D) transcription-coupled repair.
A) mismatch repair.
B) nucleotide-excision repair.
C) photoreactivation.
D) transcription-coupled repair.
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25
Patients with hereditary nonpolyposis colorectal cancer genes should have
A) frequent colonoscopies.
B) a colectomy.
C) gene-replacement therapy.
D) an intraperitoneal injection of the normal enzyme.
A) frequent colonoscopies.
B) a colectomy.
C) gene-replacement therapy.
D) an intraperitoneal injection of the normal enzyme.
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26
E. coli DNA polymerase V
A) is induced in response to high temperatures.
B) recognizes thymine dimers and inserts nucleotides on the opposite strand.
C) has a low frequency of errors.
D) is activated during transcription.
A) is induced in response to high temperatures.
B) recognizes thymine dimers and inserts nucleotides on the opposite strand.
C) has a low frequency of errors.
D) is activated during transcription.
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27
Double-stranded breaks are repaired by
A) direct reversal of DNA damage.
B) translesion repair.
C) excision repair.
D) recombinational repair.
A) direct reversal of DNA damage.
B) translesion repair.
C) excision repair.
D) recombinational repair.
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28
The gene responsible for inherited breast cancer (BRCA2) encodes a protein that is involved in
A) initiation of cell death by apoptosis.
B) regulation of cell proliferation.
C) repair of double-strand DNA breaks by homologous recombination.
D) error-prone repair.
A) initiation of cell death by apoptosis.
B) regulation of cell proliferation.
C) repair of double-strand DNA breaks by homologous recombination.
D) error-prone repair.
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29
Site-specific recombination
A) occurs in randomly occurring DNA sequences.
B) is mediated by proteins that recognize specific DNA target sequences.
C) leads to programmed cell death.
D) is also referred to as homologous recombination.
A) occurs in randomly occurring DNA sequences.
B) is mediated by proteins that recognize specific DNA target sequences.
C) leads to programmed cell death.
D) is also referred to as homologous recombination.
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30
Site-specific recombination occurs commonly during
A) mitosis of somatic cells.
B) meiosis of germ cells.
C) development of immune-system cells.
D) prokaryotic cell division.
A) mitosis of somatic cells.
B) meiosis of germ cells.
C) development of immune-system cells.
D) prokaryotic cell division.
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31
Recombination of DNA strands is important because it can
A) rearrange DNA sequences to change gene expression during development.
B) inactivate the repair of damaged sequences.
C) inhibit diversity in the next generation.
D) All of the above
A) rearrange DNA sequences to change gene expression during development.
B) inactivate the repair of damaged sequences.
C) inhibit diversity in the next generation.
D) All of the above
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32
Which of the following regions make up a mature immunoglobulin heavy chain?
A) VDJC
B) VJC
C) VDJ
D) VDJR
A) VDJC
B) VJC
C) VDJ
D) VDJR
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33
Which region is not part of the immunoglobulin light chain?
A) V region
B) J region
C) D region
D) C region
A) V region
B) J region
C) D region
D) C region
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34
In the mouse, the total number of heavy chains that can be generated by site-specific recombination events is about
A) 600.
B) 7,200.
C) 105.
D) 106.
A) 600.
B) 7,200.
C) 105.
D) 106.
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35
A major difference between immunoglobulin heavy chains and light chains is that heavy chains contain _______ regions.
A) V
B) D
C) J
D) C
A) V
B) D
C) J
D) C
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36
Mutations in the genes for RAG1 and RAG2 would most likely have an effect on
A) VDJ recombination in the immune system.
B) mismatch repair.
C) excision repair.
D) translesion DNA synthesis.
A) VDJ recombination in the immune system.
B) mismatch repair.
C) excision repair.
D) translesion DNA synthesis.
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37
T cell receptors
A) are found in the circulation.
B) contain variable and regulatory regions.
C) are tetrameric complexes that contain , , , and polypeptide chains.
D) bind antigens present on the surface of other cells.
A) are found in the circulation.
B) contain variable and regulatory regions.
C) are tetrameric complexes that contain , , , and polypeptide chains.
D) bind antigens present on the surface of other cells.
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38
Gene amplification is
A) seen in ribosomal genes of developing amphibian oocytes.
B) seen in the genes for muscle proteins of developing muscle cells.
C) seen in the genes for immunoglobulins during B lymphocyte development.
D) never seen in eukaryotic cells, since the amount of DNA per cell is always constant, except during S phase of the cell cycle.
A) seen in ribosomal genes of developing amphibian oocytes.
B) seen in the genes for muscle proteins of developing muscle cells.
C) seen in the genes for immunoglobulins during B lymphocyte development.
D) never seen in eukaryotic cells, since the amount of DNA per cell is always constant, except during S phase of the cell cycle.
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39
A mutation in the enzyme _______ will block the separation of daughter chromatids in mitosis.
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40
On one typical eukaryotic chromosome there are, in number, _______ telomere(s) and _______ origin(s) of replication.
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41
On a typical prokaryotic chromosome the number of telomeres and origins of replication is _______ telomere(s) and _______ origin(s) of replication.
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42
The BRCA genes responsible for inherited breast cancer are involved in the repair of _______ DNA breaks by homologous recombination.
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43
Repair of double-strand breaks in DNA caused by ionizing radiation often leads to the loss of _______ around the site of damage.
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44
The genes that encode the immunoglobulin light chain consist of regions that are called _______, _______, and _______.
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45
IgM antibodies contain _______ constant regions in their heavy chains.
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46
T cell receptors bind to _______ on the surface of other cells during immune responses.
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47
T cell receptors resemble _______ in many ways.
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48
_______ can be beneficial to organisms such as amphibians to accommodate the generation of large pools of rRNAs, while it can be deleterious in some forms of cancer by dramatically increasing the number of genes driving proliferation.
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49
All known DNA polymerases synthesize DNA in the 5ʹ to 3ʹ direction.
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50
Mitochondria have their own unique DNA polymerase.
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51
Eukaryotic cells have many different DNA polymerases, one or more of which function primarily in repair of damaged DNA.
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52
The leading and lagging strands at a replication fork are synthesized in opposite directions, but both are synthesized in a continuous manner.
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53
Both topoisomerase I and topoisomerase II allow DNA to relieve torsion.
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54
Some DNA polymerases have a nuclease activity that allows them to remove mismatched nucleotides and repair a sequence.
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55
Proofreading is done by DNA polymerases.
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56
DNA replication starts at sites called replication forks.
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57
Yeast origins of replication are autonomously replicating sequences.
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58
The rate of DNA replication in mammalian cells is tenfold faster than in prokaryotic cells.
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59
Telomere sequences form loops at the ends of eukaryotic chromosomes.
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60
Telomerase is a reverse transcriptase.
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61
Telomerase carries its own template DNA.
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62
Telomerase extends the ends of linear chromosomes by making a copy that is complementary to the other strand of DNA.
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63
DNA glycosylase can give rise to apyrimidinic and apurinic sites by cleaving bases from their deoxyribose on the DNA backbone.
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64
DNA polymerases cannot replicate DNA across from a site of DNA damage.
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65
Somatic hypermutation is focused in the diversity region of the immunoglobulin gene.
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66
How do DNA polymerases differ from RNA polymerases in terms of primer requirement?
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67
Why does the synthesis of Okazaki fragments require an RNA primer?
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68
Why does DNA polymerase synthesize DNA only in the 5ʹ to 3ʹ direction?
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69
Explain how a prokaryotic chromosome can replicate and divide normally with no telomeres and only one origin of replication.
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70
What are the functions of origins of replication?
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71
What are the functions of telomeres?
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72
Why is telomerase important in cancer cells?
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73
What type of DNA damage would you expect to occur more frequently in populations as they near the equator?
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74
Explain Tonegawa's key conclusion about the development of immunoglobulin genes.
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75
In E. coli, the major enzyme responsible for DNA replication is DNA polymerase
A) I.
B) II.
C) III.
D) .
A) I.
B) II.
C) III.
D) .
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76
Which statement is true of all known DNA polymerases?
A) They synthesize DNA in the 5ʹ to 3ʹ direction, and they require a preformed primer hydrogen-bonded to the template.
B) They synthesize DNA in the 5ʹ to 3ʹ direction, and they possess primase activity.
C) They require a preformed primer, and they possess helicase activity.
D) They synthesize DNA in the 3ʹ to 5ʹ direction, and they possess exonuclease activity.
A) They synthesize DNA in the 5ʹ to 3ʹ direction, and they require a preformed primer hydrogen-bonded to the template.
B) They synthesize DNA in the 5ʹ to 3ʹ direction, and they possess primase activity.
C) They require a preformed primer, and they possess helicase activity.
D) They synthesize DNA in the 3ʹ to 5ʹ direction, and they possess exonuclease activity.
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77
DNA polymerase requires a primer and cannot initiate synthesis de novo. What serves as a primer for DNA replication?
A) Short fragments of DNA complementary to the template strand
B) A protein with a free OH group
C) Short fragments of RNA complementary to the template strand
D) Double-stranded hairpins at the end of the DNA molecule that are formed by a looping of the DNA
A) Short fragments of DNA complementary to the template strand
B) A protein with a free OH group
C) Short fragments of RNA complementary to the template strand
D) Double-stranded hairpins at the end of the DNA molecule that are formed by a looping of the DNA
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78
Which statement concerning elongation of DNA at the replication fork is false?
A) The leading strand is synthesized continuously in the direction of replication fork movement.
B) The lagging strand is synthesized in Okazaki fragments backward from the overall direction of replication.
C) The Okazaki fragments are joined by the action of DNA ligase.
D) Both strands are synthesized continuously at the replication fork.
A) The leading strand is synthesized continuously in the direction of replication fork movement.
B) The lagging strand is synthesized in Okazaki fragments backward from the overall direction of replication.
C) The Okazaki fragments are joined by the action of DNA ligase.
D) Both strands are synthesized continuously at the replication fork.
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79
The twisting of the parental DNA strands around each other ahead of a replication fork is relieved by enzymes called
A) DNA helicases.
B) topoisomerases.
C) DNA ligases.
D) DNA polymerases.
A) DNA helicases.
B) topoisomerases.
C) DNA ligases.
D) DNA polymerases.
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80
During replication, _______ stabilize the unwound DNA template so it can be copied by the DNA polymerase.
A) Single-stranded DNA-binding proteins
B) Helicases
C) PCNAs
D) Topoisomerases
A) Single-stranded DNA-binding proteins
B) Helicases
C) PCNAs
D) Topoisomerases
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