Deck 19: Ordinary Differential Equations

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Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + cos(x - y) = sin x.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above <div style=padding-top: 35px> + cos(x - y) = sin x.

A) 2nd order; linear
B) 2nd order; nonlinear
C) 1st order; nonlinear
D) 1st order; linear
E) None of the above
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Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   +   y = sin x</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above <div style=padding-top: 35px> + <strong>State the order of the following differential equation and whether it is linear or nonlinear:   +   y = sin x</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above <div style=padding-top: 35px> y = sin x

A) 1st order; nonlinear
B) 1st order; linear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   - x   = 0.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above <div style=padding-top: 35px> - x <strong>State the order of the following differential equation and whether it is linear or nonlinear:   - x   = 0.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above <div style=padding-top: 35px> = 0.

A) 2nd order; linear
B) 2nd order; nonlinear
C) 1st order; nonlinear
D) 1st order; linear
E) None of the above
Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   = 3x.</strong> A) 1st order; linear B) 1st order; nonlinear C) 6th order; linear D) 6th order; nonlinear E) None of the above <div style=padding-top: 35px> = 3x.

A) 1st order; linear
B) 1st order; nonlinear
C) 6th order; linear
D) 6th order; nonlinear
E) None of the above
Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   =   + 2.</strong> A) nth order; linear B) nth order; nonlinear C) 1st order; linear D) 1st order; nonlinear E) None of the above <div style=padding-top: 35px> = <strong>State the order of the following differential equation and whether it is linear or nonlinear:   =   + 2.</strong> A) nth order; linear B) nth order; nonlinear C) 1st order; linear D) 1st order; nonlinear E) None of the above <div style=padding-top: 35px> + 2.

A) nth order; linear
B) nth order; nonlinear
C) 1st order; linear
D) 1st order; nonlinear
E) None of the above
Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + y =  </strong> A) 2nd order; linear B) 2nd order; nonlinear C) 3/2 order; nonlinear D) 3/2 order; linear E) None of the above <div style=padding-top: 35px> + y = <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + y =  </strong> A) 2nd order; linear B) 2nd order; nonlinear C) 3/2 order; nonlinear D) 3/2 order; linear E) None of the above <div style=padding-top: 35px>

A) 2nd order; linear
B) 2nd order; nonlinear
C) 3/2 order; nonlinear
D) 3/2 order; linear
E) None of the above
Question
Find two values of r such that y = <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 <div style=padding-top: 35px> is a solution of <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 <div style=padding-top: 35px> <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 <div style=padding-top: 35px> - 9x <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 <div style=padding-top: 35px> - 24y = 0, x > 0.

A) r = 6, 4
B) r = -8, 3
C) r = 12, -2
D) r = -12, 2
E) r = -6, -4
Question
State the order of the following differential equation and whether it is linear or nonlinear:y <strong>State the order of the following differential equation and whether it is linear or nonlinear:y   = 1.</strong> A) 1st order; linear B) 1st order; nonlinear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above <div style=padding-top: 35px> = 1.

A) 1st order; linear
B) 1st order; nonlinear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
Question
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   = xy.</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above <div style=padding-top: 35px> = xy.

A) 1st order; nonlinear
B) 1st order; linear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
Question
Specify the interval where y = ln x is a solution of the differential equation x  <strong>Specify the interval where y = ln x is a solution of the differential equation x   +   = 0.</strong> A) (- \infty , 0) B) (-1, 1) C) (- \infty ,  \infty ) D) (0, \infty ) E) None of the above <div style=padding-top: 35px>  +  <strong>Specify the interval where y = ln x is a solution of the differential equation x   +   = 0.</strong> A) (- \infty , 0) B) (-1, 1) C) (- \infty ,  \infty ) D) (0, \infty ) E) None of the above <div style=padding-top: 35px>  = 0.

A) (- ∞\infty , 0)
B) (-1, 1)
C) (- ∞\infty , ∞\infty )
D) (0, ∞\infty )
E) None of the above
Question
Solve the initial-value problem <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px> + 4y = 10, y(0) = 200.

A) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
B) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
C) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
D) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
E) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   <div style=padding-top: 35px>
Question
Solve the differential equation <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px> = 6x <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px> .

A) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px>
B) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px>
C) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px>
D) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px>
E) x= C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   <div style=padding-top: 35px>
Question
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> = 3 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> , y(0) = 0.

A) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> - 12
B) 9 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> - 36
C) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> - <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px>
D) - <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> + 12
E) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <div style=padding-top: 35px> + 12
Question
Determine the solution of the differential equation <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> = (1 - 2x) <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> that satisfies the condition <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>

A) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
B) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
C) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
D) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
E) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px> + 3tx = 2t.

A) x = -1 + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px>
B) x = <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px>
C) x = 2 + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px>
D) x = <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px>
E) x = - <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px> <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px> = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px>

A) x = -2 <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px>
B) x = 2 <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px>
C) x = - <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px>
D) x = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px>
E) x = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <div style=padding-top: 35px> + C
Question
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px> = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px> , x(0) = 4.

A) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
B) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
C) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
D) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
E) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
Question
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> = <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> , x(0) = a.

A) x = -ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> )
B) x = ln(1 + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> )
C) x = -ln(1 + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> )
D) x = ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> )
E) x = ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) <div style=padding-top: 35px> )
Question
Solve the initial-value problem <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px> = - <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px> , y(0) = 1.

A) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px>
B) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px>
C) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px>
D) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px>
E) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   <div style=padding-top: 35px>
Question
Find an integrating factor of the form μ(y) for the differential equation Find an integrating factor of the form μ(y) for the differential equation   and hence find its general solution.<div style=padding-top: 35px> and hence find its general solution.
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Find the function satisfying <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x) = x <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> , F(0) = 1.

A) F(x) = -1 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x + 1)
B) F(x) = 1 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x - 1)
C) F(x) = 2 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x + 1)
D) F(x) = 2 + <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x - 1)
E) F(x) = 3 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) <div style=padding-top: 35px> (x + 1)
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Find the solution of the differential equation <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> = 12 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - 2x + 1 that satisfies y(1) = 3.

A) y = <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - 2
B) 8x <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> + x + C
C) 8 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> + x
D) 8x <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> + x - 5
E) 8 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <div style=padding-top: 35px> + x + 5
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Solve the initial-value problem x Solve the initial-value problem x   = y (1 + ln(y) - ln(x)), y(1) =   .<div style=padding-top: 35px> = y (1 + ln(y) - ln(x)), y(1) = Solve the initial-value problem x   = y (1 + ln(y) - ln(x)), y(1) =   .<div style=padding-top: 35px> .
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> .

A) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
B) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
C) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
D) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
E) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px> = -9 <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px> .

A) <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px>
B) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px>
C) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px>
D) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px>
E) <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <div style=padding-top: 35px>
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The nonexact differential equation M (t, x)) dt + N(t, x) dx = 0 has an integration factor that depends only upon x, if the quantity The nonexact differential equation M (t, x)) dt + N(t, x) dx = 0 has an integration factor that depends only upon x, if the quantity   is independent of t.<div style=padding-top: 35px> is independent of t.
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Given the differential equation (7 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> + k <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> + 19y) dx + (19x + 2 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> + 23 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <div style=padding-top: 35px> )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.

A) k = 10, m = -3, n = -15
B) k = -26, m = 3, n = 13
C) k = -6, m = -5, n = 15
D) k = -10, m = -3, n = 15
E) k = 26, m = 3, n = -13
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Find all solutions to <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> = 1 + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> .

A) y - <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> (y) = t + C
B) y - <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> (y) = 2t + C
C) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> (y) = t + C
D) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> (y) = 2t + C
E) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C <div style=padding-top: 35px> (y) = 2t + C
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Solve the following initial-value problem: <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px> = 9.8 - 0.196v, v(0) = 48.

A) v = 50 - <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px>
B) v = 50 - 2 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px>
C) v = 50 + 2 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px>
D) v = 100 - 4 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px>
E) v = 50 + <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   <div style=padding-top: 35px>
Question
A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> = -k <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec.
(a) What is the value of k?
(b) When will the boat slow to 5 ft/sec?

A) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> (b) 70 s
B) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> (b) 700 s
C) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> (b) 140 s
D) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> (b) 100 s
E) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s <div style=padding-top: 35px> (b) 50 s
Question
The change of dependent variable y = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> transforms the equation x <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> + y = x <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> cos(x) into

A) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px>
B) ln(v) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px>
C) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> = cos(x)
D) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> - <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> = cos(x)
E) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> - <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) <div style=padding-top: 35px> = -cos(x)
Question
Determine a multiplier (integrating factor) of the first order linear differential equation  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>

A) μ\mu (x) = -  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>
B) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>
C) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>
D) μ\mu (x) = -  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>
E) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =   <div style=padding-top: 35px>
Question
Find a general solution of the first order linear differential equation <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>

A) y = - <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>
B) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>
C) y = - <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> - C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>
D) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> - C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>
E) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px> + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <div style=padding-top: 35px>
Question
Find a general solution to the first order linear differential equation <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px>

A) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + C
B) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px>
C) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px>
D) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px>
E) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px> + <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   <div style=padding-top: 35px>
Question
Find a general solution to the first order linear differential equation <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>

A) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>
B) y = <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>
C) y = <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ln(1 - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>
D) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ln(1 - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>
E) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px> ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>

A) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>
B) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px> - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>
C) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px> - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>
D) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>
E) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px> - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   <div style=padding-top: 35px>
Question
Solve the initial-value problem <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>

A) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
B) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
C) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
D) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
E) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =   <div style=padding-top: 35px>
Question
Solve the differential equation <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px> = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px> + 2 <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px> .

A) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px>
B) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px>
C) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px>
D) y = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px>
E) y = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   <div style=padding-top: 35px>
Question
Solve the differential equation (3y + 8x <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> ) dx + (x + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> y) dy = 0 by finding an integrating factor depending on x.

A) 3xy + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> = C
B) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> y + 3 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> = C
C) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> y + 2 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> = C
D) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> y + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> = C
E) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> y + 2 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <div style=padding-top: 35px> = C
Question
A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?

A) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> = 2 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> , Q(0) = 60 (b) Q(t) = 200 - 340 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> (c) 200 grams
B) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> = 4 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> , Q(0) = 60 (b) Q(t) = 400 - 340 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> (c) 400 grams
C) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> = 400 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> , Q(0) = 60 (b) Q(t) = 40 - 34 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> (c) 40 grams
D) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> = 400 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> , Q(0) = 60 (b) Q(t) = 4 - 3.4 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> (c) 4 grams
E) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> = 200 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> , Q(0) = 60 (b) Q(t) = 20 - 34 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams <div style=padding-top: 35px> (c) 20 grams
Question
Solve the following initial-value problem:cos(x)  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  + sin(x)y = 2  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  (x) sin(x) - 1, y(  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  ) = 3  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  , 0 ≤\le x ≤\le  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  .

A) y = -  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  cos(x)
B) y = +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  cos(x)
C) y = -  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  x - sin(x) + 7 cos(x)
D) y = +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  x - sin(x) + 7 cos(x)
E) y =  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x) <div style=padding-top: 35px>  cos(x)
Question
Use Euler's method to determine an approximate value of the solution of the initial-value problem <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978 <div style=padding-top: 35px> <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978 <div style=padding-top: 35px> using step size <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978 <div style=padding-top: 35px>

A) 45.6755
B) 43.6755
C) 34.4115
D) 24.5725
E) 64.8978
Question
Use Euler's method to determine an approximate value of the solution of the initial-value problem <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 <div style=padding-top: 35px> <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 <div style=padding-top: 35px> using step size <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 <div style=padding-top: 35px> Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 55.5074
B) 57.7279
C) 60.0371
D) 62.4386
E) 64.8978
Question
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351 <div style=padding-top: 35px> <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351 <div style=padding-top: 35px> using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351 <div style=padding-top: 35px>

A) 110.4464
B) 120.6730
C) 115.2341
D) 112.3558
E) 145.2351
Question
Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123 <div style=padding-top: 35px> <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123 <div style=padding-top: 35px> on the interval <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123 <div style=padding-top: 35px>

A) 0.5387
B) 0.5633
C) 0.5732
D) 0.5700
E) 0.5123
Question
Use the improved Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978 <div style=padding-top: 35px> <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978 <div style=padding-top: 35px> using step size <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978 <div style=padding-top: 35px>

A) 27.3480
B) 40.9407
C) 59.9382
D) 88.7036
E) 64.8978
Question
Use the improved Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 <div style=padding-top: 35px> <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 <div style=padding-top: 35px> using step size <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 <div style=padding-top: 35px> Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 59.8473
B) 62.2892
C) 64.8307
D) 67.2433
E) 64.8978
Question
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621 <div style=padding-top: 35px> <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621 <div style=padding-top: 35px> using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621 <div style=padding-top: 35px>

A) 633.8378
B) 316.6792
C) 156.6864
D) 76.6012
E) 164.3621
Question
Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745 <div style=padding-top: 35px> <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745 <div style=padding-top: 35px> on the interval <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745 <div style=padding-top: 35px>

A) 0.4662
B) 0.5215
C) 0.5272
D) 0.4978
E) 0.9745
Question
Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576 <div style=padding-top: 35px> <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576 <div style=padding-top: 35px> using step size <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576 <div style=padding-top: 35px>

A) 144.3001
B) 96.4752
C) 64.8581
D) 43.4739
E) 72.8576
Question
Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 <div style=padding-top: 35px> <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 <div style=padding-top: 35px> using step size <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 <div style=padding-top: 35px> Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 59.8473
B) 67.5463
C) 64.8978
D) 70.3027
E) 71.6654
Question
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736 <div style=padding-top: 35px> <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736 <div style=padding-top: 35px> using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736 <div style=padding-top: 35px>

A) 154.9004
B) 151.8943
C) 146.0963
D) 121.3222
E) 138.5736
Question
Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582 <div style=padding-top: 35px> <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582 <div style=padding-top: 35px> on the interval <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582 <div style=padding-top: 35px>

A) 0.5321
B) 0.5380
C) 0.5407
D) 0.5487
E) 0.5582
Question
Solve the integral equation y(x) = 1 + <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> dt by reinterpreting it as an initial-value problem.

A) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
B) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
C) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
D) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
E) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
Question
Solve the initial-value problem <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> + 2 = 0, <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> (2) = 3, y(-1) = -4.

A) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> + 7x + 12
B) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> + 7x - 12
C) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> + x - 2
D) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> + 7x + 4
E) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 <div style=padding-top: 35px> - x - 4
Question
Solve the initial-value problem x <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px> + 3 <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px> = 0, <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px> (1) = 2, y(1) = 3.

A) y = 4 - <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px>
B) y = 2 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px>
C) y = 5 - <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px>
D) y = 1 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px>
E) y = 4 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   <div style=padding-top: 35px>
Question
Solve the initial-value problem <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above <div style=padding-top: 35px> = 1 + <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above <div style=padding-top: 35px> , <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above <div style=padding-top: 35px> (0) = 1, y(0) = 0.

A) y = -ln(cos(x) - sin(x))
B) y = ln(cos(x) - sin(x))
C) y = -ln(sin(x) - cos(x))
D) y = ln(sin(x) - cos(x))
E) None of the above
Question
Solve the initial-value problem <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> - 2y <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> = 0, <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px> (3) = 1, y(3) = 1.

A) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
B) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
C) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
D) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
E) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   <div style=padding-top: 35px>
Question
Given that y = x is a solution of the differential equation <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 <div style=padding-top: 35px> , find the solution of the equation that satisfies y(1) = 3 and <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 <div style=padding-top: 35px> (1) = 5.

A) y = 3x + 2ln(x)
B) y = x + <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 <div style=padding-top: 35px>
C) y = 3x + 2xln(x)
D) y = x + <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 <div style=padding-top: 35px>
E) y = 5x -2
Question
Verify that y = <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> is a solution of the equation <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> , and find the general solution of this equation

A) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px>
B) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> ln x
C) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> + Bx
D) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> + B
E) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px> + Bx <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> - <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + 12y = 0.

A) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px>
B) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px>
C) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px>
D) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px>
E) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px> + Bx <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px> + 6 <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px> + 9y = 0.

A) y = A <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px>
B) y = (A + Bx) <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px>
C) y = (A + Bx) <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px>
D) y = Ax <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px> + Bx <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px>
E) y = A <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px> + Bx <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px> + 17y = 0.

A) y = [Acos(4x) + Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px>
B) y = [Acos(4x) - Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px>
C) y = [Acos(4x) + Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px>
D) y = [Acos(4x) - Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px>
E) y = [Acos(x) + Bsin(x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation Find the general solution of the differential equation   y= 0, where D stands for the differential operator   .<div style=padding-top: 35px> y= 0, where D stands for the differential operator Find the general solution of the differential equation   y= 0, where D stands for the differential operator   .<div style=padding-top: 35px> .
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> - 10 <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> + 74y = 0.

A) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> sin(7t)
B) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> sin(7t)
C) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> cos(5t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> sin(5t)
D) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> cos(5t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> sin(5t)
E) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <div style=padding-top: 35px> sin(7t)
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + 13 <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + 3y = 0.

A) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px>
B) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> - <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px>
C) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px>
D) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px>
E) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <div style=padding-top: 35px>
Question
Solve the initial-value problem 12 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> - <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> -6y = 0; y(0) = 2, <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> (0) = 10.

A) y(t) = 6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> - 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px>
B) y(t) = 4 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> - 2 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px>
C) y(t) = -6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> + 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px>
D) y(t) = -4 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> + 6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px>
E) y(t) = -6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px> + 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   <div style=padding-top: 35px>
Question
Solve the initial-value problem <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> + 2y = 0; y(0) = 4, <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> (0) = -2.

A) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> cos t - 6 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> sin t
B) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> cos t - 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> sin t
C) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> cos t + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> sin t
D) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> cos t + 6 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> sin t
E) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> cos t + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t <div style=padding-top: 35px> sin t
Question
Solve the initial-value problem <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px> + 8 <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px> + 16y = 0; y(0) = 3, <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px> (0) = 1.

A) y = (13t + 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px>
B) y = (13t - 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px>
C) y = (13t + 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px>
D) y = (7t + 1) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px>
E) y = (7t - 1) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   <div style=padding-top: 35px>
Question
Solve the initial-value problem <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> + 4 <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> = 0, y(1)= 1, <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> (1) = 2.

A) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px>
B) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px>
C) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px>
D) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px>
E) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px> <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <div style=padding-top: 35px>
Question
Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> t <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> .

A) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> - 100y = 0
B) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 100y = 0
C) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> - 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 100y = 0
D) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> - 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> - 100y = 0
E) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 10 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <div style=padding-top: 35px> + 100y = 0
Question
Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = . <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px>

A) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> - 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> - y = 0
B) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> - y = 0
C) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> - 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + y = 0
D) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + 2y = 0
E) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <div style=padding-top: 35px> + y = 0
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> - 2y = 0.

A) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px>
B) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px>
C) y = A exp(t) + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px>
D) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px>
E) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> - 16y = 0.

A) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + C cos(2t) + D sin(2t)
B) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + C cos(2t) + D sin(2t)
C) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + C cos(4t) + D sin(4t)
D) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> cos(2t) + D <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> sin(2t)
E) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> cos(4t) + D <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) <div style=padding-top: 35px> sin(4t)
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + 4 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + 6 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> +4 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + y = 0.

A) y = <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px>
B) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + Ct <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + Dt <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px>
C) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + D <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px>
D) y = <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px>
E) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + C <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px> + D <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <div style=padding-top: 35px>
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px> + 4y = 0.

A) y = cos(2x) + sin(2x)
B) y = cos(-2x) + sin(-2x)
C) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px>
D) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px>
E) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px> <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <div style=padding-top: 35px>
Question
If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> find the general solution of the DE.

A) y = A <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + (D + Et) cos(t) + (F + Gt) sin(t)
B) y = <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> (A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> ) + (D + Et) cos(t) + (F + Gt) sin(t)
C) y = A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + (D + Et) cos(t/2) + (F + Gt) sin(t/2)
D) y = A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + (D + Et) cos(t) + (F + Gt) sin(t)
E) y = A <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + Bt <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <div style=padding-top: 35px> + (D + Et) cos(t) + (F + Gt) sin(t)
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) <div style=padding-top: 35px>

A) y = Ax + B <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) <div style=padding-top: 35px>
B) y = x(A cos(ln x) + B sin(ln x))
C) A + Bx
D) A + B <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) <div style=padding-top: 35px>
E) y = x(A <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) <div style=padding-top: 35px> + B x <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) <div style=padding-top: 35px> )
Question
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = Ax cos(ln x) + Bx sin(ln x) B) y = A cos(2ln x) + B sin(2ln x) C) y = A cos(ln x) + B sin(ln x) D) y = Ax + Bx ln x E) y = Ax cos x + Bx sin x <div style=padding-top: 35px>

A) y = Ax cos(ln x) + Bx sin(ln x)
B) y = A cos(2ln x) + B sin(2ln x)
C) y = A cos(ln x) + B sin(ln x)
D) y = Ax + Bx ln x
E) y = Ax cos x + Bx sin x
Question
Solve the initial-value problem <strong>Solve the initial-value problem  </strong> A) y = 3t - 2t ln t B) y = 4t - 3t ln t C) y = 3t + 2t ln t D) y = 3t + 2 ln t E) y = 3t - t ln t <div style=padding-top: 35px>

A) y = 3t - 2t ln t
B) y = 4t - 3t ln t
C) y = 3t + 2t ln t
D) y = 3t + 2 ln t
E) y = 3t - t ln t
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Deck 19: Ordinary Differential Equations
1
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + cos(x - y) = sin x.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above + cos(x - y) = sin x.

A) 2nd order; linear
B) 2nd order; nonlinear
C) 1st order; nonlinear
D) 1st order; linear
E) None of the above
2nd order; nonlinear
2
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   +   y = sin x</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above + <strong>State the order of the following differential equation and whether it is linear or nonlinear:   +   y = sin x</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above y = sin x

A) 1st order; nonlinear
B) 1st order; linear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
2nd order; linear
3
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   - x   = 0.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above - x <strong>State the order of the following differential equation and whether it is linear or nonlinear:   - x   = 0.</strong> A) 2nd order; linear B) 2nd order; nonlinear C) 1st order; nonlinear D) 1st order; linear E) None of the above = 0.

A) 2nd order; linear
B) 2nd order; nonlinear
C) 1st order; nonlinear
D) 1st order; linear
E) None of the above
1st order; nonlinear
4
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   = 3x.</strong> A) 1st order; linear B) 1st order; nonlinear C) 6th order; linear D) 6th order; nonlinear E) None of the above = 3x.

A) 1st order; linear
B) 1st order; nonlinear
C) 6th order; linear
D) 6th order; nonlinear
E) None of the above
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5
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   =   + 2.</strong> A) nth order; linear B) nth order; nonlinear C) 1st order; linear D) 1st order; nonlinear E) None of the above = <strong>State the order of the following differential equation and whether it is linear or nonlinear:   =   + 2.</strong> A) nth order; linear B) nth order; nonlinear C) 1st order; linear D) 1st order; nonlinear E) None of the above + 2.

A) nth order; linear
B) nth order; nonlinear
C) 1st order; linear
D) 1st order; nonlinear
E) None of the above
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6
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + y =  </strong> A) 2nd order; linear B) 2nd order; nonlinear C) 3/2 order; nonlinear D) 3/2 order; linear E) None of the above + y = <strong>State the order of the following differential equation and whether it is linear or nonlinear:   + y =  </strong> A) 2nd order; linear B) 2nd order; nonlinear C) 3/2 order; nonlinear D) 3/2 order; linear E) None of the above

A) 2nd order; linear
B) 2nd order; nonlinear
C) 3/2 order; nonlinear
D) 3/2 order; linear
E) None of the above
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7
Find two values of r such that y = <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 is a solution of <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 - 9x <strong>Find two values of r such that y =   is a solution of     - 9x   - 24y = 0, x > 0.</strong> A) r = 6, 4 B) r = -8, 3 C) r = 12, -2 D) r = -12, 2 E) r = -6, -4 - 24y = 0, x > 0.

A) r = 6, 4
B) r = -8, 3
C) r = 12, -2
D) r = -12, 2
E) r = -6, -4
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8
State the order of the following differential equation and whether it is linear or nonlinear:y <strong>State the order of the following differential equation and whether it is linear or nonlinear:y   = 1.</strong> A) 1st order; linear B) 1st order; nonlinear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above = 1.

A) 1st order; linear
B) 1st order; nonlinear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
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9
State the order of the following differential equation and whether it is linear or nonlinear: <strong>State the order of the following differential equation and whether it is linear or nonlinear:   = xy.</strong> A) 1st order; nonlinear B) 1st order; linear C) 2nd order; nonlinear D) 2nd order; linear E) None of the above = xy.

A) 1st order; nonlinear
B) 1st order; linear
C) 2nd order; nonlinear
D) 2nd order; linear
E) None of the above
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10
Specify the interval where y = ln x is a solution of the differential equation x  <strong>Specify the interval where y = ln x is a solution of the differential equation x   +   = 0.</strong> A) (- \infty , 0) B) (-1, 1) C) (- \infty ,  \infty ) D) (0, \infty ) E) None of the above  +  <strong>Specify the interval where y = ln x is a solution of the differential equation x   +   = 0.</strong> A) (- \infty , 0) B) (-1, 1) C) (- \infty ,  \infty ) D) (0, \infty ) E) None of the above  = 0.

A) (- ∞\infty , 0)
B) (-1, 1)
C) (- ∞\infty , ∞\infty )
D) (0, ∞\infty )
E) None of the above
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11
Solve the initial-value problem <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)   + 4y = 10, y(0) = 200.

A) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)
B) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)
C) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)
D) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)
E) <strong>Solve the initial-value problem   + 4y = 10, y(0) = 200.</strong> A)   B)   C)   D)   E)
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12
Solve the differential equation <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   = 6x <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C   .

A) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C
B) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C
C) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C
D) x = C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C
E) x= C <strong>Solve the differential equation   = 6x   .</strong> A) x = C   B) x = C   C) x = C   D) x = C   E) x= C
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13
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 = 3 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 , y(0) = 0.

A) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 - 12
B) 9 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 - 36
C) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 - <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12
D) - <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 + 12
E) <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 <strong>Find the solution of the initial-value problem   = 3   , y(0) = 0.</strong> A)     - 12 B) 9   - 36 C)     -   D) -     + 12 E)     + 12 + 12
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14
Determine the solution of the differential equation <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   = (1 - 2x) <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =   that satisfies the condition <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =

A) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =
B) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =
C) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =
D) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =
E) y = <strong>Determine the solution of the differential equation   = (1 - 2x)   that satisfies the condition  </strong> A) y =   B) y =   C) y =   D) y =   E) y =
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15
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   + 3tx = 2t.

A) x = -1 + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C
B) x = <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C
C) x = 2 + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C
D) x = <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C
E) x = - <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C   + C <strong>Find the general solution of the differential equation   + 3tx = 2t.</strong> A) x = -1 + C   B) x =   + C   C) x = 2 + C   D) x =   + C   E) x = -   + C
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16
Find the general solution of the differential equation <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C

A) x = -2 <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C
B) x = 2 <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C
C) x = - <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C
D) x = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C
E) x = <strong>Find the general solution of the differential equation     =  </strong> A) x = -2   B) x = 2   C) x = -   D) x =   E) x =   + C + C
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17
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =   , x(0) = 4.

A) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =
B) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =
C) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =
D) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =
E) x = <strong>Find the solution of the initial-value problem   =   , x(0) = 4.</strong> A) x =   B) x =   C) x =   D) x =   E) x =
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18
Find the solution of the initial-value problem <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) = <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) , x(0) = a.

A) x = -ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) )
B) x = ln(1 + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) )
C) x = -ln(1 + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) )
D) x = ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) )
E) x = ln(1 - <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) + <strong>Find the solution of the initial-value problem   =   , x(0) = a.</strong> A) x = -ln(1 -   -   ) B) x = ln(1 +   -   ) C) x = -ln(1 +   -   ) D) x = ln(1 -   -   ) E) x = ln(1 -   +   ) )
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19
Solve the initial-value problem <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   = - <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =   , y(0) = 1.

A) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =
B) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =
C) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =
D) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =
E) y(x) = <strong>Solve the initial-value problem   = -   , y(0) = 1.</strong> A) y(x) =   B) y(x) =   C) y(x) =   D) y(x) =   E) y(x) =
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20
Find an integrating factor of the form μ(y) for the differential equation Find an integrating factor of the form μ(y) for the differential equation   and hence find its general solution. and hence find its general solution.
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21
Find the function satisfying <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x) = x <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) , F(0) = 1.

A) F(x) = -1 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x + 1)
B) F(x) = 1 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x - 1)
C) F(x) = 2 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x + 1)
D) F(x) = 2 + <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x - 1)
E) F(x) = 3 - <strong>Find the function satisfying   (x) = x   , F(0) = 1.</strong> A) F(x) = -1 -   (x + 1) B) F(x) = 1 -   (x - 1) C) F(x) = 2 -   (x + 1) D) F(x) = 2 +   (x - 1) E) F(x) = 3 -   (x + 1) (x + 1)
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22
Find the solution of the differential equation <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 = 12 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - 2x + 1 that satisfies y(1) = 3.

A) y = <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - 2
B) 8x <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 + x + C
C) 8 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 + x
D) 8x <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 + x - 5
E) 8 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 - <strong>Find the solution of the differential equation   = 12   - 2x + 1 that satisfies y(1) = 3.</strong> A) y =   - 2 B) 8x   -   + x + C C) 8   -   + x D) 8x   -   + x - 5 E) 8     -   + x + 5 + x + 5
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23
Solve the initial-value problem x Solve the initial-value problem x   = y (1 + ln(y) - ln(x)), y(1) =   . = y (1 + ln(y) - ln(x)), y(1) = Solve the initial-value problem x   = y (1 + ln(y) - ln(x)), y(1) =   . .
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24
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =   .

A) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =
B) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =
C) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =
D) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =
E) y = <strong>Find the general solution of the differential equation   =   .</strong> A) y =   B) y =   C) y =   D) y =   E) y =
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25
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   = -9 <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)   .

A) <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)
B) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)
C) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)
D) - <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)
E) <strong>Find the general solution of the differential equation   = -9     .</strong> A)   B) -   C) -   D) -   E)
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26
The nonexact differential equation M (t, x)) dt + N(t, x) dx = 0 has an integration factor that depends only upon x, if the quantity The nonexact differential equation M (t, x)) dt + N(t, x) dx = 0 has an integration factor that depends only upon x, if the quantity   is independent of t. is independent of t.
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27
Given the differential equation (7 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 + k <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 + 19y) dx + (19x + 2 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 + 23 <strong>Given the differential equation (7   + k     + 19y) dx + (19x + 2     + 23   )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.</strong> A) k = 10, m = -3, n = -15 B) k = -26, m = 3, n = 13 C) k = -6, m = -5, n = 15 D) k = -10, m = -3, n = 15 E) k = 26, m = 3, n = -13 )dy = 0, find the constant real numbers k, m, and n so that the differential equation is exact.

A) k = 10, m = -3, n = -15
B) k = -26, m = 3, n = 13
C) k = -6, m = -5, n = 15
D) k = -10, m = -3, n = 15
E) k = 26, m = 3, n = -13
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28
Find all solutions to <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C = 1 + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C .

A) y - <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C (y) = t + C
B) y - <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C (y) = 2t + C
C) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C (y) = t + C
D) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C (y) = 2t + C
E) y + <strong>Find all solutions to   = 1 +   .</strong> A) y -   (y) = t + C B) y -   (y) = 2t + C C) y +   (y) = t + C D) y +   (y) = 2t + C E) y +   (y) = 2t + C (y) = 2t + C
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29
Solve the following initial-value problem: <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +   = 9.8 - 0.196v, v(0) = 48.

A) v = 50 - <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +
B) v = 50 - 2 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +
C) v = 50 + 2 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +
D) v = 100 - 4 <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +
E) v = 50 + <strong>Solve the following initial-value problem:   = 9.8 - 0.196v, v(0) = 48.</strong> A) v = 50 -   B) v = 50 - 2   C) v = 50 + 2   D) v = 100 - 4   E) v = 50 +
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30
A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s = -k <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec.
(a) What is the value of k?
(b) When will the boat slow to 5 ft/sec?

A) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s (b) 70 s
B) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s (b) 700 s
C) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s (b) 140 s
D) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s (b) 100 s
E) (a) <strong>A motorboat is travelling with a velocity of 40 ft/sec when its motor shuts off at time t = 0. Thereafter, its deceleration due to water resistance is given by   = -k   , where k is a positive constant. After 10 seconds, the boat's velocity is measured to be 20 ft/sec. (a) What is the value of k? (b) When will the boat slow to 5 ft/sec?</strong> A) (a)   (b) 70 s B) (a)   (b) 700 s C) (a)   (b) 140 s D) (a)   (b) 100 s E) (a)   (b) 50 s (b) 50 s
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31
The change of dependent variable y = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) transforms the equation x <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) + y = x <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) cos(x) into

A) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x)
B) ln(v) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) = <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x)
C) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) + <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) = cos(x)
D) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) - <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) = cos(x)
E) <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) - <strong>The change of dependent variable y =   transforms the equation x   + y = x   cos(x) into</strong> A)   +   =   B) ln(v)   +   =   C)   +   = cos(x) D)   -   = cos(x) E)   -   = -cos(x) = -cos(x)
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32
Determine a multiplier (integrating factor) of the first order linear differential equation  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =

A) μ\mu (x) = -  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =
B) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =
C) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =
D) μ\mu (x) = -  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =
E) μ\mu (x) =  <strong>Determine a multiplier (integrating factor) of the first order linear differential equation  </strong> A)  \mu  (x) = -   B)  \mu (x) =   C)  \mu (x) =   D)  \mu (x) = -   E)  \mu (x) =
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33
Find a general solution of the first order linear differential equation <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C

A) y = - <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C
B) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C
C) y = - <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   - C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C
D) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   - C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C
E) y = <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C   + C <strong>Find a general solution of the first order linear differential equation  </strong> A) y = -     + C   B) y =     + C   C) y = -     - C   D) y =     - C   E) y =   + C
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34
Find a general solution to the first order linear differential equation <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +

A) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + C
B) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +
C) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +
D) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +
E) y(x) = <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +   + <strong>Find a general solution to the first order linear differential equation  </strong> A) y(x) =   +   + C B) y(x) =   + C   C) y(x) =   + C   D) y(x) =   + C   E) y(x) =   +
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35
Find a general solution to the first order linear differential equation <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C

A) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C
B) y = <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C
C) y = <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ln(1 - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C
D) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ln(1 - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C
E) y = - <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ln(1 + <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C   ) + C <strong>Find a general solution to the first order linear differential equation  </strong> A) y = -     ln(1 +   ) + C   B) y =     ln(1 +   ) + C   C) y =     ln(1 -   ) + C   D) y = -     ln(1 -   ) + C   E) y = -     ln(1 +   ) + C
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36
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -

A) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   + <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -
B) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -
C) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -
D) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   + <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -
E) y = C <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -   - <strong>Find the general solution of the differential equation  </strong> A) y = C   +   B) y = C   -   C) y = C   -   D) y = C   +   E) y = C   -
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37
Solve the initial-value problem <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =

A) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =
B) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =
C) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =
D) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =
E) x = <strong>Solve the initial-value problem  </strong> A) x =   B) x =   C) x =   D) x =   E) x =
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38
Solve the differential equation <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   + 2 <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =   .

A) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =
B) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =
C) y = x ln <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =
D) y = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =
E) y = <strong>Solve the differential equation   =   + 2   .</strong> A) y = x ln   B) y = x ln   C) y = x ln   D) y =   E) y =
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39
Solve the differential equation (3y + 8x <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C ) dx + (x + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C y) dy = 0 by finding an integrating factor depending on x.

A) 3xy + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C = C
B) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C y + 3 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C = C
C) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C y + 2 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C = C
D) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C y + 4 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C = C
E) <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C y + 2 <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C <strong>Solve the differential equation (3y + 8x   ) dx + (x + 4   y) dy = 0 by finding an integrating factor depending on x.</strong> A) 3xy + 4     = C B)   y + 3     = C C)   y + 2     = C D)   y + 4     = C E)   y + 2     = C = C
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A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?

A) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams = 2 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams , Q(0) = 60 (b) Q(t) = 200 - 340 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams (c) 200 grams
B) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams = 4 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams , Q(0) = 60 (b) Q(t) = 400 - 340 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams (c) 400 grams
C) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams = 400 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams , Q(0) = 60 (b) Q(t) = 40 - 34 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams (c) 40 grams
D) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams = 400 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams , Q(0) = 60 (b) Q(t) = 4 - 3.4 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams (c) 4 grams
E) (a) <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams = 200 - <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams , Q(0) = 60 (b) Q(t) = 20 - 34 <strong>A tank contains 200 litres of fluid in which 60 grams of salt is dissolved. A brine solution of 2 grams of salt per litre is pumped into the tank at a rate of 2 litres/minute. The well-stirred solution is then pumped out at the same rate.(a) Write the differential equation in terms of Q(t) and t and write the initial condition to model this problem. (Q(t) should represent the amount of salt in the tank at time t.)(b) Solve the equation in part (a).(c) How much salt will be present in the tank after a long period of time?</strong> A) (a)   = 2 -   , Q(0) = 60 (b) Q(t) = 200 - 340   (c) 200 grams B) (a)   = 4 -   , Q(0) = 60 (b) Q(t) = 400 - 340   (c) 400 grams C) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 40 - 34   (c) 40 grams D) (a)   = 400 -   , Q(0) = 60 (b) Q(t) = 4 - 3.4   (c) 4 grams E) (a)   = 200 -   , Q(0) = 60 (b) Q(t) = 20 - 34   (c) 20 grams (c) 20 grams
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Solve the following initial-value problem:cos(x)  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  + sin(x)y = 2  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  (x) sin(x) - 1, y(  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  ) = 3  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  , 0 ≤\le x ≤\le  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  .

A) y = -  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  cos(x)
B) y = +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  cos(x)
C) y = -  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  x - sin(x) + 7 cos(x)
D) y = +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  x - sin(x) + 7 cos(x)
E) y =  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  x - sin(x) +  <strong>Solve the following initial-value problem:cos(x)   + sin(x)y = 2   (x) sin(x) - 1, y(   ) = 3   , 0  \le x  \le    .</strong> A) y = -   x - sin(x) +   cos(x) B) y = +   x - sin(x) +   cos(x) C) y = -   x - sin(x) + 7 cos(x) D) y = +   x - sin(x) + 7 cos(x) E) y =   x - sin(x) +   cos(x)  cos(x)
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Use Euler's method to determine an approximate value of the solution of the initial-value problem <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978 <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978 using step size <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 45.6755 B) 43.6755 C) 34.4115 D) 24.5725 E) 64.8978

A) 45.6755
B) 43.6755
C) 34.4115
D) 24.5725
E) 64.8978
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43
Use Euler's method to determine an approximate value of the solution of the initial-value problem <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 using step size <strong>Use Euler's method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 55.5074 B) 57.7279 C) 60.0371 D) 62.4386 E) 64.8978 Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 55.5074
B) 57.7279
C) 60.0371
D) 62.4386
E) 64.8978
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44
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351 <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351 using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 110.4464 B) 120.6730 C) 115.2341 D) 112.3558 E) 145.2351

A) 110.4464
B) 120.6730
C) 115.2341
D) 112.3558
E) 145.2351
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45
Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123 <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123 on the interval <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5387 B) 0.5633 C) 0.5732 D) 0.5700 E) 0.5123

A) 0.5387
B) 0.5633
C) 0.5732
D) 0.5700
E) 0.5123
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46
Use the improved Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978 <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978 using step size <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 27.3480 B) 40.9407 C) 59.9382 D) 88.7036 E) 64.8978

A) 27.3480
B) 40.9407
C) 59.9382
D) 88.7036
E) 64.8978
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47
Use the improved Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 using step size <strong>Use the improved Euler method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 62.2892 C) 64.8307 D) 67.2433 E) 64.8978 Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 59.8473
B) 62.2892
C) 64.8307
D) 67.2433
E) 64.8978
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48
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621 <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621 using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 633.8378 B) 316.6792 C) 156.6864 D) 76.6012 E) 164.3621

A) 633.8378
B) 316.6792
C) 156.6864
D) 76.6012
E) 164.3621
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49
Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745 <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745 on the interval <strong>Use Euler's method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.4662 B) 0.5215 C) 0.5272 D) 0.4978 E) 0.9745

A) 0.4662
B) 0.5215
C) 0.5272
D) 0.4978
E) 0.9745
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50
Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576 <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576 using step size <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 144.3001 B) 96.4752 C) 64.8581 D) 43.4739 E) 72.8576

A) 144.3001
B) 96.4752
C) 64.8581
D) 43.4739
E) 72.8576
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51
Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 using step size <strong>Use the Runge-Kutta method to determine an approximate value of the solution of the initial-value problem     using step size   Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.</strong> A) 59.8473 B) 67.5463 C) 64.8978 D) 70.3027 E) 71.6654 Use formula replication in a computer spreadsheet to carry out the calculations as you now need 100 iterations of the formula.

A) 59.8473
B) 67.5463
C) 64.8978
D) 70.3027
E) 71.6654
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52
Use the Euler method to determine an approximate value of the solution of the initial-value problem <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736 <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736 using step size <strong>Use the Euler method to determine an approximate value of the solution of the initial-value problem     using step size  </strong> A) 154.9004 B) 151.8943 C) 146.0963 D) 121.3222 E) 138.5736

A) 154.9004
B) 151.8943
C) 146.0963
D) 121.3222
E) 138.5736
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53
Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582 <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582 on the interval <strong>Use the Runge-Kutta method with step size h = 0.1 to approximate the solution of the initial-value problem     on the interval  </strong> A) 0.5321 B) 0.5380 C) 0.5407 D) 0.5487 E) 0.5582

A) 0.5321
B) 0.5380
C) 0.5407
D) 0.5487
E) 0.5582
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54
Solve the integral equation y(x) = 1 + <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   dt by reinterpreting it as an initial-value problem.

A) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
B) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
C) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
D) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
E) y = <strong>Solve the integral equation y(x) = 1 +   dt by reinterpreting it as an initial-value problem.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
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55
Solve the initial-value problem <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 + 2 = 0, <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 (2) = 3, y(-1) = -4.

A) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 + 7x + 12
B) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 + 7x - 12
C) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 + x - 2
D) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 + 7x + 4
E) y = - <strong>Solve the initial-value problem   + 2 = 0,   (2) = 3, y(-1) = -4.</strong> A) y = -   + 7x + 12 B) y = -   + 7x - 12 C) y = -   + x - 2 D) y = -   + 7x + 4 E) y = -   - x - 4 - x - 4
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56
Solve the initial-value problem x <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   + 3 <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   = 0, <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +   (1) = 2, y(1) = 3.

A) y = 4 - <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +
B) y = 2 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +
C) y = 5 - <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +
D) y = 1 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +
E) y = 4 + <strong>Solve the initial-value problem x   + 3   = 0,   (1) = 2, y(1) = 3.</strong> A) y = 4 -   B) y = 2 +   C) y = 5 -   D) y = 1 +   E) y = 4 +
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57
Solve the initial-value problem <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above = 1 + <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above , <strong>Solve the initial-value problem   = 1 +   ,   (0) = 1, y(0) = 0.</strong> A) y = -ln(cos(x) - sin(x)) B) y = ln(cos(x) - sin(x)) C) y = -ln(sin(x) - cos(x)) D) y = ln(sin(x) - cos(x)) E) None of the above (0) = 1, y(0) = 0.

A) y = -ln(cos(x) - sin(x))
B) y = ln(cos(x) - sin(x))
C) y = -ln(sin(x) - cos(x))
D) y = ln(sin(x) - cos(x))
E) None of the above
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58
Solve the initial-value problem <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   - 2y <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   = 0, <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =   (3) = 1, y(3) = 1.

A) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
B) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
C) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
D) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
E) y = <strong>Solve the initial-value problem   - 2y   = 0,   (3) = 1, y(3) = 1.</strong> A) y =   B) y =   C) y =   D) y =   E) y =
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59
Given that y = x is a solution of the differential equation <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 , find the solution of the equation that satisfies y(1) = 3 and <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2 (1) = 5.

A) y = 3x + 2ln(x)
B) y = x + <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2
C) y = 3x + 2xln(x)
D) y = x + <strong>Given that y = x is a solution of the differential equation   , find the solution of the equation that satisfies y(1) = 3 and   (1) = 5.</strong> A) y = 3x + 2ln(x) B) y = x +   C) y = 3x + 2xln(x) D) y = x +   E) y = 5x -2
E) y = 5x -2
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60
Verify that y = <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   is a solution of the equation <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   , and find the general solution of this equation

A) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   + B <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx
B) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   + B <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   ln x
C) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   + Bx
D) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   + B
E) y = A <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx   + Bx <strong>Verify that y =   is a solution of the equation   , and find the general solution of this equation</strong> A) y = A   + B   B) y = A   + B   ln x C) y = A   + Bx D) y = A   + B E) y = A   + Bx
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61
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   - <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + 12y = 0.

A) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx
B) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx
C) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx
D) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + B <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx
E) y = A <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx   + Bx <strong>Find the general solution of the differential equation   -   + 12y = 0.</strong> A) y = A   + B   B) y = A   + B   C) y = A   + B   D) y = A   + B   E) y = A   + Bx
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   + 6 <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   + 9y = 0.

A) y = A <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   + B <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx
B) y = (A + Bx) <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx
C) y = (A + Bx) <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx
D) y = Ax <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   + Bx <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx
E) y = A <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx   + Bx <strong>Find the general solution of the differential equation   + 6   + 9y = 0.</strong> A) y = A   + B   B) y = (A + Bx)   C) y = (A + Bx)   D) y = Ax   + Bx   E) y = A   + Bx
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   + <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]   + 17y = 0.

A) y = [Acos(4x) + Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]
B) y = [Acos(4x) - Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]
C) y = [Acos(4x) + Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]
D) y = [Acos(4x) - Bsin(4x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]
E) y = [Acos(x) + Bsin(x)] <strong>Find the general solution of the differential equation   +   + 17y = 0.</strong> A) y = [Acos(4x) + Bsin(4x)]   B) y = [Acos(4x) - Bsin(4x)]   C) y = [Acos(4x) + Bsin(4x)]   D) y = [Acos(4x) - Bsin(4x)]   E) y = [Acos(x) + Bsin(x)]
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Find the general solution of the differential equation Find the general solution of the differential equation   y= 0, where D stands for the differential operator   . y= 0, where D stands for the differential operator Find the general solution of the differential equation   y= 0, where D stands for the differential operator   . .
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) - 10 <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) + 74y = 0.

A) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) sin(7t)
B) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) sin(7t)
C) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) cos(5t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) sin(5t)
D) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) cos(5t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) sin(5t)
E) y = <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) cos(7t) + <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) <strong>Find the general solution of the differential equation   - 10   + 74y = 0.</strong> A) y =     cos(7t) +     sin(7t) B) y =     cos(7t) +     sin(7t) C) y =     cos(5t) +     sin(5t) D) y =     cos(5t) +     sin(5t) E) y =     cos(7t) +     sin(7t) sin(7t)
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + 13 <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + 3y = 0.

A) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +
B) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     - <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +
C) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +
D) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +
E) y = <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     + <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +     <strong>Find the general solution of the differential equation   + 13   + 3y = 0.</strong> A) y =     +     B) y =     -     C) y =     +     D) y =     +     E) y =     +
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Solve the initial-value problem 12 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   - <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   -6y = 0; y(0) = 2, <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   (0) = 10.

A) y(t) = 6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   - 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8
B) y(t) = 4 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   - 2 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8
C) y(t) = -6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   + 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8
D) y(t) = -4 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   + 6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8
E) y(t) = -6 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8   + 8 <strong>Solve the initial-value problem 12   -   -6y = 0; y(0) = 2,   (0) = 10.</strong> A) y(t) = 6   - 8   B) y(t) = 4   - 2   C) y(t) = -6   + 8   D) y(t) = -4   + 6   E) y(t) = -6   + 8
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Solve the initial-value problem <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t + 2y = 0; y(0) = 4, <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t (0) = -2.

A) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t cos t - 6 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t sin t
B) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t cos t - 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t sin t
C) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t cos t + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t sin t
D) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t cos t + 6 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t sin t
E) y(t) = 4 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t cos t + 2 <strong>Solve the initial-value problem   + 2   + 2y = 0; y(0) = 4,   (0) = -2.</strong> A) y(t) = 4   cos t - 6   sin t B) y(t) = 4   cos t - 2   sin t C) y(t) = 4   cos t + 2   sin t D) y(t) = 4   cos t + 6   sin t E) y(t) = 4   cos t + 2   sin t sin t
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Solve the initial-value problem <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   + 8 <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   + 16y = 0; y(0) = 3, <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)   (0) = 1.

A) y = (13t + 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)
B) y = (13t - 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)
C) y = (13t + 3) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)
D) y = (7t + 1) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)
E) y = (7t - 1) <strong>Solve the initial-value problem   + 8   + 16y = 0; y(0) = 3,   (0) = 1.</strong> A) y = (13t + 3)   B) y = (13t - 3)   C) y = (13t + 3)   D) y = (7t + 1)   E) y = (7t - 1)
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Solve the initial-value problem <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     + 4 <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     = 0, y(1)= 1, <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     (1) = 2.

A) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -
B) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -
C) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -
D) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -
E) y = <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     - <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -     <strong>Solve the initial-value problem   + 4   = 0, y(1)= 1,   (1) = 2.</strong> A) y =   -     B) y =   -     C) y =   -     D) y =   -       E) y =   -
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Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 t <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 .

A) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 - 100y = 0
B) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 100y = 0
C) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 - 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 100y = 0
D) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 - 20 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 - 100y = 0
E) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 10 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y =     +   t   .</strong> A)   + 20   - 100y = 0 B)   + 20   + 100y = 0 C)   - 20   + 100y = 0 D)   - 20   - 100y = 0 E)   + 10   + 100y = 0 + 100y = 0
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Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = . <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0

A) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 - 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 - y = 0
B) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 - y = 0
C) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 - 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + y = 0
D) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + 2y = 0
E) <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + 2 <strong>Find a homogeneous linear second-order differential equation with constant coefficient having general solution y = .    </strong> A)   - 2   - y = 0 B)   + 2   - y = 0 C)   - 2   + y = 0 D)   + 2   + 2y = 0 E)   + 2   + y = 0 + y = 0
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     - 2y = 0.

A) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp
B) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp
C) y = A exp(t) + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp
D) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp
E) y = A expt <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     + exp <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp     <strong>Find the general solution of the differential equation   - 2y = 0.</strong> A) y = A expt   + exp     B) y = A expt   + exp     C) y = A exp(t) + exp     D) y = A expt   + exp     E) y = A expt   + exp
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Find the general solution of the differential equation <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) - 16y = 0.

A) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + C cos(2t) + D sin(2t)
B) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + C cos(2t) + D sin(2t)
C) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + C cos(4t) + D sin(4t)
D) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + C <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) cos(2t) + D <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) sin(2t)
E) y = A <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + B <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) + C <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) cos(4t) + D <strong>Find the general solution of the differential equation   - 16y = 0.</strong> A) y = A   + B   + C cos(2t) + D sin(2t) B) y = A   + B   + C cos(2t) + D sin(2t) C) y = A   + B   + C cos(4t) + D sin(4t) D) y = A   + B   + C   cos(2t) + D   sin(2t) E) y = A   + B   + C   cos(4t) + D   sin(4t) sin(4t)
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75
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + 4 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + 6 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   +4 <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + y = 0.

A) y = <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D
B) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + Ct <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + Dt <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D
C) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + C <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + D <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D
D) y = <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D
E) y = A <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + B <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + C <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D   + D <strong>Find the general solution of the differential equation   + 4   + 6   +4   + y = 0.</strong> A) y =     B) y = A   + B   + Ct   + Dt   C) y = A   + B   + C   + D   D) y =     E) y = A   + B   + C   + D
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76
Find the general solution of the differential equation <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     + 4y = 0.

A) y = cos(2x) + sin(2x)
B) y = cos(-2x) + sin(-2x)
C) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =
D) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =
E) y = <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =     <strong>Find the general solution of the differential equation   + 4y = 0.</strong> A) y = cos(2x) + sin(2x) B) y = cos(-2x) + sin(-2x) C) y =     D) y =     E) y =
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77
If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) find the general solution of the DE.

A) y = A <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + (D + Et) cos(t) + (F + Gt) sin(t)
B) y = <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) (A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) ) + (D + Et) cos(t) + (F + Gt) sin(t)
C) y = A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + (D + Et) cos(t/2) + (F + Gt) sin(t/2)
D) y = A + Bt + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + (D + Et) cos(t) + (F + Gt) sin(t)
E) y = A <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + Bt <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + C <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) <strong>If the auxiliary equation of a certain linear, homogeneous, 7th order DE with constant coefficients factors to   find the general solution of the DE.</strong> A) y = A   + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) B) y =   (A + Bt + C   ) + (D + Et) cos(t) + (F + Gt) sin(t) C) y = A + Bt + C   + (D + Et) cos(t/2) + (F + Gt) sin(t/2) D) y = A + Bt + C   + (D + Et) cos(t) + (F + Gt) sin(t) E) y = A   + Bt   + C     + (D + Et) cos(t) + (F + Gt) sin(t) + (D + Et) cos(t) + (F + Gt) sin(t)
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78
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   )

A) y = Ax + B <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   )
B) y = x(A cos(ln x) + B sin(ln x))
C) A + Bx
D) A + B <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   )
E) y = x(A <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) + B x <strong>Find the general solution of the differential equation  </strong> A) y = Ax + B   B) y = x(A cos(ln x) + B sin(ln x)) C) A + Bx D) A + B   E) y = x(A   + B x   ) )
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79
Find the general solution of the differential equation <strong>Find the general solution of the differential equation  </strong> A) y = Ax cos(ln x) + Bx sin(ln x) B) y = A cos(2ln x) + B sin(2ln x) C) y = A cos(ln x) + B sin(ln x) D) y = Ax + Bx ln x E) y = Ax cos x + Bx sin x

A) y = Ax cos(ln x) + Bx sin(ln x)
B) y = A cos(2ln x) + B sin(2ln x)
C) y = A cos(ln x) + B sin(ln x)
D) y = Ax + Bx ln x
E) y = Ax cos x + Bx sin x
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80
Solve the initial-value problem <strong>Solve the initial-value problem  </strong> A) y = 3t - 2t ln t B) y = 4t - 3t ln t C) y = 3t + 2t ln t D) y = 3t + 2 ln t E) y = 3t - t ln t

A) y = 3t - 2t ln t
B) y = 4t - 3t ln t
C) y = 3t + 2t ln t
D) y = 3t + 2 ln t
E) y = 3t - t ln t
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