Deck 15: Chi-Square Tests

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Question
In a chi-square test of a 5 × 5 contingency table at α = .05,the critical value is 37.65.
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Question
The chi-square test can only be used to assess independence between two variables.
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The chi-square test is unreliable when there are any cells with small observed frequency counts.
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The shape of the chi-square distribution depends only on its degrees of freedom.
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The chi-square test is based on the analysis of frequencies.
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In samples drawn from a population in which the row and column categories are independent,the value of the chi-square test statistic will be zero.
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The degrees of freedom in a 3 × 4 chi-square contingency table would equal 11.
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A large negative chi-square test statistic would indicate that the null hypothesis should be rejected.
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In a chi-square test for independence,expected frequencies must be integers (or rounded to the nearest integer).
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Observed frequencies in a chi-square goodness-of-fit test for normality may be less than 5 or even 0 in some cells,as long as the expected frequencies are large enough.
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A chi-square test for independence is called a distribution-free test since the test is based on categorical data rather than on populations that follow any particular distribution.
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Cochran's Rule requires observed frequencies of 5 or more in each cell of a contingency table.
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In a chi-square test for independence,observed and expected frequencies must sum across to the same row totals and down to the same column totals.
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A chi-square distribution is always skewed right.
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If two variables are independent,we would anticipate a chi-squaretest statistic close to zero.
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In a hypothesis test using chi-square,if the null hypothesis is true,the sample value of the sample chi-square test statistic will be exactly zero.
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The chi-square test for independence is a nonparametric test (no parameters are estimated).
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The null hypothesis for a chi-square test on a contingency table is that the variables are dependent.
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The null hypothesis for a chi-square contingency test of independence for two variables always assumes that the variables are independent.
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In a chi-square test for independence,observed frequencies must be at least 5 in every cell.
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An attraction of the Anderson-Darling test is that it is fairly easy to do without a computer.
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The Poisson goodness-of-fit test is inappropriate for continuous data.
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Goodness-of-fit tests using the ECDF (Empirical Cumulative Distribution Function)compare the actual cumulative frequencies with expected cumulative frequencies for each observation under the assumption that the data came from the hypothesized distribution.
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For a chi-square goodness-of-fit test for a uniform distribution with 5 categories,we would use the critical value for 4 degrees of freedom.
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When raw data are available,ECDF tests usually surpass the chi-square test in their ability to detect departures from the distribution specified in the null hypothesis.
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In a goodness-of-fit test,a linear probability plot suggests that the null hypothesis should be rejected.
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Probability plots are used to test the assumption of normality.
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ECDF tests have an advantage over the chi-square goodness-of-fit test on frequencies because an ECDF test treats observations individually.
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An attraction of the Kolmogorov-Smirnov test is that it is fairly easy to do without a computer.
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For a chi-square goodness-of-fit test for a normal distribution using 8 categories with estimated mean and standard deviation,we would use the critical value for 7 degrees of freedom.
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In an ECDF test for goodness-of-fit,the n observations are grouped into categories rather than being treated individually.
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In a chi-square goodness-of-fit test,we gain one degree of freedom if n increases by 1.
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For a chi-square goodness-of-fit test for a normal distribution using 7 categories with estimated mean and standard deviation,we would use the critical value for 4 degrees of freedom.
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In a chi-square goodness-of-fit test,we lose one degree of freedom for each parameter estimated.
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A probability plot usually allows outliers to be detected.
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In a chi-square goodness-of-fit test,a small p-value would indicate a good fit to the hypothesized distribution.
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For a chi-square goodness-of-fit test for a uniform distribution with 7 categories,we would use the critical value for 6 degrees of freedom.
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The Anderson-Darling test is used to test the assumption of normality.
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The Kolmogorov-Smirnov and Anderson-Darling tests are based on the ECDF (Empirical Cumulative Distribution Function).
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In a chi-square goodness-of-fit test,a sample of n observations has n - 1 degrees of freedom.
Question
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes.The results were: 0,3,3,2,1,0,1,0,0,1,1,1,2,1,0,1,0,1,2,1,1,2,1,0,1,2,0,1,0,1.For the Poisson goodness-of-fit test,what is the expected frequency of the data value X = 1?

A) Impossible to determine.
B) 11.04
C) 1.00
D) 2.47
Question
A proofreader checked 160 ads for grammatical errors.The distribution obtained is shown: <strong>A proofreader checked 160 ads for grammatical errors.The distribution obtained is shown:   At α = .01,what decision would we reach in a goodness-of-fit test to see whether this sample came from a uniform distribution?</strong> A) Reject the null and conclude the distribution is not uniform. B) Conclude that there is insufficient evidence to reject the null. C) No conclusion can be made due to small expected frequencies. D) No conclusion can be made due to inadequate sample size. <div style=padding-top: 35px> At α = .01,what decision would we reach in a goodness-of-fit test to see whether this sample came from a uniform distribution?

A) Reject the null and conclude the distribution is not uniform.
B) Conclude that there is insufficient evidence to reject the null.
C) No conclusion can be made due to small expected frequencies.
D) No conclusion can be made due to inadequate sample size.
Question
To determine how well an observed set of frequencies fits an expected set of frequencies from a Poisson distribution we must estimate:

A) no parameters.
B) one parameter (λ).
C) two parameters (μ,σ).
D) three parameters (μ,σ,n).
Question
A chi-square goodness of fit test for a normal distribution used 60 observations,and the mean and standard deviation were estimated from the sample.The test used seven categories.We would use how many degrees of freedom in looking up the critical value for the test?

A) 6
B) 4
C) 59
D) 57
Question
A chi-square goodness of fit test for a normal distribution used 40 observations,and the mean and standard deviation were estimated from the sample.The test used six categories.We would use how many degrees of freedom in looking up the critical value for the test?

A) 39
B) 37
C) 5
D) 3
Question
In a test for a uniform distribution with k categories,the expected frequency is n/k in each cell.
Question
An operations analyst counted the number of arrivals per minute at a bank ATM in each of 30 randomly chosen minutes.The results were: 0,3,3,2,1,0,1,0,0,1,1,1,2,1,0,1,0,1,2,1,1,2,1,0,1,2,0,1,0,1.Which goodness-of-fit test would you recommend?

A) Uniform.
B) Poisson.
C) Normal.
D) Binomial.
Question
A proofreader checked 160 ads for grammatical errors.The sample frequency distribution is shown: <strong>A proofreader checked 160 ads for grammatical errors.The sample frequency distribution is shown:   Using a goodness-of-fit test to determine whether this distribution is uniform would result in a chi-square test statistic of approximately:</strong> A) 55. B) 79. C) 85. <div style=padding-top: 35px> Using a goodness-of-fit test to determine whether this distribution is uniform would result in a chi-square test statistic of approximately:

A) 55.
B) 79.
C) 85.
Question
Which of these statements concerning a chi-square goodness-of-fit test is correct?

A) It is inapplicable to test for a normal distribution with open-ended top and bottom classes.
B) It is generally a better test than the chi-square test of independence.
C) There is no way to get the degrees of freedom since the right tail goes to infinity.
D) It can be used to test whether a sample follows a specified distribution.
Question
A chi-square test of independence is a one-tailed test.The reason is that:

A) we are testing whether the frequencies exceed their expected values.
B) we square the deviations so the test statistic lies at or above zero.
C) hypothesis tests are one-tailed tests when dealing with sample data.
D) the chi-square distribution is positively skewed.
Question
The critical value in a chi-square test for independence depends on:

A) the normality of the data.
B) the variance of the data.
C) the number of categories.
D) the expected frequencies.
Question
Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies: <strong>Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies:   Find the p-value for the chi-square test statistic for a hypothesis of independence.</strong> A) Less than .01 B) Between .01 and .025 C) Between .025 and .05 D) Greater than .05 <div style=padding-top: 35px> Find the p-value for the chi-square test statistic for a hypothesis of independence.

A) Less than .01
B) Between .01 and .025
C) Between .025 and .05
D) Greater than .05
Question
We sometimes combine two row or column categories in a chi-square test when:

A) observed frequencies are more than 5.
B) observed frequencies are less than 5.
C) expected frequencies are more than 5.
D) expected frequencies are less than 5.
Question
Which of these statements concerning a chi-square goodness-of-fit test is correct?

A) Data could be ratio or interval measurements.
B) Population must be normally distributed.
C) All the expected frequencies must be equal.
Question
If samples are drawn from a population that is normal,a goodness-of-fit test for normality could yield:

A) Type I error but not Type II error.
B) Type II error but not Type I error.
C) Either Type I error or Type II error.
D) Both Type I and Type II errors.
Question
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 2 B) 3 C) 4 D) 6 <div style=padding-top: 35px> For a chi-square test of independence,degrees of freedom would be:

A) 2
B) 3
C) 4
D) 6
Question
Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies: <strong>Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies:   Find the chi-square test statistic for a hypothesis of independence.</strong> A) 7.22 B) 4.17 C) 5.13 D) 6.08 <div style=padding-top: 35px> Find the chi-square test statistic for a hypothesis of independence.

A) 7.22
B) 4.17
C) 5.13
D) 6.08
Question
Which of the following is not a potential solution to the problem that arises when not all expected frequencies are 5 or more in a chi-square test for independence?

A) Combine some of the columns
B) Combine some of the rows
C) Increase the sample size
D) Add more rows or columns
Question
In a chi-square test of independence,the number of degrees of freedom equals the:

A) number of observations minus one.
B) number of categories minus one.
C) number of rows minus one times the number of columns minus one.
D) number of sample observations minus the missing observations.
Question
In order to apply the chi-square test of independence,we prefer to have:

A) at least 5 observed frequencies in each cell.
B) at least 5 expected observations in each cell.
C) at least 5 percent of the observations in each cell.
D) not more than 5 observations in each cell.
Question
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   Assuming independence,the expected frequency of SUVs in Jamestown is:</strong> A) 12. B) 21. C) 75. <div style=padding-top: 35px> Assuming independence,the expected frequency of SUVs in Jamestown is:

A) 12.
B) 21.
C) 75.
Question
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   What is the value of the test statistic?</strong> A) 306.25 B) 0.00 C) 54.44 D) 13.61 <div style=padding-top: 35px> What is the value of the test statistic?

A) 306.25
B) 0.00
C) 54.44
D) 13.61
Question
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Under the assumption of independence,the expected frequency in the upper left cell is:</strong> A) 15.09. B) 24.00. C) 19.72. D) 20.22. <div style=padding-top: 35px> Under the assumption of independence,the expected frequency in the upper left cell is:

A) 15.09.
B) 24.00.
C) 19.72.
D) 20.22.
Question
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 20. B) 12. C) 399. <div style=padding-top: 35px> For a chi-square test of independence,degrees of freedom would be:

A) 20.
B) 12.
C) 399.
Question
You test a hypothesis of independence of two variables.The number of observations is 500 and you have classified the data into a 4 by 4 contingency table.The test statistic has __________ degrees of freedom.

A) 16
B) 9
C) 499
D) 498
Question
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   For a chi-square test of independence,the critical value for α = .05 is:</strong> A) 5.991. B) 7.815. C) 9.488. D) 16.92. <div style=padding-top: 35px> For a chi-square test of independence,the critical value for α = .05 is:

A) 5.991.
B) 7.815.
C) 9.488.
D) 16.92.
Question
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   Assuming independence,the expected frequency of satisfied hourly employees is:</strong> A) 80. B) 90. C) 75. <div style=padding-top: 35px> Assuming independence,the expected frequency of satisfied hourly employees is:

A) 80.
B) 90.
C) 75.
Question
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   For a chi-square test of independence,the critical value for α = .01 is:</strong> A) 9.210. B) 4.605. C) 11.34. D) 16.81. <div style=padding-top: 35px> For a chi-square test of independence,the critical value for α = .01 is:

A) 9.210.
B) 4.605.
C) 11.34.
D) 16.81.
Question
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 2. B) 9. C) 4. <div style=padding-top: 35px> For a chi-square test of independence,degrees of freedom would be:

A) 2.
B) 9.
C) 4.
Question
Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey. <strong>Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey.   Degrees of freedom for this test (shaded cell below the table)would be:</strong> A) 6. B) 7. C) 799. D) <div style=padding-top: 35px> Degrees of freedom for this test (shaded cell below the table)would be:

A) 6.
B) 7.
C) 799.
D)
Question
You want to sell your house,and you decide to obtain an appraisal on it.Looking at past data you discover that actual prices obtained for houses and the appraisals given for them prior to their sale were as follows: <strong>You want to sell your house,and you decide to obtain an appraisal on it.Looking at past data you discover that actual prices obtained for houses and the appraisals given for them prior to their sale were as follows:   Based on these data we can say that:</strong> A) no conclusion is possible without knowing α. B) appraisal and actual price are not independent at α = .05. C) appraisal and actual price are independent at any α. D) the degrees of freedom are insufficient for a decision. <div style=padding-top: 35px> Based on these data we can say that:

A) no conclusion is possible without knowing α.
B) appraisal and actual price are not independent at α = .05.
C) appraisal and actual price are independent at any α.
D) the degrees of freedom are insufficient for a decision.
Question
Preferences for the type of diet drink from a random sample of 121 shoppers are in the table below.A researcher is interested in determining if there is a relationship between the type of diet drink preferred and the age of the shoppers. <strong>Preferences for the type of diet drink from a random sample of 121 shoppers are in the table below.A researcher is interested in determining if there is a relationship between the type of diet drink preferred and the age of the shoppers.   In performing a chi-square test of independence on these data,how many degrees of freedom will the test statistic have?</strong> A) 1 B) 2 C) 4 D) 6 <div style=padding-top: 35px> In performing a chi-square test of independence on these data,how many degrees of freedom will the test statistic have?

A) 1
B) 2
C) 4
D) 6
Question
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   For a chi-square test of independence,the critical value for α = .10 is:</strong> A) 10.64. B) 14.68. C) 28.41. D) 18.55. <div style=padding-top: 35px> For a chi-square test of independence,the critical value for α = .10 is:

A) 10.64.
B) 14.68.
C) 28.41.
D) 18.55.
Question
You want to test the hypothesis that the prime rate and inflation are independent.The following table of frequencies is prepared from a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table of frequencies is prepared from a random sample,collected in various countries and various time periods:   Based on an analysis of the data in this table,which conclusion can be made at α = .01?</strong> A) The prime rate and inflation rate are independent. B) The prime rate and inflation rate are not independent. C) Small observed frequencies in some cells suggest that no reliable conclusion can be made. D) Small expected frequencies in some cells suggest that no reliable conclusion can be made. <div style=padding-top: 35px> Based on an analysis of the data in this table,which conclusion can be made at α = .01?

A) The prime rate and inflation rate are independent.
B) The prime rate and inflation rate are not independent.
C) Small observed frequencies in some cells suggest that no reliable conclusion can be made.
D) Small expected frequencies in some cells suggest that no reliable conclusion can be made.
Question
Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey. <strong>Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey.   The appropriate conclusion would be:</strong> A) do not reject H<sub>0</sub>. B) reject H<sub>0</sub> at α = .10. C) reject H<sub>0</sub> at α = .05. D) reject H<sub>0</sub> at α = .01. <div style=padding-top: 35px> The appropriate conclusion would be:

A) do not reject H0.
B) reject H0 at α = .10.
C) reject H0 at α = .05.
D) reject H0 at α = .01.
Question
To carry out a chi-square goodness-of-fit test for normality you need at least:

A) 5 categories altogether.
B) 5 observations in each category.
C) 5 expected observations in each category.
D) 50 samples or more.
Question
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   Using α = .05,what is the critical value of the test statistic that you would use?</strong> A) 3.841 B) 12.59 C) 5.991 D) 7.815 <div style=padding-top: 35px> Using α = .05,what is the critical value of the test statistic that you would use?

A) 3.841
B) 12.59
C) 5.991
D) 7.815
Question
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Which statement is most nearly correct?</strong> A) The contingency table violates Cochran's Rule. B) Visual inspection of column frequencies suggests independence. C) At α = .05 we would easily reject the null hypothesis of independence. D) At α = .05 we cannot reject he null hypothesis of independence. <div style=padding-top: 35px> Which statement is most nearly correct?

A) The contingency table violates Cochran's Rule.
B) Visual inspection of column frequencies suggests independence.
C) At α = .05 we would easily reject the null hypothesis of independence.
D) At α = .05 we cannot reject he null hypothesis of independence.
Question
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Assuming independence,the expected frequency of very uncertain students with 60 credits or more is:</strong> A) 12.47. B) 2.00 C) 14.56. D) 11.09. <div style=padding-top: 35px> Assuming independence,the expected frequency of very uncertain students with 60 credits or more is:

A) 12.47.
B) 2.00
C) 14.56.
D) 11.09.
Question
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   The expected frequency for the shaded cell is:</strong> A) 22.5. B) 30. C) 40. D) 40.5. <div style=padding-top: 35px> The expected frequency for the shaded cell is:

A) 22.5.
B) 30.
C) 40.
D) 40.5.
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Deck 15: Chi-Square Tests
1
In a chi-square test of a 5 × 5 contingency table at α = .05,the critical value is 37.65.
False
2
The chi-square test can only be used to assess independence between two variables.
False
3
The chi-square test is unreliable when there are any cells with small observed frequency counts.
False
4
The shape of the chi-square distribution depends only on its degrees of freedom.
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5
The chi-square test is based on the analysis of frequencies.
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6
In samples drawn from a population in which the row and column categories are independent,the value of the chi-square test statistic will be zero.
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7
The degrees of freedom in a 3 × 4 chi-square contingency table would equal 11.
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8
A large negative chi-square test statistic would indicate that the null hypothesis should be rejected.
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9
In a chi-square test for independence,expected frequencies must be integers (or rounded to the nearest integer).
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10
Observed frequencies in a chi-square goodness-of-fit test for normality may be less than 5 or even 0 in some cells,as long as the expected frequencies are large enough.
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11
A chi-square test for independence is called a distribution-free test since the test is based on categorical data rather than on populations that follow any particular distribution.
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12
Cochran's Rule requires observed frequencies of 5 or more in each cell of a contingency table.
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13
In a chi-square test for independence,observed and expected frequencies must sum across to the same row totals and down to the same column totals.
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14
A chi-square distribution is always skewed right.
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15
If two variables are independent,we would anticipate a chi-squaretest statistic close to zero.
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16
In a hypothesis test using chi-square,if the null hypothesis is true,the sample value of the sample chi-square test statistic will be exactly zero.
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17
The chi-square test for independence is a nonparametric test (no parameters are estimated).
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18
The null hypothesis for a chi-square test on a contingency table is that the variables are dependent.
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19
The null hypothesis for a chi-square contingency test of independence for two variables always assumes that the variables are independent.
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20
In a chi-square test for independence,observed frequencies must be at least 5 in every cell.
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21
An attraction of the Anderson-Darling test is that it is fairly easy to do without a computer.
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22
The Poisson goodness-of-fit test is inappropriate for continuous data.
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23
Goodness-of-fit tests using the ECDF (Empirical Cumulative Distribution Function)compare the actual cumulative frequencies with expected cumulative frequencies for each observation under the assumption that the data came from the hypothesized distribution.
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24
For a chi-square goodness-of-fit test for a uniform distribution with 5 categories,we would use the critical value for 4 degrees of freedom.
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25
When raw data are available,ECDF tests usually surpass the chi-square test in their ability to detect departures from the distribution specified in the null hypothesis.
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26
In a goodness-of-fit test,a linear probability plot suggests that the null hypothesis should be rejected.
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27
Probability plots are used to test the assumption of normality.
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28
ECDF tests have an advantage over the chi-square goodness-of-fit test on frequencies because an ECDF test treats observations individually.
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29
An attraction of the Kolmogorov-Smirnov test is that it is fairly easy to do without a computer.
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30
For a chi-square goodness-of-fit test for a normal distribution using 8 categories with estimated mean and standard deviation,we would use the critical value for 7 degrees of freedom.
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31
In an ECDF test for goodness-of-fit,the n observations are grouped into categories rather than being treated individually.
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32
In a chi-square goodness-of-fit test,we gain one degree of freedom if n increases by 1.
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33
For a chi-square goodness-of-fit test for a normal distribution using 7 categories with estimated mean and standard deviation,we would use the critical value for 4 degrees of freedom.
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34
In a chi-square goodness-of-fit test,we lose one degree of freedom for each parameter estimated.
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35
A probability plot usually allows outliers to be detected.
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36
In a chi-square goodness-of-fit test,a small p-value would indicate a good fit to the hypothesized distribution.
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37
For a chi-square goodness-of-fit test for a uniform distribution with 7 categories,we would use the critical value for 6 degrees of freedom.
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38
The Anderson-Darling test is used to test the assumption of normality.
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39
The Kolmogorov-Smirnov and Anderson-Darling tests are based on the ECDF (Empirical Cumulative Distribution Function).
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40
In a chi-square goodness-of-fit test,a sample of n observations has n - 1 degrees of freedom.
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41
An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes.The results were: 0,3,3,2,1,0,1,0,0,1,1,1,2,1,0,1,0,1,2,1,1,2,1,0,1,2,0,1,0,1.For the Poisson goodness-of-fit test,what is the expected frequency of the data value X = 1?

A) Impossible to determine.
B) 11.04
C) 1.00
D) 2.47
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42
A proofreader checked 160 ads for grammatical errors.The distribution obtained is shown: <strong>A proofreader checked 160 ads for grammatical errors.The distribution obtained is shown:   At α = .01,what decision would we reach in a goodness-of-fit test to see whether this sample came from a uniform distribution?</strong> A) Reject the null and conclude the distribution is not uniform. B) Conclude that there is insufficient evidence to reject the null. C) No conclusion can be made due to small expected frequencies. D) No conclusion can be made due to inadequate sample size. At α = .01,what decision would we reach in a goodness-of-fit test to see whether this sample came from a uniform distribution?

A) Reject the null and conclude the distribution is not uniform.
B) Conclude that there is insufficient evidence to reject the null.
C) No conclusion can be made due to small expected frequencies.
D) No conclusion can be made due to inadequate sample size.
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43
To determine how well an observed set of frequencies fits an expected set of frequencies from a Poisson distribution we must estimate:

A) no parameters.
B) one parameter (λ).
C) two parameters (μ,σ).
D) three parameters (μ,σ,n).
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44
A chi-square goodness of fit test for a normal distribution used 60 observations,and the mean and standard deviation were estimated from the sample.The test used seven categories.We would use how many degrees of freedom in looking up the critical value for the test?

A) 6
B) 4
C) 59
D) 57
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45
A chi-square goodness of fit test for a normal distribution used 40 observations,and the mean and standard deviation were estimated from the sample.The test used six categories.We would use how many degrees of freedom in looking up the critical value for the test?

A) 39
B) 37
C) 5
D) 3
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46
In a test for a uniform distribution with k categories,the expected frequency is n/k in each cell.
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47
An operations analyst counted the number of arrivals per minute at a bank ATM in each of 30 randomly chosen minutes.The results were: 0,3,3,2,1,0,1,0,0,1,1,1,2,1,0,1,0,1,2,1,1,2,1,0,1,2,0,1,0,1.Which goodness-of-fit test would you recommend?

A) Uniform.
B) Poisson.
C) Normal.
D) Binomial.
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48
A proofreader checked 160 ads for grammatical errors.The sample frequency distribution is shown: <strong>A proofreader checked 160 ads for grammatical errors.The sample frequency distribution is shown:   Using a goodness-of-fit test to determine whether this distribution is uniform would result in a chi-square test statistic of approximately:</strong> A) 55. B) 79. C) 85. Using a goodness-of-fit test to determine whether this distribution is uniform would result in a chi-square test statistic of approximately:

A) 55.
B) 79.
C) 85.
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49
Which of these statements concerning a chi-square goodness-of-fit test is correct?

A) It is inapplicable to test for a normal distribution with open-ended top and bottom classes.
B) It is generally a better test than the chi-square test of independence.
C) There is no way to get the degrees of freedom since the right tail goes to infinity.
D) It can be used to test whether a sample follows a specified distribution.
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50
A chi-square test of independence is a one-tailed test.The reason is that:

A) we are testing whether the frequencies exceed their expected values.
B) we square the deviations so the test statistic lies at or above zero.
C) hypothesis tests are one-tailed tests when dealing with sample data.
D) the chi-square distribution is positively skewed.
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51
The critical value in a chi-square test for independence depends on:

A) the normality of the data.
B) the variance of the data.
C) the number of categories.
D) the expected frequencies.
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52
Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies: <strong>Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies:   Find the p-value for the chi-square test statistic for a hypothesis of independence.</strong> A) Less than .01 B) Between .01 and .025 C) Between .025 and .05 D) Greater than .05 Find the p-value for the chi-square test statistic for a hypothesis of independence.

A) Less than .01
B) Between .01 and .025
C) Between .025 and .05
D) Greater than .05
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53
We sometimes combine two row or column categories in a chi-square test when:

A) observed frequencies are more than 5.
B) observed frequencies are less than 5.
C) expected frequencies are more than 5.
D) expected frequencies are less than 5.
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54
Which of these statements concerning a chi-square goodness-of-fit test is correct?

A) Data could be ratio or interval measurements.
B) Population must be normally distributed.
C) All the expected frequencies must be equal.
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55
If samples are drawn from a population that is normal,a goodness-of-fit test for normality could yield:

A) Type I error but not Type II error.
B) Type II error but not Type I error.
C) Either Type I error or Type II error.
D) Both Type I and Type II errors.
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56
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 2 B) 3 C) 4 D) 6 For a chi-square test of independence,degrees of freedom would be:

A) 2
B) 3
C) 4
D) 6
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57
Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies: <strong>Kortholts that fail to meet certain precise specifications must be reworked on the next day until they are within the desired specifications.A sample of one day's output of kortholts from the Melodic Kortholt Company showed the following frequencies:   Find the chi-square test statistic for a hypothesis of independence.</strong> A) 7.22 B) 4.17 C) 5.13 D) 6.08 Find the chi-square test statistic for a hypothesis of independence.

A) 7.22
B) 4.17
C) 5.13
D) 6.08
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58
Which of the following is not a potential solution to the problem that arises when not all expected frequencies are 5 or more in a chi-square test for independence?

A) Combine some of the columns
B) Combine some of the rows
C) Increase the sample size
D) Add more rows or columns
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59
In a chi-square test of independence,the number of degrees of freedom equals the:

A) number of observations minus one.
B) number of categories minus one.
C) number of rows minus one times the number of columns minus one.
D) number of sample observations minus the missing observations.
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60
In order to apply the chi-square test of independence,we prefer to have:

A) at least 5 observed frequencies in each cell.
B) at least 5 expected observations in each cell.
C) at least 5 percent of the observations in each cell.
D) not more than 5 observations in each cell.
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61
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   Assuming independence,the expected frequency of SUVs in Jamestown is:</strong> A) 12. B) 21. C) 75. Assuming independence,the expected frequency of SUVs in Jamestown is:

A) 12.
B) 21.
C) 75.
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62
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   What is the value of the test statistic?</strong> A) 306.25 B) 0.00 C) 54.44 D) 13.61 What is the value of the test statistic?

A) 306.25
B) 0.00
C) 54.44
D) 13.61
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63
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Under the assumption of independence,the expected frequency in the upper left cell is:</strong> A) 15.09. B) 24.00. C) 19.72. D) 20.22. Under the assumption of independence,the expected frequency in the upper left cell is:

A) 15.09.
B) 24.00.
C) 19.72.
D) 20.22.
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64
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 20. B) 12. C) 399. For a chi-square test of independence,degrees of freedom would be:

A) 20.
B) 12.
C) 399.
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65
You test a hypothesis of independence of two variables.The number of observations is 500 and you have classified the data into a 4 by 4 contingency table.The test statistic has __________ degrees of freedom.

A) 16
B) 9
C) 499
D) 498
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66
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   For a chi-square test of independence,the critical value for α = .05 is:</strong> A) 5.991. B) 7.815. C) 9.488. D) 16.92. For a chi-square test of independence,the critical value for α = .05 is:

A) 5.991.
B) 7.815.
C) 9.488.
D) 16.92.
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67
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   Assuming independence,the expected frequency of satisfied hourly employees is:</strong> A) 80. B) 90. C) 75. Assuming independence,the expected frequency of satisfied hourly employees is:

A) 80.
B) 90.
C) 75.
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68
The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey. <strong>The table below is a tabulation of opinions of employees of Axolotl Corporation,who were sampled at random from pay records and asked to complete an anonymous job satisfaction survey.   For a chi-square test of independence,the critical value for α = .01 is:</strong> A) 9.210. B) 4.605. C) 11.34. D) 16.81. For a chi-square test of independence,the critical value for α = .01 is:

A) 9.210.
B) 4.605.
C) 11.34.
D) 16.81.
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69
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   For a chi-square test of independence,degrees of freedom would be:</strong> A) 2. B) 9. C) 4. For a chi-square test of independence,degrees of freedom would be:

A) 2.
B) 9.
C) 4.
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70
Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey. <strong>Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey.   Degrees of freedom for this test (shaded cell below the table)would be:</strong> A) 6. B) 7. C) 799. D) Degrees of freedom for this test (shaded cell below the table)would be:

A) 6.
B) 7.
C) 799.
D)
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71
You want to sell your house,and you decide to obtain an appraisal on it.Looking at past data you discover that actual prices obtained for houses and the appraisals given for them prior to their sale were as follows: <strong>You want to sell your house,and you decide to obtain an appraisal on it.Looking at past data you discover that actual prices obtained for houses and the appraisals given for them prior to their sale were as follows:   Based on these data we can say that:</strong> A) no conclusion is possible without knowing α. B) appraisal and actual price are not independent at α = .05. C) appraisal and actual price are independent at any α. D) the degrees of freedom are insufficient for a decision. Based on these data we can say that:

A) no conclusion is possible without knowing α.
B) appraisal and actual price are not independent at α = .05.
C) appraisal and actual price are independent at any α.
D) the degrees of freedom are insufficient for a decision.
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72
Preferences for the type of diet drink from a random sample of 121 shoppers are in the table below.A researcher is interested in determining if there is a relationship between the type of diet drink preferred and the age of the shoppers. <strong>Preferences for the type of diet drink from a random sample of 121 shoppers are in the table below.A researcher is interested in determining if there is a relationship between the type of diet drink preferred and the age of the shoppers.   In performing a chi-square test of independence on these data,how many degrees of freedom will the test statistic have?</strong> A) 1 B) 2 C) 4 D) 6 In performing a chi-square test of independence on these data,how many degrees of freedom will the test statistic have?

A) 1
B) 2
C) 4
D) 6
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73
As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls. <strong>As an independent project,a team of statistics students tabulated the types of vehicles that were parked in four different suburban shopping malls.   For a chi-square test of independence,the critical value for α = .10 is:</strong> A) 10.64. B) 14.68. C) 28.41. D) 18.55. For a chi-square test of independence,the critical value for α = .10 is:

A) 10.64.
B) 14.68.
C) 28.41.
D) 18.55.
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74
You want to test the hypothesis that the prime rate and inflation are independent.The following table of frequencies is prepared from a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table of frequencies is prepared from a random sample,collected in various countries and various time periods:   Based on an analysis of the data in this table,which conclusion can be made at α = .01?</strong> A) The prime rate and inflation rate are independent. B) The prime rate and inflation rate are not independent. C) Small observed frequencies in some cells suggest that no reliable conclusion can be made. D) Small expected frequencies in some cells suggest that no reliable conclusion can be made. Based on an analysis of the data in this table,which conclusion can be made at α = .01?

A) The prime rate and inflation rate are independent.
B) The prime rate and inflation rate are not independent.
C) Small observed frequencies in some cells suggest that no reliable conclusion can be made.
D) Small expected frequencies in some cells suggest that no reliable conclusion can be made.
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75
Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey. <strong>Employees of OxCo Mfg.were surveyed to evaluate the company's pension plan.The table below displays some of the results of the survey.   The appropriate conclusion would be:</strong> A) do not reject H<sub>0</sub>. B) reject H<sub>0</sub> at α = .10. C) reject H<sub>0</sub> at α = .05. D) reject H<sub>0</sub> at α = .01. The appropriate conclusion would be:

A) do not reject H0.
B) reject H0 at α = .10.
C) reject H0 at α = .05.
D) reject H0 at α = .01.
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76
To carry out a chi-square goodness-of-fit test for normality you need at least:

A) 5 categories altogether.
B) 5 observations in each category.
C) 5 expected observations in each category.
D) 50 samples or more.
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77
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   Using α = .05,what is the critical value of the test statistic that you would use?</strong> A) 3.841 B) 12.59 C) 5.991 D) 7.815 Using α = .05,what is the critical value of the test statistic that you would use?

A) 3.841
B) 12.59
C) 5.991
D) 7.815
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78
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Which statement is most nearly correct?</strong> A) The contingency table violates Cochran's Rule. B) Visual inspection of column frequencies suggests independence. C) At α = .05 we would easily reject the null hypothesis of independence. D) At α = .05 we cannot reject he null hypothesis of independence. Which statement is most nearly correct?

A) The contingency table violates Cochran's Rule.
B) Visual inspection of column frequencies suggests independence.
C) At α = .05 we would easily reject the null hypothesis of independence.
D) At α = .05 we cannot reject he null hypothesis of independence.
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79
Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below. <strong>Students in an introductory college economics class were asked how many credits they had earned in college,and how certain they were about their choice of major.Their replies are summarized below.   Assuming independence,the expected frequency of very uncertain students with 60 credits or more is:</strong> A) 12.47. B) 2.00 C) 14.56. D) 11.09. Assuming independence,the expected frequency of very uncertain students with 60 credits or more is:

A) 12.47.
B) 2.00
C) 14.56.
D) 11.09.
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80
You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods: <strong>You want to test the hypothesis that the prime rate and inflation are independent.The following table is prepared for the test on the basis of the results of a random sample,collected in various countries and various time periods:   The expected frequency for the shaded cell is:</strong> A) 22.5. B) 30. C) 40. D) 40.5. The expected frequency for the shaded cell is:

A) 22.5.
B) 30.
C) 40.
D) 40.5.
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