Exam 3: Linear Programming: Sensitivity Analysis and Interpretation of Solution

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When the cost of a resource is sunk, then the dual price can be interpreted as the

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Relevant costs should be reflected in the objective function, but sunk costs should not.

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The 100% Rule compares

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A section of output from The Management Scientist is shown here. A section of output from The Management Scientist is shown here.   What will happen to the solution if the objective function coefficient for variable 1 decreases by 20? What will happen to the solution if the objective function coefficient for variable 1 decreases by 20?

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If the range of feasibility for b1 is between 16 and 37, then if b1 = 22 the optimal solution will not change from the original optimal solution.

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To solve a linear programming problem with thousands of variables and constraints

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A negative dual price for a constraint in a minimization problem means

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The range of feasibility measures

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Which of the following is not a question answered by sensitivity analysis?

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A section of output from The Management Scientist is shown here. A section of output from The Management Scientist is shown here.   What will happen if the right-hand-side for constraint 2 increases by 200? What will happen if the right-hand-side for constraint 2 increases by 200?

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If the optimal value of a decision variable is zero and its reduced cost is zero, this indicates that alternative optimal solutions exist.

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The dual price measures, per unit increase in the right hand side of the constraint,

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Decreasing the objective function coefficient of a variable to its lower limit will create a revised problem that is unbounded.

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The reduced cost for a positive decision variable is 0.

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Classical sensitivity analysis provides no information about changes resulting from a change in the coefficient of a variable in a constraint.

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The amount by which an objective function coefficient can change before a different set of values for the decision variables becomes optimal is the

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The dual value on the nonnegativitiy constraint for a variable is that variable's

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If the dual price for the right-hand side of a \le constraint is zero, there is no upper limit on its range of feasibility.

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Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO    END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000      NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED:     END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000 Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO    END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000      NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED:     Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO    END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000      NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED:     NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED: Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO    END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000      NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED:     Eight of the entries have been deleted from the LINDO output that follows. Use what you know about linear programming to find values for the blanks. MIN 6 X1 + 7.5 X2 + 10 X3 SUBJECT TO    END LP OPTIMUM FOUND AT STEP 2 OBJECTIVE FUNCTION VALUE 1) 612.50000      NO. ITERATIONS= 2 RANGES IN WHICH THE BASIS IS UNCHANGED:

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If the range of feasibility indicates that the original amount of a resource, which was 20, can increase by 5, then the amount of the resource can increase to 25.

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