Exam 7: Detecting Data Signals in Noise

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For signal sequence si=(5,2,3)s _ { i } = ( 5 , - 2,3 ) and noise SDσN=0.1S D \sigma _ { N } = 0.1 , the variance of VV equals σV2=___\sigma _ { V } { } ^ { 2 } =\_\_\_(x.xx)( x . x x )

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Es=si2=38.σN2=0.01.σv2=σN2Es=0.38E _ { s } = \sum s _ { i } ^ { 2 } = 38 . \quad \sigma _ { N } ^ { 2 } = 0.01 . \rightarrow \sigma _ { v } ^ { 2 } = \sigma _ { N } ^ { 2 } E _ { s } = 0.38

A processor is matched to signal si = (5,-2, 3).Compute V and the determined binary data value br when Xi = (-3, 1, 6) is observed.

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V=ciXi=5(3)2(1)+3(6)=152+18=1.V>0>br=1V = \sum c _ { i } X _ { i } = 5 ( - 3 ) - 2 ( 1 ) + 3 ( 6 ) = - 15 - 2 + 18 = 1 . \quad V > 0 - > b _ { r } = 1

For signal sequence si=(5,2,3) and SNR =20 dB, the noise SD σN=____xx)\left. s _ { i } = ( 5 , - 2,3 ) \text { and SNR } = 20 \mathrm {~dB} \text {, the noise SD } \sigma _ { N } = \_\_\_\_ x x \right) \text {. }

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Es=si2=38.SNRdB=10log10Es/σN2=20Es/σN2=102.σN2=38/100=0.38σN=0.62E _ { s } = \sum s _ { i } ^ { 2 } = 38 . S N R _ { d B } = 10 \log _ { 10 } E _ { s } / \sigma _ { N } ^ { 2 } = 20 \rightarrow E _ { s } / \sigma _ { N } ^ { 2 } = 10 ^ { 2 } . \sigma _ { N } ^ { 2 } = 38 / 100 = 0.38 \rightarrow \sigma _ { N } = 0.62

A linear processor with coefficient set ci=(5,3,1)c _ { i } = ( 5,3,1 ) that observes the signal values Xi=(3,2,1)X _ { \mathrm { i } } = ( 3,2,1 ) produces output V equal to_______.

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For signal sequence si=(5,2,3)s _ { i } = ( 5 , - 2,3 ) the matched processor produces output value equal to V =_____.

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For signal sequence si=(5,2,3)\mathrm { s } _ { \mathrm { i } } = ( 5 , - 2,3 ) ) and noise SD σN=0.1\sigma _ { \mathrm { N } } = 0.1 , the SNR equals _____ (xx.x) dB.

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