Exam 14: Trigonometry With Any Angle

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Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). C = 56.0°, c = 151 m, b = 187 m Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). C = 56.0°, c = 151 m, b = 187 m

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Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 78.5°, b = 45.6 m, a = 14.1 m Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 78.5°, b = 45.6 m, a = 14.1 m

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Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 47.5°, b = 303 m, a = 265 m Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 47.5°, b = 303 m, a = 265 m

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=69.5\angle A = 69.5 °, B=75.6\angle B = 75.6 °, b = 234 ft  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 69.5  °,  \angle B = 75.6  °, b = 234 ft

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). B=74.6\angle B = 74.6 °, A=63.0\angle A = 63.0 °, b = 302 ft  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle B = 74.6  °,  \angle A = 63.0  °, b = 302 ft

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Find the period P, amplitude A, and phase shift S, and graph at least two periods of the equation.   y=5sin(12x+120)y = 5 \sin \left( \frac { 1 } { 2 } x + 120 ^ { \circ } \right)

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Find the value of tan 243.6° rounded to four significant digits.

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Find the period P and amplitude A and graph at least two periods of the equation. y=4cos43xy = 4 \cos \frac { 4 } { 3 } x

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Find the period P, amplitude A, and phase shift S, and graph at least two periods of the equation. y = 11 cos (5x + 150°)

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=68.0\angle A = 68.0 °, a = 23.5 m, b = 18.0 m  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 68.0  °, a = 23.5 m, b = 18.0 m

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Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 110.2°, a = 1,420 ft, b = 1,130 ft Solve the triangle given below. Do not round results during calculations. (For answers, round lengths to three significant digits and angles to the nearest tenth of a degree). A = 110.2°, a = 1,420 ft, b = 1,130 ft

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Solve each triangle using the labels as shown in the Illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=64.0\angle A = 64.0 °, a = 133 mi, c = 119 mi  Solve each triangle using the labels as shown in the Illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 64.0  °, a = 133 mi, c = 119 mi

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=19.6\angle A = 19.6 °, B=37.1\angle B = 37.1 °, c = 41.7 cm  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 19.6  °,  \angle B = 37.1  °, c = 41.7 cm

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). C=53.3\angle C = 53.3 °, c = 127 cm, b = 147 cm  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle C = 53.3  °, c = 127 cm, b = 147 cm

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Find the value of cos 170.5° rounded to four significant digits.

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Find the period P, amplitude A, and phase shift S, and graph at least two periods of the equation. y=8cos(14x+210)y = 8 \cos \left( \frac { 1 } { 4 } x + 210 ^ { \circ } \right)

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=42.0\angle A = 42.0 °, B=48.1\angle B = 48.1 °, a = 49.7 m  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 42.0  °,  \angle B = 48.1  °, a = 49.7 m

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Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree). A=119.0\angle A = 119.0 °, a = 5,640 m, b = 4,770 m  Solve the triangle using the labels as shown in the illustration (round lengths of sides to three significant digits and angles to the nearest tenth of a degree).  \angle A = 119.0  °, a = 5,640 m, b = 4,770 m

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Graph the equation for values of x between 0° and 360° in multiples of 30°. y = 5 sin x

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The maximum voltage in a simple generator is V. The changing voltage v as the coil rotates is given by v = V sin x. Graph this equation in multiples of 30° for one complete revolution of the coil for the given value of V. V = 42 Volts

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