Exam 6: Exponents and Polynomials
Exam 1: Some Basic Concepts of Arithmetic and Algebra255 Questions
Exam 2: The Real Numbers261 Questions
Exam 3: Equations, Inequalities and Problem Solving327 Questions
Exam 4: Formulas and Problem Solving233 Questions
Exam 5: Coordinate Geometry and Linear Systems396 Questions
Exam 6: Exponents and Polynomials390 Questions
Exam 7: Factoring, Solving Equations and Problem Solving302 Questions
Exam 8: A Transition From Elementary Algebra to Intermediate Algebra276 Questions
Exam 9: Rational Expressions277 Questions
Exam 10: Exponents and Radicals274 Questions
Exam 11: Quadratic Equations and Inequalities283 Questions
Exam 12: Coordinate Geometry: Lines, Parabolas, Circles, Ellipses and Hyperbolas165 Questions
Exam 13: Functions195 Questions
Exam 14: Exponential and Logarithmic Functions228 Questions
Exam 15: Systems of Equations: Matrices and Determinants228 Questions
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Find the indicated product by using the shortcut pattern for multiplying binomials. ( x + 3)( x + 9)
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Find the indicated product by applying the distributive property. ( x 9)( y 8)
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A square piece of cardboard is y = 15 inches long on each side. From each corner a square piece x inches on a side is cut out as shown. The flaps are then turned up to form an open box. Find a polynomial that represents the volume of the box. 

(Multiple Choice)
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Multiply the following. Enter your answer as where k , p , q are numbers and a , y are variables.
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Find the product. Assume that the variables in the exponents represent positive integers; for example, .
(Multiple Choice)
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Simplify the following algebraic expression and express your answer using positive exponents only.
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Simplify the following algebraic expression and express your answer using positive exponents only.
(Multiple Choice)
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Simplify the following algebraic expression and express your answer using positive exponents only.
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Perform the division and find the quotient. Answer does not include the remainder.
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Remove the parentheses by multiplying and then simplify by combining similar terms.
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