Exam 5: Circular Motion

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ACD\mathrm{A} C D has a diameter of 12.0 cm12.0 \mathrm{~cm} . If the CDC D is rotating with a constant period of 0.314 seconds, then the frequency of the rotational motion is

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A boy on a bicycle rides in a circle of radius r0r_{0} at speed v0v_{0} . If the boy rides at the same radius r0r_{0} , by what approximate factor must he change his speed in order to triple his radial acceleration?

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ACD\mathrm{A} C D has a diameter of 12.0 cm12.0 \mathrm{~cm} . If the CD\mathrm{CD} is rotating at a constant frequency of 3.18 Hz3.18 \mathrm{~Hz} , then the period of the rotational motion is

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.0rad/sec21.0 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm4.0 \mathrm{~cm} from the center at the time 2.0 seconds from the start?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.00rad/sec21.00 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the magnitude of the (total) acceleration of a point 4.00 cm4.00 \mathrm{~cm} from the center at the time 30.0 seconds from the start?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.0rad/sec21.0 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} for 15 seconds15 \mathrm{~seconds} and then slows to a stop in 12.0 second with a constant angular acceleration. What is the angular distance traveled by a point 4.0 cm4.0 \mathrm{~cm} from the center, at the time 2.0 seconds from the start?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.0rad/sec21.0 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the linear speed of a point 4.0 cm4.0 \mathrm{~cm} from the center at the time 2.0 seconds from the start?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.00rad/sec21.00 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the magnitude of the (total) acceleration of a point 4.00 cm4.00 \mathrm{~cm} from the center at the time 2.00 seconds from the start?

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The Crab Pulsar is a neutron star, rotating with a period of about 33.085 ms33.085 \mathrm{~ms} . It is estimated to have an equatorial radius of 15 km15 \mathrm{~km} , about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest 9.5×1010 s9.5 \times 10^{10} \mathrm{~s} in the future. What is the magnitude of the average angular acceleration in this situation?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.0rad/sec21.0 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the radial acceleration of a point 4.0 cm4.0 \mathrm{~cm} from the center at the time 25.0 seconds from the start?

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A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800 km800 \mathrm{~km} . The speed of the satellite is (ME=5.98×1024 kg,RE=6.37×106 m,G=6.67×1011\left(\mathrm{M}_{\mathrm{E}}=5.98 \times 10^{24} \mathrm{~kg}, \mathrm{R}_{\mathrm{E}}=6.37 \times 10^{6} \mathrm{~m}, \mathrm{G}=6.67 \times 10^{-11}\right. Nm2/kg2)\left.\mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{kg}^{2}\right)

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A CD has a diameter of 12.0 cm12.0 \mathrm{~cm} and is rotating at an angular velocity of 10.0rad/sec10.0 \mathrm{rad} / \mathrm{sec} . If the CD\mathrm{CD} has a constant angular acceleration of 0.5rad/sec2-0.5 \mathrm{rad} / \mathrm{sec}^{2} , then the angular velocity of the CD\mathrm{CD} after 3.0sec3.0 \mathrm{sec} is

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The Crab Pulsar is a neutron star, rotating with a period of about 33.085 ms33.085 \mathrm{~ms} . It is estimated to have an equatorial radius of 15 km15 \mathrm{~km} , about average for a neutron star. The pulsar is slowing in its rotation so that it is expected to come to rest 9.5×1010 s9.5 \times 1010 \mathrm{~s} in the future. Assuming it is slowing with a constant angular acceleration, what is the tangential acceleration of an object on the neutron star's equator?

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ACD\mathrm{A} C D has a diameter of 12.0 cm12.0 \mathrm{~cm} . If the CD\mathrm{CD} is rotating at a constant angular speed of 20.0 radians per second, then the period of the rotational motion is

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A boy on a bicycle rides in a circle of radius r0r_{0} at speed v0v_{0} . If the boy now rides at a radius equal to half the initial radius ror_{\mathrm{o}} , by what approximate factor must he change his speed in order to have the same radial acceleration?

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.00rad/sec21.00 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.00rad/sec5.00 \mathrm{rad} / \mathrm{sec} for 15.0 seconds15.0 \mathrm{~seconds} and then slows to a stop in 12.0 second with a constant angular acceleration. What is the angular distance traveled by a point 4.00 cm4.00 \mathrm{~cm} from the center, at the time 10.0 seconds from the start?

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An object is moving in a circular path of radius 4.00 m4.00 \mathrm{~m} . If the object moves through an angle of 1.2 radians, then the tangential distance traveled by the object is

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ACD\mathrm{A} C D has a diameter of 12.0 cm12.0 \mathrm{~cm} . If the CD\mathrm{CD} is rotating at a constant frequency of 6.00 rotations per second, then the angular speed is

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ACD\mathrm{A} C D has a diameter of 12.0 cm12.0 \mathrm{~cm} . If the CD\mathrm{CD} starts from rest and has a constant angular acceleration of 2.00 rad/sec2\mathrm{rad} / \mathrm{sec}^{2} , then the radial acceleration of a point 3.00 cm3.00 \mathrm{~cm} from the center of the CD after 3.00sec3.00 \mathrm{sec} is

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A CD with a diameter of 12.0 cm12.0 \mathrm{~cm} starts from rest and with a constant angular acceleration of 1.0rad/sec21.0 \mathrm{rad} / \mathrm{sec}^{2} acquires an angular velocity of 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} . The CD continues rotating at 5.0rad/sec5.0 \mathrm{rad} / \mathrm{sec} for 15.0 seconds and then slows to a stop in 12.0 second with a constant angular acceleration. What is the linear speed of a point 4.0 cm4.0 \mathrm{~cm} from the center at the time 10.0 seconds from the start?

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