Exam 5: Polynomials: Factoring

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Factor. - 9x418x3+8x29 x^{4}-18 x^{3}+8 x^{2}

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Factor using the ac-method. - 10y419y21510 y^{4}-19 y^{2}-15

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Factor. - 6x226x206 x^{2}-26 x-20

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Factor. - x20.9x+0.2x^{2}-0.9 x+0.2

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Solve the problem. -The length of a rectangular frame is 3 cm3 \mathrm{~cm} more than the width. The area inside the frame is 40 square cm\mathrm{cm} . Find the width of the frame.

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Factor using the ac-method. - 96x2+56xy+8y296 x^{2}+56 x y+8 y^{2}

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Solve by factoring and using the principle of zero products. - 2k213k7=02 k^{2}-13 k-7=0

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Factor. - y2+1.4y+0.49y^{2}+1.4 y+0.49

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Factor. - x2+8x48x^{2}+8 x-48

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Factor. - 3x(6x+5)2(6x+5)3 x(6 x+5)-2(6 x+5)

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Solve by factoring and using the principle of zero products. - x(x6)=16\mathrm{x}(\mathrm{x}-6)=16

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Determine whether the following is a difference of squares. - x24y2x^{2}-4 y^{2}

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Factor. - x2x54x^{2}-x-54

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Factor. - 20x223xy+6y220 x^{2}-23 x y+6 y^{2}

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Solve the problem. -Within a group of nn people, the number of possible handshakes, NN , is given by N=12(n2n)\mathrm{N}=\frac{1}{2}\left(\mathrm{n}^{2}-\mathrm{n}\right) . At a party, everybody shakes hands with every other person. If the total number of handshakes is 28 , how many people are at the party?

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