Exam 21: Developmental Genetics and Immunogenetics
Exam 1: Introduction to Genetics, Chromosomes and Cellular Reproduction11 Questions
Exam 2: Basic Principles of Heredity7 Questions
Exam 3: Sex Determination and Sex-Linked Characteristics9 Questions
Exam 4: Extensions and Modifications of Basic Principles13 Questions
Exam 5: Pedigree Analysis, Applications, and Genetic Testing9 Questions
Exam 6: Linkage, Recombination, and Eukaryotic Gene Mapping6 Questions
Exam 7: Bacterial and Viral Genetic Systems9 Questions
Exam 8: Chromosome Variation7 Questions
Exam 9: DNA: The Chemical Nature of the Gene9 Questions
Exam 10: Chromosome Structure and Transposable Elements12 Questions
Exam 11: DNA Replication and Recombination12 Questions
Exam 12: Transcription8 Questions
Exam 13: RNA Molecules and RNA Processing9 Questions
Exam 14: The Genetic Code and Translation9 Questions
Exam 15: Control of Gene Expression in Prokaryotes9 Questions
Exam 16: Control of Gene Expression in Eukaryotes6 Questions
Exam 17: Gene Mutations and DNA Repair9 Questions
Exam 18: Molecular Genetic Analysis and Biotechnology13 Questions
Exam 19: Genomics and Proteomics9 Questions
Exam 20: Organelle DNA6 Questions
Exam 21: Developmental Genetics and Immunogenetics7 Questions
Exam 22: Cancer Genetics7 Questions
Exam 23: Quantitative Genetics8 Questions
Exam 24: Population Genetics10 Questions
Exam 25: Evolutionary Genetics7 Questions
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The genes encoding the antibody chains are organized in segments, and germ-line DNA contains multiple versions of each segment. The many possible combinations of V, J, and D segments permit an immense variety of different antibodies to be generated. This diversity is augmented by the different combinations of light and heavy chains, the random addition and deletion of nucleotides at the junctions of the segments, and the high mutation rates in the immunoglobulin genes.
-How does somatic recombination differ from alternative splicing of RNA?
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Somatic recombination takes place through the rearrangement of DNA segments, and so each lymphocyte has a different sequence of nucleotides in its DNA. Alternative splicing (discussed in Chapter 14) takes place through the rearrangement of RNA sequences in pre-mRNA; there is no change in the DNA that encodes the pre-mRNA. The generation of antibody diversity requires both the somatic recombination of DNA sequences and the alternative splicing of the pre-mRNA sequences.
Homeotic genes help determine the identity of individual segments in Drosophila embryos by producing DNA-binding proteins that activate other genes. Each homeotic gene contains a consensus sequence called a homeobox, which encodes the DNA-binding domain.
-Mutations in homeotic genes often cause
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Correct Answer:
D
When the major axes of the fruit-fly embryo have been established, segmentation genes determine the number, orientation, and basic organization of the body segments.
-The correct sequence in which the segmentation genes act is:
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B
The ability to clone plants and animals from single specialized cells demonstrates that genes are not lost or permanently altered during development.
-Scientists have cloned some animals by injecting a nucleus from an early embryo into an enucleated egg cell. The resulting animals are genetically identical with the donor of the nucleus. Does this outcome prove that genetic material is not lost during evelopment? Why or why not?
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The major axes of development in early fruit-fly embryos are established as a result of initial differences in the distribution of specific mRNAs and proteins encoded by genes in the female parent (genetic maternal effect). These differences in distribution establish concentration gradients of morphogens, which cause different genes to be activated in different parts of the embryo.
-High concentration of which protein stimulates the development of anterior structures?
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Cells are capable of apoptosis (programmed cell death), a highly regulated process that depends on enzymes called caspases. Apoptosis plays an important role in animal development and is implicated in a number of diseases.
-How does cell death from apoptosis differ from cell death from necrosis?
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Plant homeotic genes control the development of floral structures in plants. The products of four classes of homeotic genes interact to determine the formation of the four whorls that constitute a complete flower.
-What types of flower structures would you expect to see in whorls 1 through 4 of a mutant plant that failed to produce both class A and class B gene products?
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