Exam 9: One-Sample Hypothesis Tests

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At α = .05, the critical value to test the hypotheses H0: π ≥ .40, H1: π < .40 would be:

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After testing a hypothesis regarding the mean, we decided not to reject H0. Thus, we are exposed to:

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A Type I error can only occur if you reject H0.

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When testing the hypothesis H0: μ = 100 with n = 100 and σ2 = 100, we find that the sample mean is 97. The test statistic is:

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A Type II error can only occur when you fail to reject H0.

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Which is not a step in hypothesis testing?

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A two-tailed hypothesis test for H0: μ = 15 at α = .10 is analogous to asking if a 90 percent confidence interval for μ contains 15.

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The decision rule is:

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After testing a hypothesis, we decided to reject the null hypothesis. Thus, we are exposed to:

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For a given level of significance (α), increasing the sample size will increase the probability of Type II error because there are more ways to make an incorrect decision.

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The height of the power curve shows the probability of accepting a true null hypothesis.

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A study over a 10-year period showed that a certain mammogram test had a 50 percent rate of false positives. This indicates that:

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Which of the following is not a valid null hypothesis?

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In hypothesis testing, we cannot prove a null hypothesis is true.

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If n = 25 and α = .05 in a right-tailed test of a mean with unknown σ, the critical value is:

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If a judge acquits every defendant, the judge will never commit a Type I error. (H0 is the hypothesis of innocence.)

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In a left-tailed test, a statistician got a z test statistic of -1.720. What is the p-value?

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Guidelines for the Jolly Blue Giant Health Insurance Company say that the average hospitalization for a triple hernia operation should not exceed 30 hours. A diligent auditor studied records of 16 randomly chosen triple hernia operations at Hackmore Hospital and found a mean hospital stay of 40 hours with a standard deviation of 20 hours. "Aha!" she cried, "the average stay exceeds the guideline." At α = .025, the critical value for a right-tailed test of her hypothesis is:

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For a sample of nine items, the critical value of Student's t for a left-tailed test of a mean at α = .05 is -1.860.

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For a given level of significance, the critical value of Student's t increases as n increases.

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