Exam 4: Probability and Probability Distributions

arrow
  • Select Tags
search iconSearch Question
flashcardsStudy Flashcards
  • Select Tags

The law of large numbers states that subjective probabilities can be estimated based on the long run relative frequencies of events

(True/False)
4.9/5
(39)

The relative frequency of an event is the number of times the event occurs out of the total number of times the random experiment is run.

(True/False)
4.8/5
(37)

If A and B are mutually exclusive events with P(A)= 0.30 and P(B)= 0.40,then the probability that either A or B occur is:

(Multiple Choice)
4.7/5
(40)

Two events A and B are said to be independent if P(A and B)= P(A)+ P(B)

(True/False)
4.8/5
(32)

Probabilities that cannot be estimated from long-run relative frequencies of events are

(Multiple Choice)
4.8/5
(34)

If A and B are independent events with P(A)= 0.40 and P(B)= 0.50,then P(A/B)is 0.50.

(True/False)
4.8/5
(36)

If A and B are two independent events with P(A)= 0.20 and P(B)= 0.60,then P(A and B)= 0.80

(True/False)
4.9/5
(31)

If P(A)= P(A|B),then events A and B are said to be

(Multiple Choice)
4.9/5
(41)

Two or more events are said to be exhaustive if at most one of them can occur.

(True/False)
5.0/5
(33)

Probabilities that can be estimated from long-run relative frequencies of events are

(Multiple Choice)
4.7/5
(35)

The probability of an event and the probability of its complement always sum to

(Multiple Choice)
4.8/5
(40)

The number of car insurance policy holders is an example of a discrete random variable.

(True/False)
4.7/5
(29)

Two or more events are said to be exhaustive if one of them must occur.

(True/False)
4.8/5
(38)

If two events are mutually exclusive,what is the probability that one or the other occurs?

(Multiple Choice)
4.9/5
(38)

A discrete probability distribution:

(Multiple Choice)
4.9/5
(36)

The probabilities shown in a table with two rows, A1 and A2A _ { 1 } \text { and } A _ { 2 } And two columns, B1 and B2B _ { 1 } \text { and } B _ { 2 } ,are as follows: P(A1 and B1)=10P \left( A _ { 1 } \text { and } B _ { 1 } \right) = 10 , P(A1 and B2)=.30P \left( A _ { 1 } \text { and } B _ { 2 } \right) = .30 , P(A2 and B1)=.05P \left( A _ { 2 } \text { and } B _ { 1 } \right) = .05 ,and P(A2 and B2)=.55P \left( A _ { 2 } \text { and } B _ { 2 } \right) = .55 )Then P(A1B1)P \left( A _ { 1 } \mid B _ { 1 } \right) ,calculated up to two decimals,is

(Multiple Choice)
4.8/5
(41)
Showing 41 - 56 of 56
close modal

Filters

  • Essay(0)
  • Multiple Choice(0)
  • Short Answer(0)
  • True False(0)
  • Matching(0)