Exam 8: Confidence Interval Estimation

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As the sample size increases,the t-distribution becomes more similar to the ________ distribution.

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The chi-square distribution for developing a confidence interval for a standard deviation has degrees of freedom.

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If you are constructing a confidence interval for a single mean,the confidence interval will with an increase in the sample size.

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Suppose there are 500 accounts in a population.You sample 50 of them and find a sample mean of $500.What would be your estimate for the population total?

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The upper limit of the 90% confidence interval for the population proportion p,given that n = 100;and P^\hat { P } = 0.20 is 0.2658.

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If two samples contain the same number of observations,then the data must be paired.

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A parameter such as σ\sigma Is sometimes referred to as a ________ parameter,because many times we need its value even though it is not the parameter of primary interest.

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The t-distribution and the standard normal distribution are practically indistinguishable as the degrees of freedom increase.

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There are,generally speaking,two types of statistical inference.They are:

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We can form a confidence interval for the population total T by finding a confidence interval for the population mean μ\mu in the usual way,and then multiplying the lower and upper limits the confidence interval by the population size N.

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If two random samples of size 40 each are selected independently from two populations whose variances are 35 and 45,then the standard error of the sampling distribution of the sample mean difference, x1x2x _ { 1 } - x _ { 2 } ,equals 1.4142.

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In developing a confidence interval for the population standard deviation σ\sigma ,we make use of the fact that the sampling distribution of the sample standard deviation s is not the normal distribution or the t-distribution,but rather a right-skewed distribution called the chi-square distribution,which (for this procedure)has n - 1 degrees of freedom.

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For a given confidence level,the procedure for controlling interval length usually begins with the specification of

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If two random samples of sizes 30 and 35 are selected independently from two populations whose means are 85 and 90,then the mean of the sampling distribution of the sample mean difference, x1x2x _ { 1 } - x _ { 2 } ,equals 5.

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A 90% confidence interval estimate for a population mean μ\mu is determined to be 72.8 to 79.6.If the confidence level is reduced to 80%,the confidence interval for μ\mu becomes narrower.

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The interval estimate 18.5 ±\pm 2.5 was developed for a population mean when the sample standard deviation s was 7.5.Had s equaled 15,the interval estimate would be 37 ±\pm 5.0.

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The mean of the sampling distribution of the sample proportion p^\hat { p } ,when the sample size n = 100 and the population proportion p = 0.15,is 15.0.

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The lower limit of the 95% confidence interval for the population proportion p,given that n = 300;and p^\hat { p } = 0.10 is 0.1339.

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If we cannot make the strong assumption that the variances of two samples are equal,then we must use the pooled standard deviation in calculating the standard error of a difference between the means.

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The approximate standard error of the point estimate of the population total is Ns/nN s / \sqrt { n } .

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