Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests
Exam 1: Introduction and Data Collection131 Questions
Exam 2: Presenting Data in Tables and Charts178 Questions
Exam 3: Numerical Descriptive Measures148 Questions
Exam 4: Basic Probability146 Questions
Exam 5: Some Important Discrete Probability Distributions169 Questions
Exam 6: The Normal Distribution and Other Continuous Distributions187 Questions
Exam 7: Sampling Distributions183 Questions
Exam 8: Confidence Interval Estimation176 Questions
Exam 9: Fundamentals of Hypothesis Testing: One-Sample Tests167 Questions
Exam 10: Hypothesis Testing: Two Sample Tests160 Questions
Exam 11: Analysis of Variance141 Questions
Exam 12: Simple Linear Regression196 Questions
Exam 13: Introduction to Multiple Regression256 Questions
Exam 14: Time-Series Forecasting and Index Numbers203 Questions
Exam 15: Chi-Square Tests135 Questions
Exam 16: Multiple Regression Model Building92 Questions
Exam 17: Decision Making111 Questions
Exam 18: Statistical Applications in Quality and Productivity Management127 Questions
Exam 19: Further Non-Parametric Tests51 Questions
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Instruction 9-3
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W.From previous studies,it is believed that power consumption for microwave ovens is normally distributed with a population standard deviation of 15 W.A consumer group has decided to try to discover if the claim appears true.They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.
-Referring to Instruction 9-3,the p-value of the test is ________.
(Short Answer)
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Instruction 9-4
A drug company is considering marketing a new local anaesthetic.The effective time of the anaesthetic the drug company is currently producing has a normal distribution with a mean of 7.4 minutes with a standard deviation of 1.2 minutes.The chemistry of the new anaesthetic is such that the effective time should be normal with the same standard deviation,but the mean effective time may be lower.If it is lower,the drug company will market the new anaesthetic;otherwise,it will continue to produce the older drug.A sample of size 36 results in a sample mean of 7.1.A hypothesis test will be done to help make the decision.
-Referring to Instruction 9-4,what is the power of the test if the mean effective time of the anaesthetic is 7.0 using a 0.10 level of significance?
(Short Answer)
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A region of non-rejection is sometimes called the critical region.
(True/False)
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You have created a 95% confidence interval for μ with the result (10,15).What decision will you make if you test H0: μ = 16 versus H1: μ ≠ 16 at α = 0.05?
(Multiple Choice)
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Instruction 9-3
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W.From previous studies,it is believed that power consumption for microwave ovens is normally distributed with a population standard deviation of 15 W.A consumer group has decided to try to discover if the claim appears true.They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.
-Referring to Instruction 9-3,what is the power of the test if the mean power consumption of all such microwave ovens is in fact 248 W using a 0.10 level of significance?
(Short Answer)
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If an economist wishes to determine whether there is evidence that average family income in a community equals $50,000
(Multiple Choice)
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Instruction 9-1
Microsoft Excel was used on a set of data involving the number of parasites found in a random sample of 46 Blue Tiger butterflies captured in Kakadu National Park.A biologist wants to know if the mean number of parasites per butterfly is greater than 20.She will make her decision using a test with a level of significance of 0.10.The following information was extracted from the Microsoft Excel output for the sample of 46 butterflies:
Arithmetic Mean = 28.00; Standard Deviation = 25.92; Standard Error = 3.82; Null Hypothesis: Test Statistic = 2.09;
One-Tailed Test Upper Critical Value -value Decision Reject.
-Referring to Instruction 9-1,the power of the test is ________ if the mean number of parasites per butterfly on Blue Tiger butterflies in Kakadu National Park is 30 using a 0.1 level of significance and assuming that the population standard deviation is 25.92.
(Short Answer)
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Instruction 9-3
An appliance manufacturer claims to have developed a compact microwave oven that consumes a mean of no more than 250 W.From previous studies,it is believed that power consumption for microwave ovens is normally distributed with a population standard deviation of 15 W.A consumer group has decided to try to discover if the claim appears true.They take a sample of 20 microwave ovens and find that they consume a mean of 257.3 W.
-Referring to Instruction 9-3,the consumer group can conclude that there is enough evidence to prove that the manufacturer's claim is not true when allowing for a 5% probability of committing a Type I error.
(True/False)
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Instruction 9-7
A major home improvement store conducted its biggest brand recognition campaign in the company's history.A series of new television advertisements featuring well-known entertainers and sports figures were launched.A key metric for the success of television advertisements is the proportion of viewers who "like the ads a lot".A study of 1,189 adults who viewed the ads reported that 230 indicated that they "like the ads a lot".The percentage of a typical television advertisement receiving the "like the ads a lot" score is believed to be 22%.Company officials wanted to know if there is evidence that the series of television advertisements are less successful than the typical ad at a 0.01 level of significance.
-Referring to Instruction 9-7,the largest level of significance at which the null hypothesis will not be rejected is ________.
(Short Answer)
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A sample is used to obtain a 95% confidence interval for the mean of a population.The confidence interval goes from 15 to 19.If the same sample had been used to test the null hypothesis that the mean of the population is equal to 20 versus the alternative hypothesis that the mean of the population differs from 20,the null hypothesis could be rejected at a level of significance of 0.02.
(True/False)
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Instruction 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tailed test of the null hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Instruction 9-6,if the test is performed with a level of significance of 0.05,the engineer can conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650.
(True/False)
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Instruction 9-7
A major home improvement store conducted its biggest brand recognition campaign in the company's history.A series of new television advertisements featuring well-known entertainers and sports figures were launched.A key metric for the success of television advertisements is the proportion of viewers who "like the ads a lot".A study of 1,189 adults who viewed the ads reported that 230 indicated that they "like the ads a lot".The percentage of a typical television advertisement receiving the "like the ads a lot" score is believed to be 22%.Company officials wanted to know if there is evidence that the series of television advertisements are less successful than the typical ad at a 0.01 level of significance.
-Referring to Instruction 9-7,the parameter the company officials is interested in is
(Multiple Choice)
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Instruction 9-1
Microsoft Excel was used on a set of data involving the number of parasites found in a random sample of 46 Blue Tiger butterflies captured in Kakadu National Park.A biologist wants to know if the mean number of parasites per butterfly is greater than 20.She will make her decision using a test with a level of significance of 0.10.The following information was extracted from the Microsoft Excel output for the sample of 46 butterflies:
Arithmetic Mean = 28.00; Standard Deviation = 25.92; Standard Error = 3.82; Null Hypothesis: Test Statistic = 2.09;
One-Tailed Test Upper Critical Value -value Decision Reject.
-Referring to Instruction 9-1,the evidence proves beyond any doubt that the mean number of parasites on butterflies in Kakadu National Park is greater than 20.
(True/False)
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Instruction 9-1
Microsoft Excel was used on a set of data involving the number of parasites found in a random sample of 46 Blue Tiger butterflies captured in Kakadu National Park.A biologist wants to know if the mean number of parasites per butterfly is greater than 20.She will make her decision using a test with a level of significance of 0.10.The following information was extracted from the Microsoft Excel output for the sample of 46 butterflies:
Arithmetic Mean = 28.00; Standard Deviation = 25.92; Standard Error = 3.82; Null Hypothesis: Test Statistic = 2.09;
One-Tailed Test Upper Critical Value -value Decision Reject.
-Referring to Instruction 9-1,the lowest level of significance at which the null hypothesis can be rejected is ________.
(Short Answer)
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Instruction 9-4
A drug company is considering marketing a new local anaesthetic.The effective time of the anaesthetic the drug company is currently producing has a normal distribution with a mean of 7.4 minutes with a standard deviation of 1.2 minutes.The chemistry of the new anaesthetic is such that the effective time should be normal with the same standard deviation,but the mean effective time may be lower.If it is lower,the drug company will market the new anaesthetic;otherwise,it will continue to produce the older drug.A sample of size 36 results in a sample mean of 7.1.A hypothesis test will be done to help make the decision.
-Referring to Instruction 9-4,the appropriate hypotheses are
(Multiple Choice)
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A sample is used to obtain a 95% confidence interval for the mean of a population.The confidence interval goes from 15 to 19.If the same sample had been used to test the null hypothesis that the mean of the population is equal to 20 versus the alternative hypothesis that the mean of the population differs from 20,the null hypothesis could be rejected at a level of significance of 0.10.
(True/False)
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Instruction 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tailed test of the null hypothesis that the mean for the stressed oak furniture is 650.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Instruction 9-6,suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650.What would be the p-value of this one-tailed test?
(Multiple Choice)
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If a researcher accepts a true null hypothesis,she has made a ________ decision.
(Short Answer)
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For a given sample size,the probability of committing a Type II error will increase when the probability of committing a Type I error is reduced.
(True/False)
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