Exam 28: Magnetic Fields
Exam 1: Measurement31 Questions
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Exam 21: Electric Charge45 Questions
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Exam 23: Gauss Law34 Questions
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Exam 28: Magnetic Fields48 Questions
Exam 29: Magnetic Fields Due to Currents47 Questions
Exam 30: Induction and Inductance85 Questions
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Exam 32: Maxwells Equations; Magnetism of Matter81 Questions
Exam 33: Electromagnetic Waves79 Questions
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Exam 35: Interference40 Questions
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Exam 42: Nuclear Physics67 Questions
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A loop of current-carrying wire has a magnetic dipole moment of 5 *10-4 A .m2. The moment initially is aligned with a 0.5-T magnetic filed.To rotate the loop so its dipole momentt is perpendicular to the field and hold it in that orentation, you must do work of:
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(Multiple Choice)
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Correct Answer:
B
At any point the magnetic field lines are in the direction of:
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Correct Answer:
E
A uniform magnetic field is directed into the page. A charged particle, moving in the plane of the page, follows a clockwise spiral of decreasing radius as shown. A reasonable explanation is: 

(Multiple Choice)
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An electron enters a region of uniform perpendicular
fields. It is observed that the velocity
of the electron is unaffected. A possible explanation is:


(Multiple Choice)
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A current is clockwise around the outside edge of this page and a uniform magnetic field is directed parallel to the page, from left to right. If the magnetic force is the only force acting on the page, the page will turn so the right edge:
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An electron and a proton are both initially moving with the same speed and in the same direction at 90˚ to the same uniform magnetic field. They experience magnetic forces, which are initially:
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An electron is launched with velocity
in a uniform magnetic field
The angle between
is between 0 and 90o. As a result, the electron follows a helix, its velocity vector
returning to its initial value in a time interval of:




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A proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The ratio of their speeds, vproton/valpha is:
(Multiple Choice)
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An electron (charge = -1.6 *10-19C) is moving at 3 *105 m/s in the positive x direction. A magnetic field of 0.8 T is in the positive z direction. The magnetic force on the electron is:
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The magnetic force on a charged particle is in the direction of its velocity if:
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An ion with a charge of +3.25*10−19 C is in region where a uniform electric field of 5 * 104. V/m is perpendicular to a uniform magnetic field of 0.8 T. If its acceleration is zero then its speed must be:
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The direction of the magnetic field in a certain region of space is determined by firing a test charge into the region with its velocity in various directions in different trials. The field direction is:
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The diagrams show five possible orientations of a magnetic dipole
in a uniform magnetic field
For which of these does the magnetic torque on the dipole have the greatest magnitude? 



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J. J. Thomson's experiment, involving the motion of an electron beam in mutually perpendicular
fields, gave the value of:

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An electron is travelling in the positive x direction. A uniform electric field
is in the negative y direction. If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero. The appropriate direction for the magetic field is: 


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An electron travels due north through a vacuum in a region of uniform magnetic field
that is also directed due north. It will:

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A uniform magnetic field is in the positive z direction. A positively charged particle is moving in the positive x direction through the field. The net force on the particle can be made zero by applying an electric field in what direction?
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