Exam 28: Magnetic Fields

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In the formula In the formula

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E

A loop of current-carrying wire has a magnetic dipole moment of 5 *10-4 A .m2. The moment initially is aligned with a 0.5-T magnetic filed.To rotate the loop so its dipole momentt is perpendicular to the field and hold it in that orentation, you must do work of:

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At any point the magnetic field lines are in the direction of:

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A uniform magnetic field is directed into the page. A charged particle, moving in the plane of the page, follows a clockwise spiral of decreasing radius as shown. A reasonable explanation is: A uniform magnetic field is directed into the page. A charged particle, moving in the plane of the page, follows a clockwise spiral of decreasing radius as shown. A reasonable explanation is:

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An electron enters a region of uniform perpendicular An electron enters a region of uniform perpendicular   fields. It is observed that the velocity   of the electron is unaffected. A possible explanation is: fields. It is observed that the velocity An electron enters a region of uniform perpendicular   fields. It is observed that the velocity   of the electron is unaffected. A possible explanation is: of the electron is unaffected. A possible explanation is:

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A current is clockwise around the outside edge of this page and a uniform magnetic field is directed parallel to the page, from left to right. If the magnetic force is the only force acting on the page, the page will turn so the right edge:

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An electron and a proton are both initially moving with the same speed and in the same direction at 90˚ to the same uniform magnetic field. They experience magnetic forces, which are initially:

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An electron is launched with velocity  An electron is launched with velocity   in a uniform magnetic field   The angle  \theta between   is between 0 and 90<sup>o</sup>. As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: in a uniform magnetic field  An electron is launched with velocity   in a uniform magnetic field   The angle  \theta between   is between 0 and 90<sup>o</sup>. As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: The angle θ\theta between  An electron is launched with velocity   in a uniform magnetic field   The angle  \theta between   is between 0 and 90<sup>o</sup>. As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: is between 0 and 90o. As a result, the electron follows a helix, its velocity vector  An electron is launched with velocity   in a uniform magnetic field   The angle  \theta between   is between 0 and 90<sup>o</sup>. As a result, the electron follows a helix, its velocity vector   returning to its initial value in a time interval of: returning to its initial value in a time interval of:

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A proton (charge e), traveling perpendicular to a magnetic field, experiences the same force as an alpha particle (charge 2e) which is also traveling perpendicular to the same field. The ratio of their speeds, vproton/valpha is:

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An electron (charge = -1.6 *10-19C) is moving at 3 *105 m/s in the positive x direction. A magnetic field of 0.8 T is in the positive z direction. The magnetic force on the electron is:

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Units of a magnetic field might be:

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The magnetic force on a charged particle is in the direction of its velocity if:

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An ion with a charge of +3.25*1019 C is in region where a uniform electric field of 5 * 104. V/m is perpendicular to a uniform magnetic field of 0.8 T. If its acceleration is zero then its speed must be:

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The units of magnetic dipole moment are:

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The direction of the magnetic field in a certain region of space is determined by firing a test charge into the region with its velocity in various directions in different trials. The field direction is:

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The diagrams show five possible orientations of a magnetic dipole The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   For which of these does the magnetic torque on the dipole have the greatest magnitude?  in a uniform magnetic field The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   For which of these does the magnetic torque on the dipole have the greatest magnitude?  For which of these does the magnetic torque on the dipole have the greatest magnitude? The diagrams show five possible orientations of a magnetic dipole   in a uniform magnetic field   For which of these does the magnetic torque on the dipole have the greatest magnitude?

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J. J. Thomson's experiment, involving the motion of an electron beam in mutually perpendicular J. J. Thomson's experiment, involving the motion of an electron beam in mutually perpendicular   fields, gave the value of: fields, gave the value of:

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An electron is travelling in the positive x direction. A uniform electric field An electron is travelling in the positive x direction. A uniform electric field   is in the negative y direction. If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero. The appropriate direction for the magetic field is:  is in the negative y direction. If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero. The appropriate direction for the magetic field is: An electron is travelling in the positive x direction. A uniform electric field   is in the negative y direction. If a uniform magnetic field with the appropriate magnitude and direction also exists in the region, the total force on the electron will be zero. The appropriate direction for the magetic field is:

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An electron travels due north through a vacuum in a region of uniform magnetic field An electron travels due north through a vacuum in a region of uniform magnetic field   that is also directed due north. It will: that is also directed due north. It will:

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A uniform magnetic field is in the positive z direction. A positively charged particle is moving in the positive x direction through the field. The net force on the particle can be made zero by applying an electric field in what direction?

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