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What Is the Equilibrium Constant for the Following Reaction, HCO2H(aq)

Question 10

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What is the equilibrium constant for the following reaction, HCO2H(aq) + CN-(aq) What is the equilibrium constant for the following reaction, HCO<sub>2</sub>H(aq) + CN<sup>-</sup>(aq)    HCO<sub>2</sub><sup>-</sup>(aq) + HCN(aq)  And does the reaction favor the formation of reactants or products? The acid dissociation constant,K<sub>a</sub>,for HCO<sub>2</sub>H is 1.8 × 10<sup>-4</sup> and the acid dissociation constant for HCN is 4.0 × 10<sup>-10</sup>. A)  K = 1.00.The reaction favors neither the formation of reactants nor products. B)  K = 2.2 × 10<sup>-6</sup>.The reaction favors the formation of products. C)  K = 2.2 × 10<sup>-6</sup>.The reaction favors the formation of reactants. D)  K = 4.5 × 10<sup>5</sup>.The reaction favors the formation of products. E)  K = 4.5 × 10<sup>5</sup>.The reaction favors the formation of reactants. HCO2-(aq) + HCN(aq)
And does the reaction favor the formation of reactants or products? The acid dissociation constant,Ka,for HCO2H is 1.8 × 10-4 and the acid dissociation constant for HCN is 4.0 × 10-10.


A) K = 1.00.The reaction favors neither the formation of reactants nor products.
B) K = 2.2 × 10-6.The reaction favors the formation of products.
C) K = 2.2 × 10-6.The reaction favors the formation of reactants.
D) K = 4.5 × 105.The reaction favors the formation of products.
E) K = 4.5 × 105.The reaction favors the formation of reactants.

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