Multiple Choice
2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g) According to the equation above,what mass of aluminum is needed to completely react with 2.98 mol of hydrochloric acid?
A) 241 g
B) 36.3 g
C) 26.8 g
D) 2.98 g
E) 80.4 g
Correct Answer:

Verified
Correct Answer:
Verified
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