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Use the Standard Reaction Enthalpies Given Below to Determine

Question 10

Multiple Choice

Use the standard reaction enthalpies given below to determine Use the standard reaction enthalpies given below to determine H° for the following reaction: 2S(s) + 3O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= ? Given: SO<sub>2</sub>(g) → S(s) + O<sub>2</sub>(g) H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -197.8 kJ A) -494.6 kJ mol<sup>-1</sup> B) -692.4 kJ mol<sup>-1</sup> C) -791.4 kJ mol<sup>-1</sup> D) 1583 kJ mol<sup>-1</sup> E) -293.0 kJ mol<sup>-1</sup> H° for the following reaction: 2S(s) + 3O2(g) → 2SO3(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2S(s) + 3O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= ? Given: SO<sub>2</sub>(g) → S(s) + O<sub>2</sub>(g) H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -197.8 kJ A) -494.6 kJ mol<sup>-1</sup> B) -692.4 kJ mol<sup>-1</sup> C) -791.4 kJ mol<sup>-1</sup> D) 1583 kJ mol<sup>-1</sup> E) -293.0 kJ mol<sup>-1</sup> H° = ?
Given:
SO2(g) → S(s) + O2(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2S(s) + 3O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= ? Given: SO<sub>2</sub>(g) → S(s) + O<sub>2</sub>(g) H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -197.8 kJ A) -494.6 kJ mol<sup>-1</sup> B) -692.4 kJ mol<sup>-1</sup> C) -791.4 kJ mol<sup>-1</sup> D) 1583 kJ mol<sup>-1</sup> E) -293.0 kJ mol<sup>-1</sup> H° = +296.8 kJ
2SO2(g) + O2(g) → 2SO3(g) Use the standard reaction enthalpies given below to determine H° for the following reaction: 2S(s) + 3O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= ? Given: SO<sub>2</sub>(g) → S(s) + O<sub>2</sub>(g) H°<sub> </sub>= +296.8 kJ 2SO<sub>2</sub>(g) + O<sub>2</sub>(g) → 2SO<sub>3</sub>(g) H°<sub> </sub>= -197.8 kJ A) -494.6 kJ mol<sup>-1</sup> B) -692.4 kJ mol<sup>-1</sup> C) -791.4 kJ mol<sup>-1</sup> D) 1583 kJ mol<sup>-1</sup> E) -293.0 kJ mol<sup>-1</sup> H° = -197.8 kJ


A) -494.6 kJ mol-1
B) -692.4 kJ mol-1
C) -791.4 kJ mol-1
D) 1583 kJ mol-1
E) -293.0 kJ mol-1

Correct Answer:

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