Using the Thermodynamic Data Below and a Value of -717

Multiple Choice

Using the thermodynamic data below and a value of -717 kJ/mole for the lattice enthalpy for KCl, calculate the ionization energy of K. $$\begin{array} { l l } \text { Enthalpy of atomization of } \mathrm { K } & + 89 \mathrm {~kJ} / \mathrm { mol } \\\text { Enthalpy of formation of } \mathrm { KCl } ( \mathrm { s } ) & - 437 \mathrm {~kJ} / \mathrm { mol } \\\text { Enthalpy of formation of } \mathrm { Cl } ( \mathrm { g } ) & + 121 \mathrm {~kJ} / \mathrm { mol } \\\text { Electron attachment enthalpy of } \mathrm { Cl } ( \mathrm { g } ) & - 349 \mathrm {~kJ} / \mathrm { mol }\end{array}$$

A) -576 kJ/mol
B) +141 kJ/mol
C) +419 kJ/mol
D) +576 kJ/mol
E) +597 kJ/mol