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Essentials of Statistics Study Set 1
Exam 5: Discrete Probability Distributions
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Question 21
Multiple Choice
Exhibit 5-11 A local bottling company has determined the number of machine breakdowns per month and their respective probabilities as shown below:
Number of
Breakdowns
Prabability
0
0.12
1
0.38
2
0.25
3
0.18
4
0.07
\begin{array}{ll}\text { Number of } & \\\text { Breakdowns } & \text { Prabability } \\0 & 0.12 \\1 & 0.38 \\2 & 0.25 \\3 & 0.18 \\4 & 0.07\end{array}
Number of
Breakdowns
0
1
2
3
4
Prabability
0.12
0.38
0.25
0.18
0.07
-Refer to Exhibit 5-11. The probability of at least 3 breakdowns in a month is
Question 22
Multiple Choice
Which of the following is not a property of a binomial experiment?
Question 23
Multiple Choice
The Poisson probability distribution is a
Question 24
Short Answer
The following probability distribution represents the number of grievances filed per month with the MNM. Corporation.
x
f
x
)
0
0.04
1
0.36
2
0.50
3
0.08
4
0.02
\begin{array} { l l } x&fx)\\0&0.04\\1&0.36\\2&0.50\\3&0.08\\4&0.02\end{array}
x
0
1
2
3
4
f
x
)
0.04
0.36
0.50
0.08
0.02
a. Determine the expected value of the number of grievances in a month. b. Determine the variance. c. Compute the standard deviation.
Question 25
Multiple Choice
Exhibit 5-10 The probability distribution for the number of goals the Lions soccer team makes per game is given below.
Number
Of Goals
Prabability
0
0.05
1
0.15
2
0.35
3
0.30
4
015
\begin{array} { c c } \text { Number } & \\\text { Of Goals } & \text { Prabability } \\0 & 0.05 \\1 & 0.15 \\2 & 0.35 \\3 & 0.30 \\4 & 015\end{array}
Number
Of Goals
0
1
2
3
4
Prabability
0.05
0.15
0.35
0.30
015
-Refer to Exhibit 5-10. The expected number of goals per game is
Question 26
Multiple Choice
Which of the following is a required condition for a discrete probability function?
Question 27
Short Answer
Compute the hypergeometric probabilities for the following values of n and x. Assume N = 8 and r = 5. a. n = 5, x = 2 b. n = 6, x = 4 c. n = 3, x = 0 d. n = 3, x = 3
Question 28
Short Answer
The following table shows part of the probability distribution for a random variable x.
x
f
x
)
0
0.2
1
?
2
0.15
3
?
4
0.15
\begin{array} { r r } \mathbf { x } & \mathbf { f x } ) \\0 & 0.2 \\1 & ? \\2 & 0.15 \\3 & ? \\4 & 0.15\end{array}
x
0
1
2
3
4
fx
)
0.2
?
0.15
?
0.15
a. The mean of the above distribution is known to be 1.8 i.e., Ex) = 1.8). Determine f1) and f3). b. Compute the variance and the standard deviation for the above probability distribution.
Question 29
Multiple Choice
Exhibit 5-8 The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two-time periods of an equal length. It is known that the mean number of occurrences in ten minutes is 5.3. -Refer to Exhibit 5-8. The appropriate probability distribution for the random variable is
Question 30
Multiple Choice
Exhibit 5-5 Probability Distribution
x
f
x
)
10
.
2
20
.
3
30
.
4
40
.
1
\begin{array}{ll}x&fx) \\10 & .2 \\20 & .3 \\30 & .4 \\40 & .1\end{array}
x
10
20
30
40
f
x
)
.2
.3
.4
.1
-Refer to Exhibit 5-5. The expected value of x equals
Question 31
Short Answer
Determine the probability of being dealt 4 kings in a 5-card poker hand.
Question 32
Multiple Choice
Exhibit 5-13 Oriental Reproductions, Inc. is a company that produces handmade carpets with oriental designs. The production records show that the monthly production has ranged from 1 to 5 carpets. The production levels and their respective probabilities are shown below.
Production
Per Month
Probability
x
f
x
)
1
0.01
2
0.04
3
0.10
4
0.80
5
005
\begin{array}{ll}\text { Production }\\\text { Per Month }&\text { Probability }\\\mathbf{x} & \mathbf{f x}) \\1 & 0.01 \\2 & 0.04 \\3 & 0.10 \\4 & 0.80 \\5 & 005\end{array}
Production
Per Month
x
1
2
3
4
5
Probability
fx
)
0.01
0.04
0.10
0.80
005
-Refer to Exhibit 5-13. The standard deviation for the production is
Question 33
Multiple Choice
Exhibit 5-12 The police records of a metropolitan area kept over the past 300 days show the following number of fatal accidents.
Number of Fatal
Accidents
Number of Day
0
45
1
75
2
120
3
45
4
15
\begin{array}{cc}\text { Number of Fatal }\\\text { Accidents }&\text { Number of Day }\\0 & 45 \\1 & 75 \\2 & 120 \\3 & 45 \\4 & 15\end{array}
Number of Fatal
Accidents
0
1
2
3
4
Number of Day
45
75
120
45
15
-Refer to Exhibit 5-12. What is the probability that in a given day there will be less than 3 accidents?
Question 34
Multiple Choice
Four percent of the customers of a mortgage company default on their payments. A sample of five customers is selected. What is the probability that exactly two customers in the sample will default on their payments?