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Find the Point (X, Y) on the Unit Circle That t=5π6t = \frac { 5 \pi } { 6 }

Question 38

Multiple Choice

Find the point (x, y) on the unit circle that corresponds to the real number t. t=5π6t = \frac { 5 \pi } { 6 }


A) t=5π6t = \frac { 5 \pi } { 6 } corresponds to the point (12,32) \left( \frac { 1 } { 2 } , - \frac { \sqrt { 3 } } { 2 } \right) .
B) t=5π6t = \frac { 5 \pi } { 6 } corresponds to the point (32,12) \left( - \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right) .
C) t=5π6t = \frac { 5 \pi } { 6 } corresponds to the point (32,12) \left( - \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right) .
D) t=5π6t = \frac { 5 \pi } { 6 } corresponds to the point (32,12) \left( \frac { \sqrt { 3 } } { 2 } , - \frac { 1 } { 2 } \right) .
E) t=5π6t = \frac { 5 \pi } { 6 } corresponds to the point (32,12) \left( \frac { \sqrt { 3 } } { 2 } , \frac { 1 } { 2 } \right) .

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