Solved

Select the Graph of the Polar Equation Using Symmetry, Zeros r=35sinθr = 3 - 5 \sin \theta

Question 26

Multiple Choice

Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.
r=35sinθr = 3 - 5 \sin \theta


A) Symmetric with respect to θ=π2\theta = \frac { \pi } { 2 } r=8 when θ=3π2r=0 when θ=π6,θ=5π6\begin{array} { c } | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 }\end{array}  Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.   r = 3 - 5 \sin \theta   A) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     B) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     C) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     D) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}    E) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}
B) Symmetric with respect to θ=π2\theta = \frac { \pi } { 2 } r=8 when θ=3π2r=0 when θ=π6,θ=5π6\begin{array} { c } | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 }\end{array}  Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.   r = 3 - 5 \sin \theta   A) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     B) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     C) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     D) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}    E) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}
C) Symmetric with respect to θ=π2\theta = \frac { \pi } { 2 } r=8 when θ=3π2r=0 when θ=π6,θ=5π6\begin{array} { c } | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 }\end{array}  Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.   r = 3 - 5 \sin \theta   A) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     B) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     C) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     D) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}    E) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}
D) Symmetric with respect to θ=π2\theta = \frac { \pi } { 2 } r=8 when θ=3π2r=0 when θ=π6,θ=5π6\begin{array} { c } | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 }\end{array}  Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.   r = 3 - 5 \sin \theta   A) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     B) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     C) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     D) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}    E) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}
E) Symmetric with respect to θ=π2\theta = \frac { \pi } { 2 } r=8 when θ=3π2r=0 when θ=π6,θ=5π6\begin{array} { c } | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 }\end{array}  Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.   r = 3 - 5 \sin \theta   A) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     B) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     C) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}     D) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}    E) Symmetric with respect to  \theta = \frac { \pi } { 2 }   \begin{array} { c }  | r | = 8 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 6 } , \theta = \frac { 5 \pi } { 6 } \end{array}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions