Select the correct graph of the polar equation.Describe your viewing window.

r = \frac { 7 } { 4 }

A) $Select the correct graph of the polar equation.Describe your viewing window. r = \frac { 7 } { 4 } A) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} B) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} C) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} D) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} E) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array}$

\begin{array} { l } \theta _ { \min } = 0 \\\theta _ { \max } = 2 \pi \\\theta _ { s t e p } = \pi / 24 \\X _ { \min } = - 5 \\X _ { \max } = 5 \\X _ { s c l } = 1 \\Y _ { \min } = - 5 \\Y _ { \max } = 5 \\Y _ { s c l } = 1\end{array}

B) $Select the correct graph of the polar equation.Describe your viewing window. r = \frac { 7 } { 4 } A) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} B) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} C) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} D) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} E) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array}$

\begin{array} { l } \theta _ { \min } = 0 \\\theta _ { \max } = 2 \pi \\\theta _ { s t e p } = \pi / 24 \\X _ { \min } = - 5 \\X _ { \max } = 5 \\X _ { s c l } = 1 \\Y _ { \min } = - 5 \\Y _ { \max } = 5 \\Y _ { s c l } = 1\end{array}

C) $Select the correct graph of the polar equation.Describe your viewing window. r = \frac { 7 } { 4 } A) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} B) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} C) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} D) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} E) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array}$

\begin{array} { l } \theta _ { \min } = 0 \\\theta _ { \max } = 2 \pi \\\theta _ { s t e p } = \pi / 24 \\X _ { \min } = - 5 \\X _ { \max } = 5 \\X _ { s c l } = 1 \\Y _ { \min } = - 5 \\Y _ { \max } = 5 \\Y _ { s c l } = 1\end{array}

D) $Select the correct graph of the polar equation.Describe your viewing window. r = \frac { 7 } { 4 } A) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} B) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} C) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} D) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} E) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array}$

\begin{array} { l } \theta _ { \min } = 0 \\\theta _ { \max } = 2 \pi \\\theta _ { s t e p } = \pi / 24 \\X _ { \min } = - 5 \\X _ { \max } = 5 \\X _ { s c l } = 1 \\Y _ { \min } = - 5 \\Y _ { \max } = 5 \\Y _ { s c l } = 1\end{array}

E) $Select the correct graph of the polar equation.Describe your viewing window. r = \frac { 7 } { 4 } A) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} B) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} C) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} D) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array} E) \begin{array} { l } \theta _ { \min } = 0 \\ \theta _ { \max } = 2 \pi \\ \theta _ { s t e p } = \pi / 24 \\ X _ { \min } = - 5 \\ X _ { \max } = 5 \\ X _ { s c l } = 1 \\ Y _ { \min } = - 5 \\ Y _ { \max } = 5 \\ Y _ { s c l } = 1 \end{array}$

\begin{array} { l } \theta _ { \min } = 0 \\\theta _ { \max } = 2 \pi \\\theta _ { s t e p } = \pi / 24 \\X _ { \min } = - 5 \\X _ { \max } = 5 \\X _ { s c l } = 1 \\Y _ { \min } = - 5 \\Y _ { \max } = 5 \\Y _ { s c l } = 1\end{array}

Convert the Rectangular Equation to Polar Form 5x+7y−4=05 x + 7 y - 4 = 05x+7y−4=0

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Convert the Rectangular Equation to Polar Form $5 x + 7 y - 4 = 0$

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