Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points.

r = ( 1 + \sin \theta )

A)Symmetric with respect to

\theta = \frac { \pi } { 2 }

\begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 2 }\end{array}

$Select the graph of the polar equation using symmetry, zeros, maximum r-values, and any other additional points. r = ( 1 + \sin \theta ) A)Symmetric with respect to \theta = \frac { \pi } { 2 } \begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 2 } \end{array} B)Symmetric with respect to \theta = \frac { \pi } { 2 } \begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 2 } \end{array} C)Symmetric with respect to \theta = \frac { \pi } { 2 } \begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 2 } \end{array} D)Symmetric with respect to \theta = \frac { \pi } { 2 } \begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 2 } \end{array} E)Symmetric with respect to \theta = \frac { \pi } { 2 } \begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\ r = 0 \text { when } \theta = \frac { \pi } { 2 } \end{array}$
B)Symmetric with respect to

\theta = \frac { \pi } { 2 }

\begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 2 }\end{array}

\theta = \frac { \pi } { 2 }

\begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 2 }\end{array}

\theta = \frac { \pi } { 2 }

\begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 2 }\end{array}

\theta = \frac { \pi } { 2 }

\begin{array} { l } | r | = 2 \text { when } \theta = \frac { 3 \pi } { 2 } \\r = 0 \text { when } \theta = \frac { \pi } { 2 }\end{array}

Use the Discriminant to Classify the Graph 16x2−5xy+10y2−44=016 x ^ { 2 } - 5 x y + 10 y ^ { 2 } - 44 = 016x2−5xy+10y2−44=0

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Use the Discriminant to Classify the Graph $16 x ^ { 2 } - 5 x y + 10 y ^ { 2 } - 44 = 0$

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