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Use the Quadratic Formula to Solve For yy x25xy4y2+3x32=0x ^ { 2 } - 5 x y - 4 y ^ { 2 } + 3 x - 32 = 0

Question 272

Multiple Choice

Use the Quadratic Formula to solve for yy . x25xy4y2+3x32=0x ^ { 2 } - 5 x y - 4 y ^ { 2 } + 3 x - 32 = 0


A) y=5x±25x2+16(x23x32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } - 3 x - 32 \right) } } { 8 }
B) y=5x±25x216(x2+3x32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } - 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }
C) y=5x±25x216(x2+3x+32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } - 16 \left( x ^ { 2 } + 3 x + 32 \right) } } { 8 }
D) y=5x±25x2+16(x2+3x32) 8y = \frac { - 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }
E) y=5x±25x2+16(x2+3x32) 8y = \frac { 5 x \pm \sqrt { 25 x ^ { 2 } + 16 \left( x ^ { 2 } + 3 x - 32 \right) } } { 8 }

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